Question

[Đỗ Văn Duy Anh]

{[(2*x-5)*23-246/123]-5}/5=4

Answer 1

[Thảo Phương]

\(\dfrac{\left\{\left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]-5\right\}}{5}=4\\\Rightarrow\left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]-5=20\\ \Leftrightarrow \left[\left(2x-5\right)\cdot23-\dfrac{246}{123}\right]=25\\\Rightarrow\left(2x-5\right)\cdot23=25+\dfrac{246}{123} =27\\ \Rightarrow2x-5=\dfrac{27}{23}\\\Leftrightarrow 2x=\dfrac{27}{23}+5=\dfrac{142}{23}\\ \Leftrightarrow x=\dfrac{142}{23}:2=\dfrac{71}{23}\)

Answer 2

[Phạm Như Nam]

{[(2xx-5)x23-246:123]-5}:5=4

{[(2xx-5)x23-2]-5}=4x5

{[(2xx-5)x23-2]-5}=20

[(2xx-5)]x23-2]=20+5

[(2xx-5)]x23-2]=25

(2xx-5)x23=25+2

(2xx-5)x23=27

2xx-5=27:23

2xx-5=27/23

2xx=27/23+5

2xx=142/23

x=142/23:2

x=71/23