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Câu 1: 2/x=8/5-4/5
=>2/x=4/5
=>2*5=4*x
=>10=4x
=>x=10/4
Câu 2: x=8/3
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\(\frac{5}{11}\)x \(\frac{27}{11}\)- \(\frac{5}{11}\) x \(\frac{2}{7}\)
= \(\frac{5}{11}\)x ( \(\frac{27}{11}\) - \(\frac{5}{11}\))
=\(\frac{5}{11}\)x \(\frac{22}{11}\)
=\(\frac{5}{11}\) x 2 = \(\frac{10}{11}\)
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a, không đủ thông tin
b, 12/27 - x = 2/9
x = 12/27 - 2/9
x = 12/27 - 6/27
x = 6/27
c, 4/5 * x = 9/7
x = 9/7 : 4/5
x = 9/7 * 5/4
x = 45/28
d, 31/29 : x = 9/7
x = 31/29 : 9/7
x = 31/29 * 7/9
x = 217/261
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a. 3.(5+2+3)=30
b. 9.(2+5+3)=90
c. 8.(5-2+6)=72
d. (1000-298).(140:14-10)=702.0=0
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Câu 1)
1/5*x=4/6
x=4/6/1/5
x=10/3
Câu 3)x/6*5/8=5/12
x/6=5/12/5/8
x/6=2/3
x/6=4/6
Vây x=4
Câu 3)
5/9/3/x=5/27
3/x=5/9/5/27
3/x=3
Vây x=1
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\(\frac{25}{27}-\frac{5}{6}\times\frac{2}{3}\)
\(=\frac{25}{27}-\frac{5}{9}\)
\(=\frac{25}{27}-\frac{15}{27}\)
\(=\frac{25-15}{27}\)
\(=\frac{10}{27}\)
\(\frac{25}{27}-\frac{5}{6}\)x\(\frac{2}{3}=\frac{25}{27}-\frac{5}{9}=\frac{25}{27}-\frac{15}{27}=\frac{10}{27}\)
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Bài 1:
a) 19/27+9/7+6/27+5/7+2/7
= (19/27+6/27) + (9/7+5/7+2/7)
=1 + 16/7
=23/7
b) 2/7 + 27/48 + 7/16 +45/63
= (2/7 + 45/63) + (27/48 +7/16)
= (2/7 + 5/7) + ( 9/16 + 7/16)
= 1 + 1
=2
c) Tính bằng cách bình thường
Bài 2:
6/11 + x = 1
x = 1-6/11
x = 5/11
Bài làm
a) \(\frac{19}{27}+\frac{9}{7}+\frac{6}{27}+\frac{5}{7}+\frac{2}{7}\)
\(=\frac{27}{27}+\frac{16}{7}\)
\(=1+\frac{16}{7}\)
\(=\frac{7}{7}+\frac{16}{7}\)
\(=\frac{23}{7}\)
b) \(\frac{2}{7}+\frac{27}{48}+\frac{7}{16}+\frac{45}{63}\)
\(=\left(\frac{18}{63}+\frac{45}{63}\right)+\left(\frac{27}{48}+\frac{21}{48}\right)\)
\(=\frac{63}{63}+\frac{48}{48}\)
\(=1+1\)
\(=2\)
c) \(\frac{17}{23}+\left(\frac{4}{7}-\frac{6}{13}\right)\)
\(=\frac{17}{23}+\left(\frac{52}{91}-\frac{42}{91}\right)\)
\(=\frac{17}{23}+\frac{10}{91}\)
\(=\frac{1547}{2093}+\frac{230}{2093}\)
\(=\frac{1770}{2093}\)
Bài 2
\(\frac{6}{11}+x=1\)
\(x=1-\frac{6}{11}\)
\(x=\frac{11}{11}-\frac{6}{11}=\frac{5}{11}\)
Vậy \(x=\frac{5}{11}\)
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27 x 2/5 = 54/5