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(x- 38) : 16= 12
x-38= 12 . 16
x- 38= 192
x= 192 +38
x= 230
x= 200
Bài 1 :
a) \(\left(18+29\right)+\left(158-18-29\right)\)
\(=\left(18-18\right)+\left(29-29\right)+158\)
\(=0+0+158\)
\(=0+158\)
\(=158\)
b) \(\left(-2\right)^2.3+51:\left(-3\right)\)
\(=4.3+-17\)
\(=12+-17\)
\(=-34\)
\(4,\Rightarrow\overline{\text{*}34\text{*}}=\overline{\text{*}340}⋮9\\ \Rightarrow\text{*}+7⋮9\\ \Rightarrow\text{*}=5\\ \Rightarrow\overline{\text{*}34\text{*}}=5340\\ 5,\Rightarrow\overline{7\text{*}\text{*}}\in\left\{\overline{7\text{*}4};\overline{7\text{*}9}\right\}\)
\(TH_1:\overline{7\text{*}4}⋮3\Rightarrow\text{*}+11⋮3\Rightarrow\text{*}\in\left\{1;4;7\right\}\\ TH_2:\overline{7\text{*}9}⋮3\\ \Rightarrow\text{*}\in\left\{2;5;8\right\}\)
Vậy ...
Để đánh số trang từ 1 đến 9 cần :
( 9 - 1 ) : 1 + 1 = 9 ( chữ số )
Để đánh số trang từ 10 đến 99 cần :
[ ( 99 - 10 ) : 1 + 1 ] x 2 = 180 ( chữ số )
Đế đánh số trang từ 100 đến 120 cần :
[ ( 120 - 100 ) : 1 + 1 ] x 3 = 63 ( chữ số )
Để đánh số trang từ 1 đến 120 cần :
9 + 180 + 63 = 252 ( chữ số )
a) \(\dfrac{2}{3}x-\dfrac{3}{2}x=\dfrac{5}{12}\)
\(x\left(\dfrac{2}{3}-\dfrac{3}{2}\right)=\dfrac{5}{12}\)
\(x\cdot\left(-\dfrac{5}{6}\right)=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\left(-\dfrac{5}{6}\right)\)
\(x=-\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\).
b) \(\dfrac{2}{5}+\dfrac{3}{5}\cdot\left(3x-3\cdot7\right)=-\dfrac{53}{10}\)
\(\dfrac{3}{5}\left(3x-3\cdot7\right)=-\dfrac{53}{10}-\dfrac{2}{5}\)
\(\dfrac{3}{5}\left(3x-3\cdot7\right)=-\dfrac{57}{10}\)
\(3x-3\cdot7=-\dfrac{57}{10}:\dfrac{3}{5}\)
\(3x-3\cdot7=-\dfrac{19}{2}\)
\(3x-21=-\dfrac{19}{2}\)
\(3x=-\dfrac{19}{2}+21\)
\(3x=\dfrac{23}{2}\)
\(x=\)\(\dfrac{23}{2}:3\)
\(x=\dfrac{23}{6}\)
Vậy \(x=\dfrac{23}{6}\).
c) \(\dfrac{7}{9}:\left(2+\dfrac{3}{4x}\right)+\dfrac{5}{3}=\dfrac{23}{27}\)
\(\dfrac{7}{9}:\left(2+\dfrac{3}{4x}\right)=\dfrac{23}{27}-\dfrac{5}{3}\)
\(\dfrac{7}{9}:\left(2+\dfrac{3}{4x}\right)=-\dfrac{22}{27}\)
\(2+\dfrac{3}{4x}=\dfrac{7}{9}:-\dfrac{22}{27}\)
\(2+\dfrac{3}{4x}=-\dfrac{21}{22}\)
\(\dfrac{3}{4x}=-\dfrac{21}{22}-2\)
\(\dfrac{3}{4x}=-\dfrac{65}{22}\)
\(4x=\dfrac{3\cdot22}{-65}\)
\(4x=-\dfrac{66}{65}\)
\(x=-\dfrac{66}{65}:4\)
\(x=-\dfrac{33}{130}\)
Vậy \(x=-\dfrac{33}{130}\).
d) \(-\dfrac{2}{3}x+\dfrac{1}{5}=\dfrac{3}{10}\)
\(-\dfrac{2}{3}x=\dfrac{3}{10}-\dfrac{1}{5}\)
\(-\dfrac{2}{3}x=\dfrac{1}{10}\)
\(x=\dfrac{1}{10}:-\dfrac{2}{3}\)
\(x=-\dfrac{3}{20}\)
Vậy \(x=-\dfrac{3}{20}\).
e) \(\left|x\right|-\dfrac{3}{4}=\dfrac{5}{3}\)
\(\left|x\right|=\dfrac{5}{3}+\dfrac{3}{4}\)
\(\left|x\right|=\dfrac{29}{12}\)
\(x=\dfrac{29}{12}\) hoặc \(=-\dfrac{29}{12}\)
Vậy \(x\in\left\{\dfrac{29}{12};-\dfrac{29}{12}\right\}\).
\(\dfrac{1}{5}:x=\dfrac{7}{35}+\dfrac{5}{35}\)
\(\dfrac{1}{5}:x=\dfrac{12}{35}\)
\(x=\dfrac{1}{5}:\dfrac{12}{35}\)
\(x=\dfrac{1}{5}\times\dfrac{35}{12}\)
\(x=\dfrac{7}{12}\)
27. 23 + 4. 32 – 5. 120
=27 . 8 + 4 . 9 - 5 . 1
=216 + 36 - 5
=252 - 5
=147
ơ gì thế:)??