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Lời giải:
a.
$4(2x-4)+2=18$
$4(2x-4)=16$
$2x-4=16:4=4$
$2x=4+4=8$
$x=8:2$
$x=4$
b.
\(5^3+(18x-65).3=26^2+10\)
$125+3(18x-65)=686$
$3(18x-65)=686-125=561$
$18x-65=561:3=187$
$18x=187+65$
$18x=252$
$x=252:18=14$
c.
\(|x-10|+2^2.5=5^5\)
$|x-10|+20=3125$
$|x-10|=3125-20=3105$
$\Rightarrow x-10=3105$ hoặc $x-10=-3105$
$\Rightarrow x=3115$ hoặc $x=-3095$
d.
\((x-2)^2-2^3.5=104\)
$(x-2)^2-40=104$
$(x-2)^2=104+40=144=12^2=(-12)^2$
$\Rightarrow x-2=12$ hoặc $x-2=-12$
$\Rightarrow x=14$ hoặc $x=-10$

Ta có:
\(16^x<128^4\Rightarrow2^{4x}<2^{28}\Rightarrow4x=28\Rightarrow x=7\)
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}\Rightarrow5^{3x+3}\le5^{18}\Rightarrow3x+3\le18\Rightarrow x\le5\)


a) kết quả =77
b) kết quả =78
c) kết quả =4
d) kết quả 1953
a/ 6^2 : 4.3+2.5^2
=36:4.3 + 2.25
=27+50
=77
b/ 5.4^2 - 18:3^2
=5.16 - 18:9
=80-2
=78
c/ 80 - (4.5^2-3.2^3)
=80-(4.25 - 3.8)
=80- (100-24)
=80-76
=4
d/ 23.75+25+23+180
=1725+25+23+180
=1953

b)
\(5^x.5^{x+1}.5^{x+2}=5^x.5^x.5.5^x.5^2=5^{x+x+x+1+3}=5^{3x+3}\le10^{18}:2^{118}\)
\(=>5^{3x+3}\le5^{18}=>3x+3\le18=>x\le5=>x\in\left\{0;1;2;3;4;5\right\}\)
**** bn, câu a tự lm nhé

a, 32 x 35 + 32 x 65 b, 150 : [ 25 x ( 18- 42)]
= 32 x ( 35 +65) = 150 : [ 25 x ( 18-16)]
= 9 x 100 = 150 : ( 25 x 2)
= 900 = 150 : 50 = 3
c, 57 : 54 - 21 x 22
= 53- 2 x 4
= 125-8
=117
a) 3 ^ 2 x 35 + 3 ^ 2 x 65 = 9 x 35 + 9 x 65 = 9 x ( 65 + 35 ) = 9 x 100 = 900

a)2x+5-(x-7)=18
2x+5-x+7=18
2x-x+(5+7)=18
x+12=18
x=18-12
x=6
b)2(x+1)+4^2=2^4
2(x+1)+(2^2)^2=2^4
2(x+1)+2^4=2^4
2(x+1)=2^4-2^4
2(x+1)=0
x+1=0:2=0
x=0-1
x=-1
c) mk đang nghĩ tí mk gửi qua tin nhắn cho
a) \(2x+5-\left(x-7\right)=18\)
\(2x+5-x+7=18\)
\(2x-x=18-5-7\)
\(x=6\)
b) \(2\left(x+1\right)+4^2=2^4\)
\(2x+2+16=16\)
\(2x=16-16-2\)
\(2x=-2\)
\(x=-1\)
c) \(\frac{x-3}{x-5}=\frac{5}{7}\)
\(\left(x-3\right)\cdot7=\left(x+5\right)\cdot5\)
\(7x-21=5x+25\)
\(7x-5x=25+21\)
\(2x=46\)
\(x=\frac{46}{2}=23\)

a) \(\frac{18^4.3^2.8^3}{27^3.16^2}=\frac{\left(2.3^2\right)^4.3^2.\left(2^3\right)^3}{\left(3^3\right)^3.\left(2^4\right)^2}=\frac{2^4.2^9.3^8.3^2}{3^9.2^8}=\frac{2^{13}.3^{10}}{3^9.2^8}=3.2^5=96\)
b) \(\frac{35^5.9^3.8^5}{81^4.32^5}=\frac{35^5.\left(3^2\right)^3.\left(2^3\right)^5}{\left(3^4\right)^4.\left(2^5\right)^5}=\frac{35^5.3^6.2^{15}}{3^{16}.2^{25}}=\frac{35^5}{3^{10}.2^{10}}=\frac{35^5}{6^{10}}\)
c) \(\frac{48^5.18^2}{81^2.34^4}=\frac{\left(2^4.3\right)^5.\left(2.3^2\right)^2}{\left(3^4\right)^2.\left(2.17\right)^4}=\frac{2^{20}.3^5.2^2.3^4}{3^8.2^4.17^4}=\frac{2^{22}.3^9}{3^8.2^4.17^4}=\frac{2^{18}.3}{17^4}\)
d) \(\frac{54^7.27^3.16^2}{243^2.64^3}=\frac{\left(2.3^3\right)^7.\left(3^3\right)^3.\left(2^4\right)^2}{\left(3^5\right)^2.\left(2^6\right)^3}=\frac{2^7.3^{21}.3^9.2^8}{3^{10}.2^{18}}=\frac{2^{15}.3^{30}}{3^{10}.2^{18}}=\frac{3^{20}}{2^3}\)

2(5 x 42 - 18)
= 2( 5 . 16 - 18 )
= 2 . 62
= 124