Câu hỏi của ᴵᴬᴹκᴀмᴀᴅo❣тᴀɴנιʀo✦ (ɻɛ𝖆ɱ 𝖆 ħιħι)

Question

[3(x-y)4 + 2(x-y)3 - 5(x-y)2] : (y-x)2

Lm đi các bro

Trương Nhật Minh · Accepted Answer

Rút gọn:

$\dfrac{3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2}{\left(y-x\right)^2}$

$=\dfrac{3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2}{\left(x-y\right)^2}$

$=\dfrac{3\left(x-y\right)^4}{\left(x-y\right)^2}+\dfrac{2\left(x-y\right)^3}{\left(x-y\right)^2}-\dfrac{5\left(x-y\right)^2}{\left(x-y\right)^2}$

$=3\left(x-y\right)^2+2\left(x-y\right)-5$

Câu trả lời: Rút gọn:

$\dfrac{3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2}{\left(y-x\right)^2}$

$=\dfrac{3\left(x-y\right)^4+2\left(x-y\right)^3-5\left(x-y\right)^2}{\left(x-y\right)^2}$

$=\dfrac{3\left(x-y\right)^4}{\left(x-y\right)^2}+\dfrac{2\left(x-y\right)^3}{\left(x-y\right)^2}-\dfrac{5\left(x-y\right)^2}{\left(x-y\right)^2}$

$=3\left(x-y\right)^2+2\left(x-y\right)-5$