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A = \(\frac{40}{31\cdot39}+\frac{35}{39\cdot46}+\frac{30}{46\cdot52}+\frac{25}{52\cdot57}\)
A= \(5.\left(\frac{8}{31\cdot39}+\frac{7}{39\cdot46}+\frac{6}{46\cdot52}+\frac{5}{52\cdot57}\right)\)
A= \(5\cdot\left(\frac{1}{31}-\frac{1}{39}+\frac{1}{39}-\frac{1}{46}+\frac{1}{46}-\frac{1}{52}+\frac{1}{52}-\frac{1}{57}\right)\)
A= \(5.\left(\frac{1}{31}-\frac{1}{57}\right)\)
A= \(5.\left(\frac{26}{1767}\right)\)
A = \(\frac{130}{1767}\)
ta có 50^40>50^39
50^39>50^38=)1/50^39<1/50^38
=)50^40+1/50^39>50^39+1/50^38
=)50^40+1/50^39+1>50^39+1/50^38+1
=)A>B
\(\frac{-7}{25}\times\frac{39}{-14}\times\frac{50}{78}\)
\(=\frac{39}{50}\times\frac{50}{78}\)
\(=\frac{1}{2}\)
\(\frac{-7}{25}\)x \(\frac{39}{-14}\)x \(\frac{50}{78}\)
= \(\frac{-7}{25}\)x \(\frac{-14}{39}\)x \(\frac{25}{39}\)
=\(\frac{-7}{25}\)x\(\frac{25}{39}\)x \(\frac{-14}{39}\)
=\(\frac{-7}{39}\)x \(\frac{-14}{39}\)
=\(\frac{98}{1521}\)
chúc bạn học tốt !!!
\(\frac{-7}{25}\)x \(\frac{39}{-14}\)x\(\frac{50}{78}\)=\(\frac{\left(-7\right)x39x5x10}{5x5x\left(-7\right)x2x39x2}\)=\(\frac{10}{20}\)=\(\frac{1}{2}\)
a. 15-(15+x)=21
=> 15-15-x=21
=> 0-x=21
=> -x=21
=> x=-21
b. 39+(x-39)=50
=> 39+x-39=50
=> x=50
a) \(25-\left(25-x\right)=12+\left(42-65\right)\)
\(25-\left(25-x\right)=12+\left(-23\right)\)
\(25-\left(25-x\right)=-11\)
\(25-x=25-\left(-11\right)\)
\(25-x=36\)
\(x=25-36\)
\(x=-11\)
Làm 2 câu dài cho bạn nhá! Mấy câu ngắn tương tự!
a, \(25-\left(25-x\right)=12+\left(42-65\right)\)
\(\Rightarrow25-25+x=12+42-65\)
\(\Rightarrow x=-11\)
b, \(215+\left(-38\right)-54+90-\left(-48+x\right)=0\)
\(\Rightarrow215-38-54+90+48-x=0\)
\(\Rightarrow x=261\)
m, \(\left|x\right|-5=12\)
\(\Rightarrow\left|x\right|=17\Rightarrow\left\{{}\begin{matrix}x=-17\\x=17\end{matrix}\right.\)
Chúc bạn học tốt!!!
39.( 25 - 50 ) - 50.(39 - 39 )
= 39 .25 - 39 . 50 - 50 . 39 - 50 . 39
= ( 39.25 - 50.39 ) - ( 39 . 50 - 50 . 39 )
= 25 . ( 39 - 78 ) - 0
= 25 . ( - 39 )
= - 975
39.(25-50)-50.(39-39)
=[39 . (-25)] - 0
=-975