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45-(5-2x)^2=4375
-(5-2x)^2=45-4375
-(10-4x)=-4330
-10+4x=-4330
4x=-4330+10
4x=-4320
x=-1080
\(A=111-109+107-105+...+7-5+3-1\)
\(A=\left(111-109\right)+\left(107-105\right)+...+\left(7-5\right)+\left(3-1\right)\)
\(A=2+2+...+2+2\) ( có 28 số 2)
\(A=2.28=56\)
Vậy \(A=56\)
A = 111 - 109 + 107 - 105 + ... + 7 - 5 + 3 - 1
A= ( 111 - 109 ) + (107 -105 ) + ... + ( 7 - 5 ) +( 3 - 1 )
A= 2 + 2 + 2 + ... + 2 + 2
A=2 . 28
A= 56
\(2x=\frac{1}{5}+\left(-\frac{3}{7}\right)\)
\(\Rightarrow2x=\frac{7}{35}+\left(-\frac{15}{35}\right)\)
\(\Rightarrow2x=-\frac{8}{35}\)
\(\Rightarrow x=\frac{-\frac{8}{35}}{2}=-\frac{4}{35}\)
a, Cách 1: 15. 12 - 3.5.10
= 180 - 150
= 30
Cách 2 : 15 . 12 - 3 . 5 . 10
= 15 . 12 - (3.5) .10
= 15 . 12 - 15 . 10
= 15.( 12 -10)
= 15 . 2
= 30
b, Cách 1: 45 - 9 . (13 + 5)
= 45 - 9 . 18
= 45 - 162
= xem lại đề bài
c, Cách 1: 29 . (19 - 13) - 19. (29 - 13)
= 29 . 6 - 19 . 16
= 174 - 304
= Xem lại đề bài.
\(|2x-4|-3\left(x-5\right)+1=\) \(0\)\
<=> \(|2x-4|-3x+15+1=0\)
<=> \(|2x-4|=3x-16\)
<=> \(\orbr{\begin{cases}2x-4=3x-16\\2x-4=-3x+16\end{cases}}\)
<=> \(\orbr{\begin{cases}x=12\\x=4\end{cases}}\)
vậy \(x=12\left(h\right)x=4\)
chúc bn học tốt
\(|2x+4|-3\left(x-5\right)+1=0\)\(\Rightarrow|2x+4|-3x+3.5+1=0\)
\(\Rightarrow|2x+4|-3x+15+1=0\)\(\Leftrightarrow|2x+4|-3x+16=0\)
\(\Rightarrow|2x+4|=3x-16\Leftrightarrow\orbr{\begin{cases}2x+4=3x-16\\2x+4=-3x+16\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x-3x=4-16\\2x-\left(-3x\right)=4+16\end{cases}}\Leftrightarrow\orbr{\begin{cases}-x=-12\Leftrightarrow x=12\\5x=20\Rightarrow x=4\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=12\\x=4\end{cases}}\)
\(x.\left(2+8\right)=125-25\)
\(x.10=100\)
\(x=100:10\)
\(x=10\)
Vậy x=10
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
a)\(x-15\%x=\frac{1}{3}\)
\(x.\left(1-15\%\right)=\frac{1}{3}\)
\(x.\frac{-280}{3}=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{-280}{3}\)
\(x=\frac{-1}{280}\)
Vậy \(x=\frac{-1}{280}\)
b)\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{6}{5}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{17}{10}x+\frac{6}{5}=\frac{-5}{6}\)
\(-\frac{17}{10}x=-\frac{5}{6}-\frac{6}{5}\)
\(-\frac{17}{10}x=\frac{-61}{30}\)
\(x=\frac{-61}{30}:\frac{-17}{10}\)
\(x=\frac{61}{51}\)
Vậy \(x=\frac{61}{51}\)
-45:5.(-3-2x)=3
-9.(-3-2x)=3
-3-2x=3:(-9)
-3-2x=\(-\frac{1}{3}\)
2x=-3-(\(-\frac{1}{3}\))
2x=\(-\frac{8}{3}\)
x=\(-\frac{8}{3}\):2
x=\(-\frac{4}{3}\)
vậy..
-45 : 5 x (-3 - 2x) = 3
-45 : (-15) - 10x = 3
3 - 10x = 3
10x = 3 - 3
10x = 0
x = 0
Vậy x = 0