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a: \(\Leftrightarrow2x-2+4x+8=-12\)
=>6x+6=-12
=>6x=-18
hay x=-3
b: \(\Leftrightarrow-10x-15-12+9x=13\)
=>-x-27=13
=>-x=40
hay x=-40
c: \(\Leftrightarrow-10x+70+20-5x=-15\)
\(\Leftrightarrow-15x=-105\)
hay x=7
d: \(\Leftrightarrow8x-12-7x+14=10\)
=>x+2=10
hay x=8
e: \(\Leftrightarrow-12x-18+14x+2=2\)
=>2x-16=2
hay x=9
a) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
Câu tiếp theo làm tương tự nhé =))
) [ 3x-1] + 4x - 3 = 7
3x - 1 + 4x = 7 + 3 = 10
( 3 + 4 )x - 1 =10
7x - 1 = 10
7x=11
x=11/7
a, 1+x-10-6x=4-5x
<=> -5x-9=4-5x
<=>0x=13(vô lý)
vậy phương trình vô nghiệm
b, 6-3x+1=-3x+7
-3x+3x=7-7
<=>0x=0(luôn đúng)
vậy phương trình có vô số nghiệm
a) Nếu \(\frac{1}{2}x\ge0\Rightarrow x\ge0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow\frac{1}{2}x=3-2x\Rightarrow\frac{5}{2}x=3\Rightarrow x=\frac{6}{5}\) (nhận)
Nếu \(\frac{1}{2}x< 0\Rightarrow x< 0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow-\frac{1}{2}x=3-2x\Rightarrow\frac{3}{2}x=3\Rightarrow x=2\) (loại)
Vậy x = 6/5
b) Nếu \(x-1\ge0\Rightarrow x\ge1\) thì \(\left|x-1\right|=3x+2\Rightarrow x-1=3x+2\Rightarrow-2x=3\Rightarrow x=\frac{-2}{3}\) (loại)
Nếu \(x-1< 0\Rightarrow x< 1\) thì \(\left|x-1\right|=3x+2\Rightarrow-\left(x-1\right)=3x+2\Rightarrow-x+1=3x+2\Rightarrow-4x=1\Rightarrow x=\frac{-1}{4}\) (nhận)
Vậy x = -1/4
a) \(\frac{3}{2}-\left(x-\frac{7}{3}\right)=\left|-\frac{3}{4}-\frac{9}{8}\right|\)
=> \(\frac{3}{2}-x+\frac{7}{3}=\left|-\frac{15}{8}\right|\)
=> \(\frac{3}{2}-x+\frac{7}{3}=\frac{15}{8}\)
=> \(\frac{3}{2}-x=-\frac{11}{24}\)
=> \(x=\frac{47}{24}\)
b) \(\frac{5}{2}-\left(\frac{3}{2}-\frac{7}{3}+x\right)=\frac{8}{15}-\left(\frac{1}{4}-\frac{7}{10}\right)\)
=> \(\frac{5}{2}-\frac{3}{2}+\frac{7}{3}-x=\frac{8}{15}-\left(-\frac{9}{20}\right)\)
=> \(\frac{10}{3}-x=\frac{59}{60}\)
=> \(x=\frac{10}{3}-\frac{59}{60}=\frac{47}{20}\)
c) \(2\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
=> \(\frac{3}{2}-10x-\frac{4}{5}+3x=0\)
=> \(\left(\frac{3}{2}-\frac{4}{5}\right)+\left(-10x+3x\right)=0\)
=> \(\frac{7}{10}-7x=0\)
=> \(7x=\frac{7}{10}\)
=> x = 1/10
`#040911`
`a)`
`3 1/3 x + 16 3/4 = -13,25`
`=> 3 1/3 x = -13,25 - 16 3/4`
`=> 3 1/3 x = -30`
`=> x = -30 \div 3 1/3`
`=> x =-9`
Vậy, `x = -9`
`b)`
`3 2/7*x - 1/8 = 2 3/4`
`=> 3 2/7x = 2 3/4 + 1/8`
`=> 3 2/7x = 23/8`
`=> x = 23/8 \div 3 2/7`
`=> x = 7/8`
Vậy, `x = 7/8`
`c)`
`x \div 4 1/3 = -2,5`
`=> x = -2,5 * 4 1/3`
`=> x = -65/6`
Vậy, `x = -65/6`
`d)`
`( (3x)/7 + 1) \div (-4) = (-1)/28`
`=> (3x)/7 +1 = (-1)/28 * (-4)`
`=> (3x)/7 + 1 = 1/7`
`=> (3x)/7 = 1/7 - 1`
`=> (3x)/7 = -6/7`
`=> 3x = -6`
`=> x = -6 \div 3`
`=> x = -2`
Vậy, `x = -2.`
a
=>10/3 . x + 16 + 3/4 = -13,25
=>10/3 x + 3/4 = -29,25
=>10/3 x = -30
=>x=-30 : 10/3
=>x=-30 . 3/10
=>x=-9
b.
=>23/7 x - 1/8 = = 11/4
=>23/7 x = 11/4 + 1/8
=>23/7 x= 22/8 + 1/8
=>23/7 x= 23/8
=>x=23/8 : 23/7
=>x=23/8 . 7/23
=>x=7/8
c.
=>x : 13/3 =-5/2
=>x=-5/2 . 13/3
=>x=-65/6
d.
=>3x/7 +1 = (-1/28) . (-4)
=>3x/7 + 1 = 1/7
=>3x/7 = -6/7
=>3x=-6
=>x=-2
a) 2(x - 5) - 3(x + 7) = 14
<=> 2x - 10 - 3x - 21 = 14
<=> 2x - 3x = 14 + 10 + 21
<=> x = -45
Vậy x = -45
b) 5(x - 6) - 2(x + 3) = 12
<=> 5x - 30 - 2x - 6 = 12
<=> 5x - 2x = 12 + 30 + 6
<=> 3x = 48
<=> x = 16
Vậy x = 16
c) 3(x - 4) - (8 - x) = 12
<=> 3x - 12 - 8 + x = 12
<=> 3x + x = 12 + 12 + 8
<=> 4x = 32
<=> x = 8
Vậy x = 8
d) -7(3x - 5) + (7x - 14) = 28
<=> -21x + 35 + 7x - 14 = 28
<=> -21x + 7x = 28 - 35 + 14
<=> -14x = 7
<=> x = -1/2
Vậy x = -1/2
\(a,2\left(x-5\right)-3\left(x+7\right)=14\)
\(\Leftrightarrow2x-10-3x-21=14\)
\(\Leftrightarrow-x=45\)
\(\Leftrightarrow x=-45\)
\(b,5\left(x-6\right)-2\left(x+3\right)=12\)
\(\Leftrightarrow5x-30-2x-6=12\)
\(\Leftrightarrow3x=48\)
\(\Leftrightarrow x=16\)
\(c,3\left(x-4\right)-\left(8-x\right)=12\)
\(\Leftrightarrow3x-12-8+x=12\)
\(\Leftrightarrow4x=32\)
\(\Leftrightarrow x=8\)
\(d,-7\left(3x-5\right)+2\left(7x-14\right)=28\)
\(\Leftrightarrow-21x+35+14x-28=28\)
\(\Leftrightarrow-7x=21\)
\(\Leftrightarrow x=-3\)
|3x-2| = |(-7)+3|
|3x-2| = | -4|
|3x-2| = 4
TH1: 3x-2 = 4
3x =4+2
3x =6
x= 6:3
x= 2
TH2: 3x-2= -4
3x= -4+2
3x= -2
x= -2 :3
x= -2/3
Vậy...
Hk biết có j sai hk nữa
\(x=-2\)