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1) Tìm số nguyên x, biết :
a) 3x = 94/ 273
3x = 1/3
3x = 3-1
=> x = -1
b) 3x = 98 / 273 . 812
3x = 37.38
3x = 315
=> x = 15
c) 2x - 3 / 410 = 83
2x - 3 = 83.410
2x - 3 = 226
=> x - 3 = 26
=> x = 29
d) 22x - 3 / 410 = 83 . 165
22x - 3 / 410 = 269
22x - 3 = 269 . 410
22x - 3 = 289
=> 2x - 3 = 89
2x = 91
x = 91/2
e) 35 / 3x = 310
3x = 35 : 310
3x = 3-5
=> x = -5
a ) \(\frac{3^5}{27}=\frac{3^5}{3^3}=\frac{3^3.3^2}{3^3}=3^2=9\)
b ) \(\frac{4^7}{64}=\frac{4^7}{4^3}=\frac{4^3.4^4}{4^3}=4^4=256\)
c ) \(\frac{x^{13}}{x^5}=\frac{x^5.x^8}{x^5}=x^8\)
d ) \(\frac{x^{19}}{x^{18}}=\frac{x^{18}.x}{x^{18}}=x\)
e ) \(\frac{2.x^{10}}{x^7}=\frac{2.\left(x^7.x^3\right)}{x^7}=2.x^3\)
a) ( 3x - 1 )2 - 4
= ( 3x - 1 ) - 22
= ( 3x - 1 - 2 )( 3x - 1 + 2 )
= ( 3x - 3 )( 3x + 1 )
= 3( x - 1 )( 3x + 1 )
b) ( x + y )2 - x2
= ( x + y - x )( x + y + x )
= y( 2x + y )
c) 100 - ( 2x - y )2
= 102 - ( 2x - y )2
= [ 10 - ( 2x - y ) ][ 10 + ( 2x - y ) ]
= ( 10 - 2x + y )( 10 + 2x - y )
d) ( 2x - 1 )2 - ( x - 1 )2
= [ ( 2x - 1 ) - ( x - 1 ) ][ ( 2x - 1 ) + ( x - 1 ) ]
= ( 2x - 1 - x + 1 )( 2x - 1 + x - 1 )
= x( 3x - 2 )
e) 4( x + 6 )2 - 9( 1 + x )2
= 22( x + 6 )2 - 32( 1 + x )2
= ( 2x + 12 )2 - ( 3 + 3x )2
= [ ( 2x + 12 ) - ( 3 + 3x ) ][ ( 2x + 12 + ( 3 + 3x ) ]
= ( 2x + 12 - 3 - 3x )( 2x + 12 + 3 + 3x )
= ( 9 - x )( 5x + 15 )
= 5( 9 - x )( x + 3 )
Bài 1 :
\(M+N\)
\(=\left(2xy^2-3x+12\right)+\left(-xy^2-3\right)\)
\(=2xy^2-3x+12-xy^2-3\)
\(=\left(2xy^2-xy^2\right)-3x+\left(12-3\right)\)
\(=xy^2-3x+9\)
dễ
ai đi qua tick cho mình nha
ai tick thì may mắn trọn đời
\(P\left(x\right)=3x^5+x^4-2x^2+2x-1\)
\(Q\left(x\right)=-3x^5+2x^2-2x+3\)
\(P\left(x\right)+Q\left(x\right)=3x^5+x^4-2x^2+2x-1-3x^5+2x^2-2x+3\)
\(=x^4+2\)
\(P\left(x\right)-Q\left(x\right)=3x^5+x^4-2x^2+2x-1+3x^5-2x^2+2x-3\)
\(=6x^5+x^4-4x^2+4x-4\)
Thu gọn + sắp xếp luôn
P(x) = 3x5 + x4 - 2x2 + 2x - 1
Q(x) = -3x5 + 2x2 - 2x + 3
P(x) + Q(x) = ( 3x5 + x4 - 2x2 + 2x - 1 ) + ( -3x5 + 2x2 - 2x + 3 )
= ( 3x5 - 3x5 ) + x4 + ( 2x2 -- 2x2 ) + ( 2x - 2x ) + ( 3 - 1 )
= x4 + 2
P(x) - Q(x) = ( 3x5 + x4 - 2x2 + 2x - 1 ) - ( -3x5 + 2x2 - 2x + 3 )
= 3x5 + x4 - 2x2 + 2x - 1 + 3x5 - 2x2 + 2x - 3
= ( 3x5 + 3x5 ) + x4 + ( -2x2 - 2x2 ) + ( 2x + 2x ) + ( -1 - 3 )
= 6x5 + x4 - 4x2 + 4x - 4
a/ Ta có: 27x : 3x = 9
=> 33x-x = 9 =\(\left(\pm3\right)^2\)
=> 3x - x = 2
=> 2x = 2
=> x = 1
Vậy x = 1
b/ Ta có:
1/2 . 2x + 4 . 2x = 9 . 25
=> 2x . ( 1/2 + 4 ) = 9 . 32
=> 2x . 9/2 = 288
=> 2x = 64
=> x = 32
Vậy x = 32
a ) 27x : 3x = 9
<=> ( 27 : 3 )x = 9
<=> 9x = 9
=> x = 1
b )\(\frac{1}{2}.2x+4.2x=9.2^5\)
<=> x + 8x = 9.32
<=> 9x = 288
=> x = 288 : 9 = 32