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a) \(\frac{7^3.5^8}{49.25^4}=\frac{7^3.5^8}{7^2.\left(5^2\right)^4}=7.\frac{5^8}{5^8}=7\)
b) \(\frac{3^9.25.5^3}{15.625.3^8}=\frac{3.3^8.5^2.5^3}{3.5.5^4.3^8}=\frac{5^5}{5^5}=1\)
c) Đề hơi sai roi bạn oi
d) \(\left(\frac{2}{5}-\frac{1}{2}\right)^2+\left(\frac{1}{2}+\frac{3}{5}\right)^2=\left(\frac{-1}{10}\right)^2+\left(\frac{11}{10}\right)^2=\frac{1}{100}+\frac{121}{100}=\frac{61}{50}\)
Ta có: \(5^x+5^{x-1}=125\)
\(\Leftrightarrow5^{x-1}\left(5+1\right)=125\)
\(\Leftrightarrow5^{x-1}\cdot6=125\)
\(\Rightarrow5^{x-1}=\frac{125}{6}\)
\(\Leftrightarrow x-1\approx1,87\)
\(\Rightarrow x\approx2,87\)
Có vấn đề rồi đây
a) \(\left(\frac{1}{16}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2^4}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left[\left(\frac{1}{2}\right)^4\right]^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{4.25}\div\left(\frac{1}{2}\right)^{30}\)
\(=\left(\frac{1}{2}\right)^{100}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{100-30}=\left(\frac{1}{2}\right)^{70}\)
b) \(584^{100}\div292^{100}=\left(584-292\right)^{100}=292^{100}\)
c) \(125^4\cdot16^3=\left(5^3\right)^4\cdot\left(2^4\right)^3=5^{3\cdot4}\cdot2^{4\cdot3}=5^{12}\cdot2^{12}=\left(5+2\right)^{12}=7^{12}\)
a, (-0,2)2 \(\times\) 5 - \(\dfrac{2^{13}\times27^3}{4^6\times9^5}\)
= 0,04 \(\times\) 5 - \(\dfrac{2^{13}\times3^9}{2^{12}\times3^{10}}\)
= 0,2 - \(\dfrac{2}{3}\)
= \(\dfrac{2}{10}\) - \(\dfrac{2}{3}\)
= - \(\dfrac{7}{15}\)
b, \(\dfrac{5^6+2^2.25^3+2^3.125^2}{26.5^6}\)
= \(\dfrac{5^6+4.5^6+8.5^6}{26.5^6}\)
= \(\dfrac{5^6.\left(1+4+8\right)}{26.5^6}\)
= \(\dfrac{1}{2}\)
`@` `\text {Ans}`
`\downarrow`
`-125^4 \div 25^5`
`= (-5^3)^4 \div (5^2)^5`
`= -5^12 \div 5^10`
`= -5^2=-25`
\(#04052010\)
25²⁵ + 5⁴⁹ - 125¹⁶
= (5²)²⁵ + 5⁴⁹ - (5³)¹⁶
= 5⁵⁰ + 5⁴⁹ - 5⁴⁸
= 5⁴⁸.(5² + 5 - 1)
= 5⁴⁸.24