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ta co (x-2163)(1/2011+1/28+1/124)=0
vi 1/2011+1/28+1/124khac0
x-2163=0
x=2163
Đặt \(A=\dfrac{x-28-124}{2011}+\dfrac{x-124-2011}{28}+\dfrac{x-2011-28}{124}=3\)
\(\Rightarrow\dfrac{x-28-124}{2011}-1+\dfrac{x-124-2011}{28}-1+\dfrac{x-2011-28}{124}-1=3-1-1-1\)
\(\Rightarrow\dfrac{x-28-124}{2011}-\dfrac{2011}{2011}+\dfrac{x-124-2011}{28}-\dfrac{28}{28}+\dfrac{x-2011-28}{124}=0\)
\(\Rightarrow\dfrac{x-28-124-2011}{2011}+\dfrac{x-124-2011-28}{28}+\dfrac{x-2011-29-124}{124}=0\)
\(\Rightarrow x-28-124-2011\left(\dfrac{1}{2011}+\dfrac{1}{28}+\dfrac{1}{124}\right)=0\)
\(\Rightarrow x-28-124-2011=0\Rightarrow x=2163\)
Vậy x = 2163
a )
\(\Rightarrow\frac{x-100}{24}-1+\frac{x-98}{26}-1+\frac{x-96}{26}-1=0\)
\(\frac{x-124}{24}+\frac{x-124}{26}+\frac{x-124}{28}=0\)
\(\left(x-124\right)\left(\frac{1}{26}+\frac{1}{24}+\frac{1}{28}\right)=0\)
\(\Rightarrow x-124=0\Rightarrow x=124\)
258 x 28 = (25 x 2)8 = 508
\(25^8.2^8=\left(25.2\right)^8=50^8\)