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(27x+6)÷3-11=9
=> (27x+6)÷3=20
=> 27x + 6 = 60
=> 27x = 54
=> x = 2
(27.x + 6) : 3 - 11 = 9
(27x + 6) : 3 = 9 + 11
(27x + 6) : 3 = 20
27x + 6 = 20 . 3
27x + 6 = 60
27x = 60 - 6
27x = 54
x = 54 : 27
x = 2
2: \(=\dfrac{-2}{75}+\dfrac{5}{39}=\dfrac{33}{325}\)
3: \(=\dfrac{6}{11}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{6}{11}\)
4: \(=\dfrac{7}{19}\left(\dfrac{5}{13}+\dfrac{8}{13}-1\right)=-2\cdot\dfrac{7}{19}=-\dfrac{14}{19}\)
5: \(=\dfrac{2}{7}\left(\dfrac{4}{23}-\dfrac{27}{23}+1\right)=0\)
6: \(=\dfrac{3}{8}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{11}{8}=\dfrac{3}{8}+\dfrac{11}{8}=\dfrac{14}{8}=\dfrac{7}{4}\)
\(\left(27x+6\right):3-11=9\)
\(\left(27x+6\right):3=9+11=20\)
\(27x+6=60\)
\(27x=54\)
\(x=2\)
\(=\left(5.3^{12}+4.3^{12}\right):3^{12}\)
\(=3^{12}\left(5+4\right):3^{12}\)
\(=9\)
\(a,\left(27x+6\right):3-11=9\)
\(\Rightarrow\left(27x-6\right):3=20\)\(\Rightarrow27x-6=60\)\(\Rightarrow27x=66\)\(\Rightarrow x=\frac{22}{9}\)
\(b,\left(15-6x\right).3^5=3^6\)
\(\Rightarrow15-6x=3\)\(\Rightarrow6x=12\)\(\Rightarrow x=2\)
\(c,\left(2x-6\right).4^7=4^9\)
\(\Rightarrow2x-6=16\)\(\Rightarrow2x=22\)\(\Rightarrow x=11\)
Bài 1: Tìm x
a,(27.x+6):3-11=9
﴾ 27x + 6﴿ : 3 ‐ 11 = 9
﴾ 27x + 6﴿ : 3 = 20
27x + 6 = 60
27x = 54
x = 54 : 27
x = 2
Vậy x = 2
b,( 15-6x ) . 35=36
( 15 - 6x ) = 36 : 35
15 - 6x = 3
6x = 15 - 3
6x = 12
x = 12 : 6
x = 2
Vậy x = 2
c,( 2x-6 ) . 47=49
2x - 6 = 49 : 47
2x - 6 = 16
2x = 16 + 6
2x = 22
x = 22 : 2
x = 11
Vậy x = 11
( 27x + 6) : 3 - 11 = 9
( 27x + 6) : 3 = 20
27x + 6 = 60
27x = 54
x = 2
(27*x+6):3=9+11=20
27x+6=20 .3=60
27x=60-6=54
x=54:27
x=2