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16 tháng 7 2016
a) \(=\left(\frac{-337}{100}:\frac{40}{100}\right).\frac{250}{100}=\frac{-337}{40}.\frac{40}{16}=-\frac{337}{16}\)
b) \(=\frac{-1}{8}.\left(-5,3\right).8=\frac{-1}{8}.8.\left(-5,3\right)=-1.\left(-5,3\right)=5,3\)
c) \(=10.\left(-7,9\right)=-79\)
d) \(=-\frac{3}{8}.\frac{13}{3}.\left(-8\right)=\left[-\frac{3}{8}.\left(-8\right)\right].\frac{13}{3}=3.\frac{13}{3}=13\)
NN
16 tháng 7 2016
a)(-3,37:0,4).2,5
=(-8,425).2,5
=-21,0625
b) (-0,125) . (-5,3) . 8
=(-0,125).8.(-5,3)
=(-1).(-5,3)
=5,3
c)(-2,5).(-4).(-7,9)
=10.(-7,9)
=-79
d)(-0,375).\(4\frac{1}{3}\).(-2)3
=(-0,375).(-2)3.\(4\frac{1}{3}\)
=3.\(\frac{13}{3}\)
=13
H9
HT.Phong (9A5)
CTVHS
3 tháng 10 2023
Bài 1:
a) \(6,125\approx6,13\)
b) \(21,333\approx21,33\)
c) \(5,666\approx5,67\)
d) \(5,346\approx5,35\)
e) \(2,\left(321\right)=2,321321...\approx2,32\)
f) \(-4,63\left(3\right)=-4.6333...\approx-4,63\)
g) \(\dfrac{3}{7}=0,\left(428571\right)\approx0,43\)
Bài 2:
a) \(\sqrt{2}\approx1,414\)
b) \(\sqrt{2}\approx1,41\)
c) \(\sqrt{2}\approx1,4\)
3 tháng 10 2023
Bài 1 :
a) \(6,125\sim6,1\)
b) \(21,333\sim21,3\)
c) \(5,666\sim5,7\)
d) \(5,346\sim5,3\)
e) \(2,\left(312\right)\sim2,3\)
f) \(-4,63\left(3\right)=-4,6\)
g) \(\dfrac{3}{7}\sim0,429\sim0,4\)
7 tháng 10 2021
\(=\left(-13,37+3,37\right)+\left(-24,58-5,42\right)\\ =-10-30=-40\)
27 tháng 1 2016
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24 tháng 8 2023
5: \(=3-\dfrac{1}{4}+\dfrac{2}{3}-5+\dfrac{1}{3}+\dfrac{6}{5}-6+\dfrac{7}{4}-\dfrac{3}{2}\)
\(=3-5-6+\dfrac{-1}{4}+\dfrac{7}{4}+\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{6}{5}-\dfrac{3}{2}\)
\(=-8+\dfrac{3}{2}+1+\dfrac{-3}{10}\)
\(=-7+\dfrac{15-3}{10}=-7+\dfrac{6}{5}=-\dfrac{29}{5}\)
6: \(=6-\dfrac{2}{3}+\dfrac{1}{2}-5-\dfrac{5}{3}+\dfrac{3}{2}-3+\dfrac{7}{3}-\dfrac{5}{2}\)
\(=6-5-3-\dfrac{2}{3}-\dfrac{5}{3}+\dfrac{7}{3}+\dfrac{1}{2}+\dfrac{3}{2}-\dfrac{5}{2}\)
\(=-2-\dfrac{1}{2}=-\dfrac{5}{2}\)
7: \(=\dfrac{5}{3}-\dfrac{3}{7}+9-2-\dfrac{5}{7}+\dfrac{2}{3}+\dfrac{8}{7}-\dfrac{4}{3}-10\)
\(=9-2-10+\dfrac{5}{3}+\dfrac{2}{3}-\dfrac{4}{3}+\dfrac{-3}{7}-\dfrac{5}{7}+\dfrac{8}{7}\)
=-3+1
=-2
8: \(=8-\dfrac{9}{4}+\dfrac{2}{7}+6+\dfrac{3}{7}-\dfrac{5}{4}-3-\dfrac{2}{4}+\dfrac{9}{7}\)
\(=8+6-3+\dfrac{2}{7}+\dfrac{3}{7}+\dfrac{9}{7}-1-\dfrac{2}{4}\)
\(=11+2-1-\dfrac{1}{2}\)
=11+1/2
=11,5
5 tháng 7 2023
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
13 tháng 7 2023
Sửa đề: 3^5+3^5+3^5; 2^x
=>\(2^x=\dfrac{4^5\cdot4}{3^5\cdot3}\cdot\dfrac{6^5\cdot6}{2^5\cdot2}\)
=>\(2^x=\left(\dfrac{4}{3}\right)^6\cdot\left(\dfrac{6}{2}\right)^6=4^6=2^{12}\)
=>x=12
