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1.\(\frac{x+1}{x-2}=\frac{3}{4}\)
\(\Leftrightarrow\left(x+1\right).4=\left(x-2\right).3\)
\(\Leftrightarrow4x+4=3x-6\)
<=>4x-3x=-6-4
<=>x=-10
2.\(\frac{52}{2x-1}=\frac{13}{30}\)
<=>52.30=(2x-1).13
<=>1560=26x-13
<=>-26x=-13-1560
<=>-26x=-1573
<=>x=60,5
3.\(\frac{2x-3}{x+1}=\frac{4}{7}\)
<=>(2x-3).7=(x+1).4
<=>14x-21=4x+4
<=>14x-4x=4+21
<=>10x=25
<=>x=2,5
4.\(\frac{2x+3}{42}=\frac{3x-1}{32}\)
<=>(2x+3).32=42(3x-1)
<=>64x+96=126x-42
<=>64x-126x=-42-96
<=>-62x=-138
<=>x=69/31
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a) Có: 2\(^5\) = 32
Nên 2\(^{x+1}\)= 32
Nên x+1 = 5
x = 5-1
x = 4
b) Hình như sai đề, bạn xem lại thử nha
c) (7\(^x\))\(^2\)= 7\(^{14}\)
7\(^x\) = 7\(^7\)
x = 7
d) Cái này cũng hơi có vấn đề này. Vì (-0.5)\(^5\)= \(\frac{-1}{32}\) mà xem lại nha!!
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\(2^{x-1}+5\cdot2^{x-2=\frac{7}{32}}\)
\(2^{x-1}+5\cdot2^{\frac{71}{32}}\)
\(2^{\frac{39}{32}}+23.2744\)
\(25.60194\)
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mk lam luon nhe!
Bot vao moi ve 3 don vi, ta co
\(\left(\frac{x-7}{50}-1\right)+\left(\frac{x-6}{51}-1\right)+\left(\frac{x-5}{52}-1\right)=\left(\frac{x-52}{5}-1\right)+\left(\frac{x-51}{6}-1\right)+\left(\frac{x-50}{7}-1\right)\)
Quy dong len ,ta co
\(\frac{x-57}{50}+\frac{x-57}{51}+\frac{x-57}{52}=\frac{x-57}{5}+\frac{x-57}{6}+\frac{x-57}{7}\)
\(\frac{x-57}{50}+\frac{x-57}{51}+\frac{x-57}{52}-\frac{x-57}{5}-\frac{x-57}{6}-\frac{x-57}{7}=0\)
(x-57).\(\left(\frac{1}{50}+\frac{1}{51}+\frac{1}{52}-\frac{1}{5}-\frac{1}{6}-\frac{1}{7}\right)=0\)
Ma \(\left(\frac{1}{50}+\frac{1}{51}+\frac{1}{52}-\frac{1}{5}-\frac{1}{6}-\frac{1}{7}\right)\) khac 0 nen => x-57=0
x=0+57 =57
Vay x =57.
Mk chac chan 100% bai nay dung
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a,\(\left(x-\frac{7}{9}\right)^3=\left(\left(\frac{2}{3}\right)^2\right)^3\)
\(x-\frac{7}{9}=\frac{4}{9}\)
\(x=\frac{4}{9}+\frac{7}{9}\)
\(x=\frac{11}{9}\)
Vậy x=\(\frac{11}{9}\)
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I, Tìm x biết :
1.\(\frac{x}{-15}=\frac{-60}{x}\)
\(\Leftrightarrow2x=\left(-15\right).\left(-60\right)\)
\(\Leftrightarrow2x=900\)
\(\Leftrightarrow x=450\)
2. \(\frac{x-2}{x-1}=\frac{x+4}{x+7}\)
\(\Leftrightarrow\left(x-2\right).\left(x+7\right)=\left(x-1\right).\left(x+4\right)\)
\(\Leftrightarrow x^2+7x-2x-14=x^2+4x-x-4\)
\(\Leftrightarrow5x-14=3x-4\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\)
Vậy : \(x=5\)
3)\(\frac{37-x}{x+13}=\frac{-3}{-7}=\frac{3}{7}\)
\(\Leftrightarrow\left(37-x\right).7=\left(x+13\right).3\)
\(\Leftrightarrow259-7x=3x+39\)
\(\Leftrightarrow220=4x\)
\(\Leftrightarrow x=55\)
Vậy : \(x=55\)
I.
1) \(\frac{x}{-15}=\frac{-60}{x}\)
=> \(x.x=\left(-60\right).\left(-15\right)\)
=> \(x.x=900\)
=> \(x^2=900\)
=> \(\left[{}\begin{matrix}x=30\\x=-30\end{matrix}\right.\)
Vậy \(x\in\left\{30;-30\right\}.\)
Chúc bạn học tốt!