Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(2^{x+1}-2^x=3^2\)
\(\Rightarrow2^x\cdot\left(2-1\right)=9\)
\(\Rightarrow2^x=9\)
\(\Rightarrow x\in\varnothing\)
\(2^{x+1}-2^x=3^2\)
=>2^x*2-2^x=9
=>2^x=9
=>\(x\in\varnothing\)
\(2^2\cdot3\left(x+5\right)-6^2=\left(2^3+2^2\right)\cdot2^2\)
\(\Rightarrow4\cdot\left(3x+15\right)-36=12\cdot4\)
\(\Rightarrow12x+60-36=48\)
\(\Rightarrow12x+24=48\)
\(\Rightarrow12x=24\)
\(\Rightarrow x=24:12=2\)
`@` `\text {Ans}`
`\downarrow`
`(2^2+1) \times (x+14) = 5^2 \times 4 + (2^5 + 3^2 + 7^2) \div 2`
` \Rightarrow (4+1) \times (x+14) = 5^2\times 2^2 + ( 32 + 9 + 49) \div 2`
`\Rightarrow 5 \times (x+14) = (5*2)^2 + (32+58) \div 2`
`\Rightarrow 5 \times (x+14) = 10^2+90 \div 2`
`\Rightarrow 5 \times (x+14) = 100 + 45`
`\Rightarrow 5 \times (x+14) = 145`
`\Rightarrow x+14 = 145 \div 5`
`\Rightarrow x+14=29`
`\Rightarrow x=29-14`
`\Rightarrow x=15`
Vậy, `x=15.`
\(\left(2^2+1\right)\cdot\left(x+14\right)=5^2\cdot4+\left(2^5+3^2+7^2\right):2\)
\(\Rightarrow\left(4+1\right)\cdot\left(x+14\right)=25\cdot4+\left(32+9+49\right):2\)
\(\Rightarrow5\cdot\left(x+14\right)=100+45\)
\(\Rightarrow5x+70=145\)
\(\Rightarrow5x=75\)
\(\Rightarrow x=\dfrac{75}{5}=15\)
b)\(3.4^2-2.3=3.\left(4^2-3\right)\)
\(=3.13\)
\(=39\)
Học tốt nha!!!
\(142-\left[50-\left(2^3×10-2^3×5\right)\right]\)
\(=142-\left[50-\left(8×10-8×5\right)\right]\)
\(=142-\left[50-\left(80-40\right)\right]\)
\(=142-\left[50-40\right]\)
\(=142-10\)
\(=132\)
142-[50-(8 x 10 - 8 x5)]
142-{50-[8 x(10-5)}
142-{50-8 x 5}
142-{50-40}
142-10
132
2^3.x+3^2.x=51
\(\Rightarrow\)8.x+9.x=51
\(\Rightarrow\)x.(8+9)=51
\(\Rightarrow\)x.17=51
\(\Rightarrow\)x=51/17
\(\Rightarrow\)x=3
\(2^3x+3^2x=51\)
\(\Leftrightarrow8x+9x=51\)
\(\Leftrightarrow\left(8+9\right)x=51\)
\(\Leftrightarrow17x=51\)
\(\Leftrightarrow x=51:17\)
\(\Leftrightarrow x=3.\)
Vậy \(x=3.\)
\(a,\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)< x< \left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}\)
\(taco:\left(\frac{31}{20}-\frac{26}{45}\right)\cdot\left(\frac{-36}{35}\right)=\frac{35}{36}\cdot\frac{-36}{35}=-1\)
\(\left(\frac{51}{56}+\frac{8}{21}+\frac{1}{3}\right)\cdot\frac{8}{13}=\frac{13}{8}\cdot\frac{8}{13}=1\)
\(=>x=0\)
\(b,\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}< x< \frac{-1}{2}+2+\frac{5}{2}\)(dau <co dau gach ngang o duoi nha)
\(taco:\frac{-5}{6}+\frac{8}{3}+\frac{29}{-3}=\frac{-5}{6}+\frac{8}{3}+\frac{-29}{3}=\frac{-5}{6}+\frac{16}{6}+\frac{-58}{6}=\frac{-47}{6}=-7,8\)
\(\frac{-1}{2}+2+\frac{5}{2}=\frac{3}{2}+\frac{5}{2}=4\)
tu do \(=>x=-7,8;...;0;1;2;3;4\)
2(x-51) =2.2 mũ 3 + 20
2(x-51) =2.8+20
2(x-51) =16+20
2(x-51) =36
x-51 =36:2
x-51 =18
x =18+51
x =69
2. (x - 51) = 2. 23 + 20
2. (x - 51) = 16 + 20
2. (x - 51) = 36
(x - 51) = 36 : 2
(x - 51) = 18
x = 18 + 51
x = 69