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a, => 12. ( x - 1 ) = 35 . 3
=> 12. ( x - 1 ) = 105
=> x - 1 = 105 : 12
=> x - 1 = 8,75
=> x = 8,75 + 1
=> x = 9,75
\(a,12.\left(x-1\right):3=35\)
\(12.\left(x-1\right)=35.3\)
\(12.\left(x-1\right)=105\)
\(x-1=105:12\)
\(x-1=\frac{35}{4}\)
\(x=\frac{35}{4}+1\)
\(x=\frac{39}{4}\)
\(b,2.x-138=72\)
\(2.x=72+138\)
\(2.x=210\)
\(x=210:2\)
\(=105\)
\(c,310-\left(118-x\right)=217\)
\(118-x=310-217\)
\(118-x=93\)
\(x=118-93\)
\(x=25\)
Học tốt
a) (x-35)-120=0
x-35= 120
➩x = 155
b)310-(118-x)=217
118 -x = 93
➩ x = 25
c)156-(x+61)=82
➩ x + 61 = 74
➩ x = 13
a: Ta có: \(x-35-120=0\)
\(\Leftrightarrow x-155=0\)
hay x=155
b: Ta có: \(310-\left(118-x\right)=217\)
\(\Leftrightarrow118-x=93\)
hay x=25
c: Ta có: \(156-\left(x+61\right)=82\)
\(\Leftrightarrow x+61=74\)
hay x=13
a) 310-(118-x)=217
118-x=310-217
118-x=93
x=118-93
x=25
b) 814-(x-305)=712
x-305=814-712
x-305=102
x =102+305
x = 407
c)5(x+35)=515
x+35 =515:5
x+35 =103
x =103-35
x =68
\(a,310-\left(118-x\right)=217\) \(c,5\left(x+35\right)=515\)
\(118-x=310-217\) \(x+35=515:5\)
\(118-x=93\) \(x+35=103\)
\(x=118-93\) \(x=103-35\)
\(x=25\) \(x=68\)
\(b,814-\left(x-305\right)=712\) \(\left[\left(6.x-39\right):3\right].28=5628\)
\(x-305=814-712\) \(\left(6.x-39\right):3=5628:28\)
\(x-305=102\) \(\left(6.x-39\right):3=201\)
\(x=102+305\) \(6.x-39=201x3\)
\(x=407\) \(6.x-39=603\)
\(6x=603+39\)
\(6x=642\)
\(x=107\)
\(e,2.x-138=2^3.2^2\)
\(2.x-138=32\)
\(2.x=32+138\)
\(2.x=170\)
\(x=170:2\)
\(x=85\)
`@` `\text {Ans}`
`\downarrow`
`317 - (118 - x) = 217`
`=> 118 - x = 317 - 217`
`=> 118 - x = 100`
`=> x = 118 - 100`
`=> x = 18`
Vậy, `x = 18.`
317 - ( 118 - x ) = 217
⇒ 118 - x = 317 - 217
⇒ 118 - x = 100
⇒ x = 118 - 100
⇔ x = 18.
Vậy x = 18.
142 + (118 - x) = 217
118 - x = 217 - 142
118 - x = 75
x = 118 - 75
x = 43
142 + ( 118 - x ) = 217
118 - x = 217 - 142
118 - x = 75
x = 118 - 75
x = 43
\(118-x=310-217=93\)
\(x=118-93=25\)
\(=nhae\)
\(=\)ThànhĐạt Nguyễn
(118-x)=310-217 |118-x =93 | x=118 - 93 | x=25