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a: 22.x+32.x=39 b: 42.x-32.x=49
=> (4+9).x=39 =>(16-9).x=49
=>13.x=39 =>7.x=49 NHỚ CHO ANH NHA:) <3
=>x=39:13 =>x=49:7
=>x=3 =>x=7


Ta có:\(\left(x-2\right)^{10}=\left(x-2\right)^{12}\)
\(\Leftrightarrow\left(x-2\right)^{12}-\left(x-2\right)^{10}=0\)
\(\Leftrightarrow\left(x-2\right)^{10}\left[\left(x-2\right)^2-1\right]=0\)
\(\Leftrightarrow\orbr{\begin{cases}\left(x-2\right)^{10}=0\\\left(x-2\right)^2-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\\left(x-2\right)^2=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2\\x\in\left\{3;1\right\}\end{cases}}\)
Vậy \(x\in\left\{-1,2,3\right\}\)
b) Ta có: \(4^{x+2}+4^{x+3}+4^{x+4}+4^{x+5}=85.\left(2^{2016}:2^{2012}\right)\)
\(\Leftrightarrow4^{x+2}\left(1+4+4^2+4^3\right)=85.2^4\)
\(\Leftrightarrow4^{x+2}.85=1360\)
\(\Leftrightarrow4^x=16\)
\(\Leftrightarrow4^x=4^2\)
\(\Leftrightarrow x=2\)
Vậy x=2

\(\text{[}2^2+2^1+2^2+2^3\text{]}.2^0.2^1.2^2.2^3\)
\(=\left(4+2+4+8\right).1.2.4.8\)
\(=\left(8+10\right).2.32\)
\(=18.64=1152\)
Chúc bạn học tốt (Cách này k đc nhanh lắm)

bài cuối đây:
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
[(x+100)+(x+1)].100 /2 =5750
(2x+101).100 /2 =5750
(2x+101).50=5750
2x+101=115
2x=14
x=7

a) 22.14x . 72 = 14100
=> (2.7)2 . 14x = 14100
=> 14x = 14100 : 142
=> 14x = 1498
=> x = 98
b) 15.x + 3(x + 2) = 96
=> 15x + 3x + 6 = 96
=> 18x = 96 - 6
=> 18x = 90
=> x = 90 : 18 = 5
c) 2x + 4.2x = 5.25
=> 2x(1 + 4) = 5.25
=> 2x .5= 5.25
=> 2x = 5.25 : 5
=> 2x = 25
=> x = 5
\(a,2^2.14^x.7^2=14^{100}\)
\(\Rightarrow14^2.14^x=14^{100}\)
\(\Rightarrow14^x=14^{98}\)
\(\Rightarrow x=98\)
\(b,15.x+3\left(x+2\right)=96\)
\(\Rightarrow3\left(5x+x+2\right)=96\)
\(\Rightarrow6x+2=32\)
\(\Rightarrow6x=30\)
\(\Rightarrow x=5\)
\(c,2^x+4.2^x=5.2^5\)
\(\Rightarrow2^x\left(1+4\right)=5.2^5\)
\(\Rightarrow2^x.5=5.2^5\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
x=2
có gì tk minh nha
2^x.2^4=2^6
2^x=2^6:2^4=2^2
x=2
vậy x=2