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= 1125-23 - 35 : ( 1 + 8 ) - 60
= 112 - 35 : 32 - 60
= 112 - 35-2 - 60
= 112 - 33 - 60
= 121 - 27 - 60
= 34
1125 : 1123 - 35 : ( 110 + 23 ) - 60
= 1125 - 23 - 35 : ( 1 + 8 ) - 60
= 112 - 243 : 9 - 60
= 121 - 243 : 9 - 60
= 121 - 27 - 60
= 34
^^ Cbht!!!
Tình GT của bt (Tính nhanh nếu có thể)
1) 13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 - 4 + 3 + 2 - 1
=13-(12+9-10-11)+(8+5-7-6)+(3+2-4-1)
=13+0+0+0=13
2) 49 - (-54) - 23
=49+54-23
=80
3) 100 + (-520) + 1140 + (-620)
=( 100+1140)+(-620)+-520)
= 100
a) 13 - 18 - (-42) - 15
=13-18+42-15
=22
TICK CHO
T
2017-{5^2.2^2-11[7^2-5.2^3+8(11^2-121)]}=
=2017-{25.4-11[49-5.8+8(121-121)]}=
= 2017-{100-11[49-40+0]}=2017-{100-11.9}=2017-1=2016
\(2017-\left\{5^2.2^2-11.\left[7^2-5.2^3+8\left(11^2-121\right)\right]\right\}\)\(=1017-\left\{100-11\left[49-40+8\left(121-121\right)\right]\right\}\)
\(=2017-\left\{100-11\left[9+8.0\right]\right\}\)
\(=2017-\left\{100-11.9\right\}\)
\(=2017-\left(100-99\right)=1017-1=2016\)
\(1)\frac{1}{5}+\frac{2}{11}< \frac{x}{55}< \frac{2}{5}+\frac{1}{55}\)
\(\Rightarrow\frac{11}{55}+\frac{10}{55}< \frac{x}{55}< \frac{22}{55}+\frac{1}{55}\)
\(\Rightarrow\frac{21}{55}< \frac{x}{55}< \frac{23}{55}\)
\(\Rightarrow21< x< 23\)
\(\Rightarrow x=22\)
\(2)\frac{11}{3}+\frac{-19}{6}+\frac{-15}{2}\le x\le\frac{19}{12}+\frac{-5}{4}+\frac{-10}{3}\)
\(\Rightarrow\frac{22}{6}+\frac{-19}{6}+\frac{-45}{6}\le x\le\frac{19}{12}+\frac{-15}{12}+\frac{-40}{12}\)
\(\Rightarrow\frac{22+\left[-19\right]+\left[-45\right]}{6}\le x\le\frac{19+\left[-15\right]+\left[-40\right]}{12}\)
\(=\frac{-42}{6}\le x\le\frac{-36}{12}\)
\(\Rightarrow-7\le x\le-3\)
\(\Rightarrow x\in\left\{-7;-6;-5;-4;-3\right\}\)
2x - 11 chia hết cho 3x + 2
=> 3( 2x - 11 ) chia hết cho 3x + 2
=> 6x - 33 chia hết cho 3x + 2
=> 2( 3x + 2 ) - 37 chia hết cho 3x + 2
=> 6x + 4 - 37 chia hết cho 3x + 2
=> 37 chia hết cho 3x + 2
=> 3x + 2 thuộc Ư(37) = { -37 ; -1 ; 1 ; 37 }
Ta có bảng sau :
3x+2 | -37 | -1 | 1 | 37 |
x | -13 | -1 | -1/3 | 35/3 |
Đề chưa xác định x thuộc gì nên để tạm vầy
a: \(=\left(15-6-\dfrac{13}{18}\right):\dfrac{298}{27}-\dfrac{17}{8}:\dfrac{51}{40}\)
\(=\dfrac{149}{18}\cdot\dfrac{27}{298}-\dfrac{5}{3}=\dfrac{3}{2}-\dfrac{5}{3}=\dfrac{9-10}{6}=\dfrac{-1}{6}\)
b: \(=\dfrac{-16}{5}\cdot\dfrac{-15}{64}+\dfrac{-22}{15}:\dfrac{11}{2}\)
\(=\dfrac{3}{4}-\dfrac{4}{15}=\dfrac{29}{60}\)
c: \(=\dfrac{-7}{9}\left(\dfrac{4}{11}+\dfrac{7}{11}\right)+5+\dfrac{7}{9}=\dfrac{-7}{9}+\dfrac{7}{9}+5=5\)
d: \(=\dfrac{1}{2}\cdot\dfrac{4}{3}\cdot10\cdot\dfrac{1}{5}\cdot\dfrac{3}{4}=1\)
e: \(=\dfrac{4}{25}+\dfrac{11}{2}\cdot\dfrac{5}{2}+\dfrac{-23}{4}=\dfrac{204}{25}\)