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\(36\div\left[7.\left(x-3\right)+4\right]=6\)
\(\Rightarrow7.\left(x-3\right)+4=36\div6\)
\(\Rightarrow7.\left(x-3\right)+4=6\)
\(\Rightarrow7.\left(x-3\right)=6-4\)
\(\Rightarrow7.\left(x-3\right)=2\)
\(\Rightarrow x-3=2\div7\)
\(\Rightarrow x-3=\frac{2}{7}\)
\(\Rightarrow x=\frac{2}{7}+3\)
\(\Rightarrow x=\frac{23}{7}\)
\(36:\left[7.\left(x-3\right)+4\right]=6\)
\(7.\left(x-3\right)+4=36:6\)
\(7.\left(x-3\right)+4=6\)
\(7.\left(x-3\right)=6-4\)
\(7.\left(x-3\right)=2\)
\(x-3=2:7\)
\(x-3=\frac{2}{7}\)
\(x=\frac{2}{7}+3\)
\(x=\frac{23}{7}\)
\(4\left(x+2\right)-8\left(x+3\right)=36\)
\(\Rightarrow4x+8-8x-24=36\)
\(\Rightarrow4x-8x=36+24-8\)
\(\Rightarrow-4x=52\)
\(\Rightarrow x=-13\)
\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)
a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)
b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)
c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)
d. \(8782-291\cdot13=8782-3783=4999\)
e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)
f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\
\(\left(x-4\right)^9=49.\left(x-4\right)^7\\ =>\left(x-4\right)^9:\left(x-4\right)^7=49\\ =>\left(x-4\right)^2=49\\ =>\left[{}\begin{matrix}x-4=7\\x-4=-7\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=11\\x=-3\end{matrix}\right.\)
(x - 4)9 = 49 . (x - 4)7
(x - 4)9 : (x - 4)7 = 49
(x - 4)2 = 72 = (-7)2
TH1 : TH2 :
(x - 4)2 = 72 (x - 4)2 = (-7)2
x - 4 = 7 x - 4 = -7
x = 7 + 4 x = -7 + 4
x = 11 x = -3
Vậy x = 11 Vậy x = -3
\(x.0=7\)
\(\Leftrightarrow0=7\)(Vô lý)
Vậy không có giả trị x nào thoả mãn yêu cầu bài toán.
\(1500:\left[\left(30x+40\right):x\right]=30\)
\(\left[\left(30x+40\right):x\right]=1500:30\)
\(\left[\left(30x+40\right):x\right]=50\)
\(30x:x+40:x=50\)
\(30+40:x=50\Leftrightarrow40:x=50-30\)
\(40:x=20\Leftrightarrow x=40:20\Leftrightarrow x=2\)
1500 : [(30.x+40):x] = 30
\(\left(30.x+40\right):x=50\)
=> 30.x + 40 = 50.x
=> 30.x - 50.x = -40
-20x = -40
x = 2
a) ( x - 4 ) . ( x - 3 ) = 0
Thỏa mãn điều kiện x - 4 hoặc x - 3 bằng 0 .
\(\Rightarrow\hept{\begin{cases}x=4\\x=3\end{cases}}\)
b) ( x - 4 ) . ( y - 3 ) = 0
Thỏa mãn điều kiện x - 4 hoặc y - 3 bằng 0 .
\(\Rightarrow\hept{\begin{cases}x=4,x=3\\y=4,y=3\end{cases}}\)
c) x - 24 : 12 = 15
x - 2 = 15
x = 13
d) ( x - 12 ) : 13 = 5
x - 12 = 65
x = 77
e) 1 + 3 + 5 + ..... + x = 36
..... + x = 27
..... + x = 20
x = 11
f) 2 + 4 + .... + 2x = 110
2 + 4 + ....x = 55
Thỏa mãn điều kiện \(x\in N\left|2x+0\right|x⋮2\)
\(x\in\varnothing\)
\(5\cdot x+10\cdot9=990\)
\(\Rightarrow5\cdot x+90=990\)
\(\Rightarrow5\cdot x=900\)
\(\Rightarrow x=\dfrac{900}{5}\)
\(\Rightarrow x=180\)
_____________
\(1045:\left[215-\left(3\cdot x-24\right)\right]=5\)
\(\Rightarrow215-\left(3\cdot x-24\right)=1045:5\)
\(\Rightarrow215-\left(3\cdot x-24\right)=209\)
\(\Rightarrow3\cdot x-24=215-209\)
\(\Rightarrow3\cdot x-24=6\)
\(\Rightarrow3\cdot x=30\)
\(\Rightarrow x=10\)
`@` `\text {Ans}`
`\downarrow`
`5.x + 10.9 = 990`
`\Rightarrow 5x + 90 = 990`
`\Rightarrow 5x = 990 - 90`
`\Rightarrow 5x = 900`
`\Rightarrow x = 900 \div 5`
`\Rightarrow x = 180`
Vậy, `x = 180`
\(1045 \div [ 215 - (3 . x - 24 ) ] = 5\)
`\Rightarrow 1045 \div (215 - 3x + 24) = 5`
`\Rightarrow 191 + 3x = 1045 \div 5`
`\Rightarrow 191 + 3x = 209`
`\Rightarrow 3x = 209 - 191`
`\Rightarrow 3x =18`
`\Rightarrow x = 18 \div 3`
`\Rightarrow x = 6`
Vậy, `x = 6.`
Bạn ơi !
đề bài của bạn : (x=+5).12=60 mình nghĩ là nhầm lẫn chỗ x=+5
Nếu đề bài đúng mình nghĩ là(x+5).12=60
<=>x+5=60:12=5
<=>x=5-5=0
KL: Vậy x = 0
\(2,7\cdot x+36=-12,8\)
\(2,7\cdot x=-12,8-36\)
\(2,7\cdot x=-48,8\)
\(x=-48,8:2,7\)
\(x=\dfrac{-488}{27}\)
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