Question

[Trần Phương Uyên]

3¹³⁵ + 2¹³⁵ + 3¹³³ + 2¹³⁴

Answer 1

[HT.Phong (9A5)]

\(3^{135}+2^{135}+3^{133}+2^{134}\)

\(=\left(3^{135}+3^{133}\right)+\left(2^{135}+2^{134}\right)\)

\(=3^{133}\cdot\left(3^2+1\right)+2^{133}\cdot\left(4+1\right)\)

\(=3^{133}\cdot10+2^{133}\cdot5\)

\(=5\cdot2\cdot\left(3^{133}+2^{132}\right)\)

\(=10\cdot\left(3^{133}+2^{132}\right)\)