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\(\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{51}{81}\)
\(\left(x+x+x+x\right)+\left(\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\right)=\frac{51}{81}\)
\(\left(x+x+x+x\right)+\left(\frac{27}{81}+\frac{9}{81}+\frac{3}{81}+\frac{1}{81}\right)=\frac{51}{81}\)
\(x\times4+\frac{40}{81}=\frac{51}{81}\)
\(x\times4=\frac{51}{81}-\frac{40}{81}\)
\(x\times4=\frac{11}{81}\)
\(\Rightarrow x=\frac{11}{81}\div4=\frac{11}{81}\times\frac{1}{4}\)
\(\Rightarrow x=\frac{11}{324}\)
[ 61 + ( 53 - x ) ] . 17 = 1785
61 + ( 53 - x ) = 1785 : 17
61 + ( 53 - x ) = 105
( 53 - x ) = 105 - 61
53 - x = 44
=> x = 53 - 44
=> x = 9
Câu 1 :\(289:17-324:18+18:3\)
\(=17-18+6\)
\(=-1+6\)
\(=5\)
Câu 2 : \(18.3-182+3.\left(51:17\right)\)
\(=18.3-182+3.3\)
\(=54-182+9\)
\(=-128+9\)
\(=-119\)
49-51+53-55+57-59
=(49-51)+(53-55)+(57-59)+61
=-2+(-2)+(-2)+61
=55
-1962+1963+1246+1146+101
= 1 + 1246 + 1146 + 101
= 1247 + 1146 + 101
= 2393 + 101
= 2494
1379-(27+379)
= 1379 - 406
= 1785
4971-(917-289)
= 4971 - 628
= 4343
-1962+1963+1246+1146+101=2496
1379-(27+379)=973
4971-(917-289)=4343
a) A=625–(61–17).12+(27+27):17A=625–(61–17).12+(27+27):17
=625–528+3=100=625–528+3=100
b) B=−126–(42–5)2+870:29B=−126–(42–5)2+870:29
=−126–112+30=−126–112+30
=−126–121+30=−217
49-51+53-55+57-59+61-63+65
=(49+-51)+(53+-55)+(57+-59)+(61+-63)+65
=-2+-2+-2+-2+65
=-8+65
=57
Nhớ k cho mình nha mệt lắm đó
-(289+51)+(389+61)-(-27)
= -289 - 51 + 389 + 61 + 27
= (389 - 289) + (61 - 51) + 27
= 100 + 10 + 27
= 110 + 27
= 137
- (289 + 51) + (389 + 61) - (-27)
= -289 - 51 + 389 + 61 + 27
= (-289 + 389) + (-51 + 61) + 27
= 100 + 10 + 27
= 110 + 27
= 137