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a) \(\frac{1}{3}-\frac{3}{4}-\left(\frac{-3}{5}\right)+\frac{1}{64}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)
=\(\left(\frac{1}{3}+\frac{3}{5}+\frac{1}{15}\right)-\left(\frac{3}{4}+\frac{2}{9}+\frac{1}{36}\right)+\frac{1}{64} \)
=\(\frac{5+9+1}{15}-\frac{27+8+1}{36}+\frac{1}{64}\)
= \(1+1+\frac{1}{64}=2\frac{1}{64}\)
B=(1/5-1/5) + (-3/7+3/7) + (5/9-5/9) + (-2/11+2/11) + (7/13-7/13) - 9/16
= 0 + 0 + 0 + 0 + 0 - 9/16
=-9/16
\(B=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
\(B=\left(\frac{1}{5}-\frac{1}{5}\right)-\left(\frac{3}{7}-\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)-\left(\frac{2}{11}-\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)
\(B=0-0+0-0+0-\frac{9}{16}\)
\(B=0-\frac{9}{16}\)
\(B=-\frac{9}{16}\)
Bài này rất dễ sai dấu
Ủng hộ mk nha ^_-
A=(9-3/5+2/3)-(7+7/5-3/2)-(9/5+5/2)
A=9 -3/5 +2/3-7-7/5+3/2-9/5-5/2
A=(9-7)-(3/5+7/5 +9/5)+(3/2-5/2)+2/3
=2-19/5-1+2/3= -32/15
1^3-3^5-(-3^5)+1^64-2^9-1^36+1^15
=1+(-3^5+3^5)+1-2^9-1+1
=2-2^9
=-510
\(A=\frac{1}{5}-\frac{3}{7}+\frac{5}{9}-\frac{2}{11}+\frac{7}{13}-\frac{9}{16}-\frac{7}{13}+\frac{2}{11}-\frac{5}{9}+\frac{3}{7}-\frac{1}{5}\)
\(=\left(\frac{1}{5}-\frac{1}{5}\right)+\left(-\frac{3}{7}+\frac{3}{7}\right)+\left(\frac{5}{9}-\frac{5}{9}\right)+\left(-\frac{2}{11}+\frac{2}{11}\right)+\left(\frac{7}{13}-\frac{7}{13}\right)-\frac{9}{16}\)
\(=0+0+0+0+0+\frac{9}{16}=\frac{9}{16}\)
Giải :
\(\frac{6^7.4^2}{9^2.12^5}=\frac{\left(2.3\right)^7.\left(2^2\right)^2}{\left(3^2\right)^2.\left(3.2^2\right)^5}=\frac{2^7.3^7.2^4}{3^4.3^5.2^{10}}=\frac{2^{11}.3^7}{3^9.2^{10}}=\frac{2}{3^2}=\frac{2}{9}\)
a. [ -2/3 + 3/7 ] : 4/5 + [ -1/3 + 4/7 ] : 4/5 = 0
b. 5/9 : [ 1/11 - 5/22 ] + 5/9 : [ 1/15 - 2/3 ] = -5
HT/nhớ k cho tôi nha
Ai làm xong sớm nhất tui k cho
\(\left(\frac{2}{9}\right)^5-\left(\frac{9}{7}\right)^5\)
\(=\frac{2^5}{9^5}-\frac{9^5}{7^5}\)
\(=\frac{32}{59049}-\frac{59049}{16807}\)
\(=\frac{32}{59049}-\frac{59049}{16807}=......\)