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Đặt \(A=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{23.24.25}\)
\(\Rightarrow2A=\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{23.24.25}\)
\(=\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+....+\frac{1}{23.24}-\frac{1}{24.25}\)
\(=\frac{1}{1.2}-\left(\frac{1}{2.3}-\frac{1}{2.3}\right)-\left(\frac{1}{3.4}-\frac{1}{3.4}\right)-\left(\frac{1}{4.5}-\frac{1}{4.5}\right)-....-\left(\frac{1}{23.24}-\frac{1}{23.24}\right)-\frac{1}{24.25}\)
\(=\frac{1}{1.2}-\frac{1}{24.25}\)
\(=\frac{1}{2}-\frac{1}{600}=\frac{299}{600}\)
Vậy : \(A=\frac{299}{600}\)
câu 1 2/8+2/24+2/48+2/80+2/120
câu 2 1/1*2+1/2*3+1/3*4+...+1/45*46
câu 3 4/1*3+4/3*5+4/5*7+...+4/51*53
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Câu 1: 2/2.4 +2/4.6+2/6.8+.....+2/10.12
= 1/2-1/4+1/4-1/6+......+1/10-1/12
=1/2-1/12
=6/12-1/12
=5/12
Câu 2: =1-1/46
= 45/46
2/2.4 +2/4.6+2/6.8+.....+2/10.12
= 1/2-1/4+1/4-1/6+......+1/10-1/12
=1/2-1/12
=6/12-1/12
=5/12
Câu 2: =1-1/46
= 45/46
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\(=\left(\frac{6}{12}+\frac{8}{12}-\frac{9}{12}\right).24\)
\(=\frac{6+8-9}{12}.24=\frac{5}{12}.24=10\)
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3 + 2x - 1 = 24 - [42- (22 - 1)]
3 + 2x-1 = 24 - [42 - (4 - 1)]
3 + 2x-1 = 24 - (16 - 3)
3 + 2x-1 = 24 - 13
3 + 2x-1 = 11
2x-1 = 11- 3
2x-1 = 8
2x-1 = 23
x - 1 = 3
x = 3 + 1
x = 4