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a) 0,01 : 25 = ( 0,75 . x ) : 0,75
\(\Rightarrow\frac{1}{2500}=0,75\cdot x:0,75\)
\(\Rightarrow x=\frac{1}{2500}\)
b) \(\left(3,8\right):\left(2x\right)=\frac{1}{4}:\frac{8}{3}\)
\(\Rightarrow3,8:\left(2x\right)=\frac{3}{32}\)
\(\Rightarrow2x=3,8:\frac{3}{32}=\frac{608}{15}\)
\(\Rightarrow x=\frac{608}{15}:2=\frac{304}{15}\)
( 0,25x ) : 3 = 5/6 : 0,125
( 1/4x ) : 3 = 5/6 : 1/8
( 1/4x ) : 3 = 5/6 x 8
( 1/4x ) : 3 = 20/3
1/4x = 20/3 x 3
1/4x = 20
x = 20 : 1/4
x = 80
0,01 : 2,5 = ( 0,75x ) : 0,75
1/100 : 25/10 = (3/4x) : 3/4
1/100 x 10/25 = (3/4x) : 3/4
=>(3/4x) : 3/4 = 1/250
3/4x = 1/250 x 3/4
3/4x = 3/1000
x = 3/1000 : 3/4
x = 1/250
\(a,3,8:2x=\frac{1}{4}:2\frac{2}{3}\)
\(\Leftrightarrow3,8:2x=\frac{3}{32}\)
\(\Leftrightarrow2x=3,8:\frac{3}{32}\)
\(\Leftrightarrow2x=\frac{608}{15}\)
\(\Leftrightarrow x=\frac{304}{15}\)
\(b,0,25x:3=\frac{5}{6}:0,125\)
\(\Leftrightarrow0,25x:3=\frac{20}{3}\)
\(\Leftrightarrow0,25x=20\)
\(\Leftrightarrow x=80\)
\(c,0,01:2,5=0,75x:0,75\)
\(\Leftrightarrow0,75x:0,75=\frac{1}{250}\)
\(\Leftrightarrow x=\frac{1}{250}\)
Mik lm hơi tắt chỗ nào chw hiểu thì hỏi mik nhé
a: =>x+2/5=11/12-2/3=11/12-8/12=3/12=1/4
=>x=1/4-2/5=5/20-8/20=-3/20
b: \(\Leftrightarrow x\cdot\dfrac{11}{4}=\dfrac{11}{7}:\dfrac{1}{100}=\dfrac{1100}{7}\)
=>x=1100/7:11/4=400/7
c: =>x=0 hoặc x-1/7=0
=>x=0 hoặc x=1/7
d: =>2x=608/15
=>x=304/15
Tìm x trong các tỉ lệ thức sau :
\(\left(a\right)3,8\div\left(2x\right)=\frac{1}{4}\div2\frac{2}{3}\)
\(3,8\div\left(2x\right)=\frac{3}{32}\)
\(2x=3,8\div\frac{3}{32}\)
\(2x=40\frac{8}{15}\)
\(x=20\frac{4}{15}\)
\(\left(0,25x\right)\div3=\frac{5}{6}\div0,125\)
\(\left(0,25x\right)\div3=6\frac{2}{3}\)
\(\left(0,25x\right)=6\frac{2}{5}\times3\)
\(\left(0,25x\right)=20\)
\(x=80\)
\(0,01\div2,5=\left(0,75x\right)\div0,75\)
\(0,004=\left(0,75x\right)\div0,75\)
\(0,75x=0,75\times0,004\)
\(0,75x=0,003\)
\(x=0,004\)
\(1\frac{1}{3}\div0,8=\frac{2}{3}\div\left(0,1x\right)\)
\(1\frac{2}{3}=\frac{2}{3}\div\left(0,1x\right)\)
\(\left(0,1x\right)=\frac{2}{3}\div1\frac{2}{3}\)
\(\left(0,1x\right)=\frac{2}{5}\)
\(x=4\)
Dung ko z
\(\left(2x+3y\right)^2\)
\(=\left(2x\right)^2+2\cdot2x\cdot3y+\left(3y\right)^2\)
\(=4x^2+12xy+9y^2\)
\(\left(0,01+xy\right)^2\)
\(=\left(0,01\right)^2+2\cdot0,01\cdot xy+\left(xy\right)^2\)
\(=0,0001+0,02xy+x^2y^2\)
\(2\dfrac{3}{4}:x=3\dfrac{1}{7}:0.01\)
\(\Leftrightarrow\dfrac{11}{4}:x=\dfrac{22}{7}\cdot100\)
\(\Leftrightarrow x=\dfrac{11}{4}:\dfrac{2200}{7}=\dfrac{7}{800}\)
\((2x+1)^3=-0,01\)
\(=>(2x+1)^3=(\sqrt[3]{-0,01})^3\)
\(=>2x+1=\sqrt[3]{-0,01}\)
\(=>2x=\sqrt[3]{-0,01}-1\)
\(=>x=\dfrac{\sqrt[3]{-0,01}-1}{2}\)
Mình chưa học phương trình nên bạn giải kiểu lũy thừa được không?