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3 tháng 1 2016

8/3 

cậu làm ơn tick cái 

3 tháng 1 2016

\(2,\left(6\right)=\frac{8}{3}\)

26 tháng 9 2023

\(\dfrac{6^6+2^7.3^6+2^6.3^7}{4.2^3.3^2.2^2}\)

\(=\dfrac{\left(2^2.3\right)^6+2^7.3^6+2^6.3^7}{2^2.2^3.3^2.2^2}\)\(=\dfrac{2^{12}.3^6+2^7.3^6+2^6.3^7}{2^7.3^2}\)

\(=\dfrac{2^6.3^6.\left(2^6+2+3\right)}{2^7.3^2}\)\(=\dfrac{3^4.69}{2}=\dfrac{5589}{2}\)

 

viết j z

19 tháng 4 2016

co the ma cung ko hieu phan so do

Sửa đề: 3^5+3^5+3^5; 2^x

=>\(2^x=\dfrac{4^5\cdot4}{3^5\cdot3}\cdot\dfrac{6^5\cdot6}{2^5\cdot2}\)

 

=>\(2^x=\left(\dfrac{4}{3}\right)^6\cdot\left(\dfrac{6}{2}\right)^6=4^6=2^{12}\)

=>x=12

1: =1/8*9/4=9/32

2: =8/27*243/32=9/4

3: =(5/4*4/5)^5*(4/5)^2=16/25

4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)

5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)

6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)

8: =(0,2*5)^4*5^2=25

10: =-0,5^5*2^10

=-0,5^5*2^5*2^5

=-32

13: =(0,5*2)^2*2^2=4

 

6 tháng 7 2023

mình cảm ơn ạ

7 tháng 6 2017

\(B=\dfrac{\sqrt{6+2\left(\sqrt{6}+\sqrt{3}+\sqrt{2}\right)}-\sqrt{6-2\left(\sqrt{6}-\sqrt{3}+\sqrt{2}\right)}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{6+2\sqrt{6}+2\sqrt{3}+2\sqrt{2}}-\sqrt{6-2\sqrt{6}+2\sqrt{3}-2\sqrt{2}}}{\sqrt{2}}\)

\(=\dfrac{\left(\sqrt{6+2\sqrt{6}+2\sqrt{3}+2\sqrt{2}}-\sqrt{6-2\sqrt{6}+2\sqrt{3}-2\sqrt{2}}\right)\sqrt{2}}{\sqrt{2}}\)

\(=\dfrac{\sqrt{\left(6+2\sqrt{6}+2\sqrt{3}+2\sqrt{2}\right)\cdot2}-\sqrt{\left(6-2\sqrt{6}+2\sqrt{3}-2\sqrt{2}\right)\cdot2}}{2}\)

\(=\dfrac{\sqrt{12+4\sqrt{6}+4\sqrt{3}+4\sqrt{2}}-\sqrt{12-4\sqrt{6}+4\sqrt{3}-4\sqrt{2}}}{2}\)

\(=\dfrac{4}{2}\)

\(=2\)

\(C=\dfrac{\sqrt{9-6\sqrt{2}}-\sqrt{6}}{\sqrt{3}}\)

\(=\dfrac{\left(\sqrt{9-6\sqrt{2}}-\sqrt{6}\right)\sqrt{3}}{3}\)

\(=\dfrac{\sqrt{\left(9-6\sqrt{2}\right)\cdot3}-3\sqrt{2}}{3}\)

\(=\dfrac{\sqrt{27-18\sqrt{2}}-3\sqrt{2}}{3}\)

\(=\dfrac{\sqrt{\left(3-3\sqrt{2}\right)^2}-3\sqrt{2}}{3}\)

\(=\dfrac{3\sqrt{2}-3-3\sqrt{2}}{3}\)

\(=\dfrac{-3}{3}\)

\(=-1\)