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325.(37+45)-63.(-325)+45.(-225)
=325.37+325.45+63.325+45.(-225)
=325.(37+63)+45.(325-225)
=325.100+45.100
=100.(325+45)
=100.370
=37000
mình chắc là nó đúng
a, |-37| + (-|15|) = 37 - 15 = 12
b, (-|-32|) +|5| = -32 + 5 = -27
c, (-|-22|) + (-|16|) = -22 - 16 = -38
d, (-23) + 13 + (-17) + 57 = 30
e, 14 + 6 + (-9) + (-14) = -3
g, (-123) +|-13| + (-7) = -123 + 13 + (-7) = -117
h, |0| + |45| + (-|-455|) + |-796| = 0 + 45 - 455 + 796 = 386
a. C1: 15 . 12 - 3.5.10
= 15 . 12 - 15 . 10
= 15.(12 - 10)
= 15 . 2
= 30
C2: 15.12 - 3.5.10
= 15.2.6 - 3.5.2.5
= 30.6 - 30.5
= 30.(6 - 5)
= 30.1
= 30
b. C1: 45 - 9.(13 + 5)
= 45 - 9.13 - 9.5
= 45 - 117 - 45
= -117
C2: 45 - 9.(13 + 5)
= 45 - 9.18
= 45 - 162
= -117
c. C1: 29.(19 - 13) - 19.(29 - 13)
= 29.19 - 29.13 - 19.29 + 19.13
= (29.19 - 19.29) + 19.13 - 29.13
= 0 + 13.(19 - 29)
= 13.(-10)
= -130
C2: 29.(19 - 13) - 19.(29 - 13)
= 29.6 - 19.16
= 174 - 304
= -130
a)cách 1:
15.12-3.5.10
=180-15.10
=180-150
=30
cách 2:
15.12-3.5.10
=15.12-15.10
=15.(12-10)
=15.2
=30
b)45-9.(13+5)
=45-9.18
=45-162
=-117
45-9.(13+5)
=45-9.13+9.5
=45-9.13+45
=(45-45)-9.13
=0-117
=-117
c)29.(19-13)-19.(29-13)
=29.19-29.13-19.29-19.13
=(29.19-19.29)+(19.13-29.13)
=0+13.(19-29)
=0+13.(-10)
=-130
29.(19-13)-19.(29-13)
=29.6-19.16
=174-304
=-130
tick nha bn mk bị âm điểm
a) 15 + 4.12 - 3²
=15 + 48 - 9
= 63 - 9
= 54
b) {[(37 + 13) : 5].2 - 45 : 5}.7 - 2022⁰
= [(50 : 5).2 - 9].7 - 1
= (10.2 - 9).7 - 1
= (20 - 9).7 - 1
= 11.7 - 1
= 77 - 1
= 76
\(15+4.12-3^2=15+48-9=63-9=54\\ ---\\ \left\{\left[\left(37+13\right):5\right]-45:5\right\}.7-2022^0=\left\{\left[50:5\right]-9\right\}.7-1\\ =\left\{10-9\right\}.7-1\\ =1.7-1=6\)
a) \(\dfrac{7}{30}+\dfrac{\left(-12\right)}{37}+\dfrac{23}{30}+\dfrac{\left(-25\right)}{37}=\left(\dfrac{7}{30}+\dfrac{23}{30}\right)+\left(\dfrac{-12}{37}+\dfrac{-25}{37}\right)=1+\left(-1\right)=0\)
b) \(\dfrac{5}{7}\cdot\dfrac{5}{11}+\dfrac{5}{7}\cdot\dfrac{2}{11}-\dfrac{5}{7}\cdot\dfrac{14}{11}=\dfrac{5}{7}\cdot\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\left(-\dfrac{7}{11}\right)=-\dfrac{5}{11}\)
c) \(\dfrac{\left(-5\right)}{7}\cdot\dfrac{3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+1\dfrac{5}{7}=\dfrac{5}{7}\cdot\dfrac{-3}{13}-\dfrac{5}{7}\cdot\dfrac{10}{13}+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(\dfrac{-3}{13}-\dfrac{10}{13}\right)+\dfrac{12}{7}=\dfrac{5}{7}\cdot\left(-1\right)+\dfrac{12}{7}=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=\dfrac{7}{7}=1\)
{50:5-45:5}x7
={10-9}x7
=1x7
=7
d,
=6^2x10:{780:[1000-15,625+35x14]}
=6^2x10:{780:[1000-15,625+490]}
=6^2x10:{780:1474,375}
=6^2x10:0,52903772785
=36x10:0,52903772785
=360:0,52903772785
=608,480769232
khum bt câu d, làm đúng chưa?
chắc sai á
{[(37+13):5]-45:5}.7
={[50:5]-9}.7
={10-9}.7
=1.7
=7