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6 tháng 6 2022

`3/2-5+1/10=15/10-50/10+1/10=[15-50+1]/10=[-34]/10=-17/5`

10 tháng 7 2016

Viết đổi 10/10 cuối vô duyên quá! và dấu của các phân số có mẫu 10 phải là -.

Sửa đi, Linh làm cho.

26 tháng 10 2021

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19 tháng 12 2016

\(a,3456731-19994=3436737\)

\(b,3\times31\times16+2\times24\times42+4\times27\times12\)

\(=\left(3\times16\right)\times31+\left(2\times24\right)\times42+\left(4\times12\right)\times27\)

\(=48\times31+48\times42+48\times27\)

\(=48\times\left(31+42+27\right)\)

\(=48\times100\)

\(=4800\)

\(c,\left(3^{10}+3^{12}\right):3^{10}\)

\(=3^{10}:3^{10}+3^{12}:3^{10}\)

\(=1+3^2\)

\(=1+9\)

\(=10\)

\(d,\left(2^{13}-3.2^{10}\right):2^{10}+\left(5^{10}-5^9\right):5^9\)

\(=2^{13}:2^{10}-3.2^{10}:2^{10}+5^{10}:5^9-5^9:5^9\)

\(=2^3-3+5-1\)

\(=8-3+5-1\)

\(=9\)

25 tháng 6 2018

\(1,\\ x+\dfrac{1}{2}=-\dfrac{5}{3}\\ x=-\dfrac{5}{3}-\dfrac{1}{2}\\ x=-\dfrac{13}{6}\\ Vậyx=-\dfrac{13}{6}\)

\(2,\\ \dfrac{1}{3}-x=\dfrac{3}{5}\\ x=\dfrac{1}{3}-\dfrac{3}{5}\\ x=-\dfrac{4}{15}\\ Vậyx=-\dfrac{4}{15}\)

\(3,\\ 3-4+x=\dfrac{7}{2}\\ -1+x=\dfrac{7}{2}\\ x=\dfrac{7}{2}+1\\ x=\dfrac{9}{2}\\ Vậyx=\dfrac{9}{2}\)

\(4,\\ x-\dfrac{4}{3}=-\dfrac{7}{9}\\ x=-\dfrac{7}{9}+\dfrac{4}{3}\\ x=\dfrac{15}{27}\\ Vậyx=\dfrac{15}{27}\)

\(5,\\ x-\left(-\dfrac{7}{3}\right)=\dfrac{5}{6}\\ x=\dfrac{5}{6}-\dfrac{7}{3}\\ x=-\dfrac{27}{18}\\ Vậyx=-\dfrac{27}{18}\)

\(6,\\ x-\dfrac{1}{5}=\dfrac{9}{10}\\ x=\dfrac{9}{10}+\dfrac{1}{5}\\ x=\dfrac{11}{10}\\ Vậyx=\dfrac{11}{10}\)

\(7,\\ x+\dfrac{5}{12}=\dfrac{3}{8}\\ x=\dfrac{3}{8}-\dfrac{5}{12}\\ x=-\dfrac{1}{24}\\ Vậyx=-\dfrac{1}{24}\)

\(8,\\ x+\dfrac{5}{4}=\dfrac{7}{6}\\ x=\dfrac{7}{6}-\dfrac{5}{4}\\ x=-\dfrac{9}{24}\\ Vậyx=-\dfrac{9}{24}\)

\(9,\\ x-\dfrac{2}{7}=\dfrac{1}{35}\\ x=\dfrac{1}{35}+\dfrac{2}{7}\\ x=\dfrac{11}{35}\\ Vậyx=\dfrac{11}{35}\\ 10,\\ x-\dfrac{1}{5}=-\dfrac{7}{10}\\ x=-\dfrac{7}{10}+\dfrac{1}{5}\\ x=-\dfrac{1}{2}\\ Vậyx=-\dfrac{1}{2}\)

18 tháng 2 2021

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11 tháng 4 2021

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6 tháng 6 2015

a/A=1+2+4+8+...+1024

2A=2+4+8+16+....+2048

2A-A=(2+4+8+16+....+2048)-(1+2+4+8+...+1024)

A=2048-1

A=2047

VẬY A=2047

b/B=1+5+25+125+....+15625

5B=5+25+125+625+....+78125

5B-B=(5+25+125+625+....+78125)-(1+5+25+125+....+15625)

4B=78125-1

4B=78124

B=78124:4

B=19531

VẬY B =19531

C=1/1.2+1/2.3+1/3.4+...+1/2015.2016

C=1-1/2+1/2-1/3+1/3-1/4+...+1/2015-1/2016

=1-1/2016

=2015/2016

VẬY C=2015/2016

D/=10/1.3+10/3.5+10/5.7+....+10/2013.2015

=5(2/1.3+2/3.5+2/5.7+...+2/2013.2015)

=5(1-1/3+1/3-1/5+1/5-1/7+..+1/2013-1/2015)

=5(1-1/2015)

=5.2014/2015

=2014/403

VẬY D=2014/403

 

6 tháng 6 2015

a, A = 1 + 2 + 4 + 8 +...+ 1024

   \(A=1+2+2^2+2^3+....+2^{10}\)

   \(2A=2+2^2+2^3+....+2^{10}+2^{11}\)

   \(A=1+2+2^2+2^3+....+2^{10}\)

  \(A=2^{11}-1=2047\)

b, B = 1 + 5 + 25 + 125 + ... + 15625

   \(B=1+5+5^2+5^3+....+5^6\)

   \(3B=5+5^2+5^3+....+5^6+5^7\)

   \(B=1+5+5^2+5^3+....+5^6\)

  \(2B=5^7-1\Rightarrow B=\frac{5^7-1}{2}=39062\)

d, D = 10 / 1 . 3 + 10 / 3 . 5 + 10 / 5 . 7 + ... + 10 / 2013 . 2015

\(D=\frac{10}{2}.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{2013.2015}\right)\)

\(D=\frac{10}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{2013}-\frac{1}{2015}\right)\)

\(D=\frac{10}{2}.\left(1-\frac{1}{2015}\right)=5.\frac{2014}{2015}=\frac{2014}{403}\)

Câu c thì tương tự

27 tháng 6 2018

1/ \(x+\dfrac{1}{2}=\dfrac{-5}{3}\)

\(x=\dfrac{-5}{3}-\dfrac{1}{2}\)

\(x=\dfrac{-10}{6}-\dfrac{3}{6}\)

Vậy \(x=\dfrac{-13}{6}\)

2/\(\dfrac{1}{3}-x=\dfrac{3}{5}\)

\(-x=\dfrac{3}{5}-\dfrac{1}{3}\)

\(-x=\dfrac{9}{15}-\dfrac{5}{15}\)

\(-x=\dfrac{4}{15}\)

Vậy \(x=\dfrac{-4}{15}\)

3/ \(3-4+x=\dfrac{7}{2}\)

\(-4+x=\dfrac{7}{2}-3\)

\(-4+x=\dfrac{7}{2}-\dfrac{6}{2}\)

\(-4+x=\dfrac{1}{2}\)

\(x=\dfrac{1}{2}+4\)

\(x=\dfrac{1}{2}+\dfrac{8}{2}\)

Vậy \(x=\dfrac{9}{2}\)

4/ \(x-\dfrac{4}{3}=\dfrac{-7}{9}\)

\(x=\dfrac{-7}{9}+\dfrac{4}{3}\)

\(x=\dfrac{-7}{9}+\dfrac{12}{9}\)

Vậy \(x=\dfrac{5}{9}\)

5/ \(x-\dfrac{-7}{2}=\dfrac{5}{6}\)

\(x=\dfrac{5}{6}-\dfrac{7}{2}\)

\(x=\dfrac{5}{6}-\dfrac{21}{6}\)

Vậy \(x=\dfrac{-16}{6}=\dfrac{-8}{3}\)

6/ \(x-\dfrac{1}{5}=\dfrac{9}{10}\)

\(x=\dfrac{9}{10}+\dfrac{1}{5}\)

\(x=\dfrac{9}{10}+\dfrac{2}{10}\)

Vậy \(x=\dfrac{11}{10}\)

7/ \(x+\dfrac{5}{12}=\dfrac{3}{8}\)

\(x=\dfrac{3}{8}-\dfrac{5}{12}\)

\(x=\dfrac{9}{24}-\dfrac{10}{24}\)

Vậy \(x=\dfrac{-1}{24}\)

8/ \(x+\dfrac{5}{4}=\dfrac{7}{6}\)

\(x=\dfrac{7}{6}-\dfrac{5}{4}\)

\(x=\dfrac{14}{12}-\dfrac{15}{12}\)

Vậy \(x=\dfrac{-1}{12}\)

9/ \(x-\dfrac{2}{7}=\dfrac{1}{35}\)

\(x=\dfrac{1}{35}+\dfrac{2}{7}\)

\(x=\dfrac{1}{35}+\dfrac{10}{35}\)

Vậy \(x=\dfrac{11}{35}\)

10 /\(x-\dfrac{1}{5}=\dfrac{-7}{10}\)

\(x=\dfrac{-7}{10}+\dfrac{1}{5}\)

\(x=\dfrac{-7}{10}+\dfrac{2}{10}\)

Vậy \(x=\dfrac{-5}{10}=\dfrac{-1}{2}\)

7 tháng 3 2020

a) \(\frac{-2}{3}x+\frac{1}{5}=\frac{1}{10}\)

\(\Leftrightarrow\frac{-2}{3}x=\frac{1}{10}-\frac{1}{5}\)

\(\Leftrightarrow\frac{-2}{3}x=\frac{-1}{10}\)

\(\Leftrightarrow x=\frac{-1}{10}\div\frac{-2}{3}\)

\(\Leftrightarrow x=\frac{3}{20}\)

26 tháng 2 2022

ko có tên à

26 tháng 3 2019

\(x\div4\frac{1}{3}=-2,5\)

\(\Leftrightarrow x\div\frac{13}{3}=\frac{-5}{2}\)

\(\Leftrightarrow x=\frac{-5}{2}.\frac{13}{3}\)

\(\Leftrightarrow x=\frac{-65}{6}\)

\(x\div\frac{-3}{5}=\frac{-10}{21}\)

\(\Leftrightarrow x=\frac{-10}{21}.\frac{-3}{5}\)

\(\Leftrightarrow x=\frac{30}{105}\)

\(\Leftrightarrow x=\frac{2}{7}\)

26 tháng 3 2019

\(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\)

\(\Leftrightarrow\frac{2}{3}x=\frac{1}{10}+\frac{1}{2}\)

\(\Leftrightarrow\frac{2}{3}x=\frac{6}{10}\)

\(\Leftrightarrow x=\frac{6}{10}\div\frac{2}{3}\)

\(\Leftrightarrow x=\frac{18}{20}\)

\(\Leftrightarrow x=\frac{9}{10}\)

\(\frac{1}{2}x+\frac{1}{2}=\frac{5}{2}\)

\(\Leftrightarrow\frac{1}{2}\left(x+1\right)=\frac{5}{2}\)

\(\Leftrightarrow\left(x+1\right)=\frac{5}{2}\div\frac{1}{2}\)

\(\Leftrightarrow\left(x+1\right)=5\)

\(\Leftrightarrow x=5-1\)

\(\Leftrightarrow x=4\)