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a: =>x/3=-5/2
hay x=-15/2
b: \(\Leftrightarrow\dfrac{7}{3}:x=\dfrac{1}{5}-\dfrac{4}{9}=\dfrac{9-20}{45}=\dfrac{-11}{45}\)
\(\Leftrightarrow x=\dfrac{7}{3}:\dfrac{-11}{45}=\dfrac{7}{3}\cdot\dfrac{-45}{11}=\dfrac{-105}{11}\)
c: \(\Leftrightarrow x=\dfrac{-7}{2}\cdot2=-7\)
d: =>x/27=-1/3+2/9=2/9-3/9=-1/9=-3/27
=>x=-3
a) \(\dfrac{x}{48}=-\dfrac{4}{7}\Rightarrow x=-\dfrac{192}{7}\)
b) \(\left(x+\dfrac{4}{5}\right)-\dfrac{2}{5}=\dfrac{3}{5}\Rightarrow x+\dfrac{4}{5}=1\)
\(\Rightarrow x=\dfrac{1}{5}\)
c) \(2\left|x-1\right|^2=72\Rightarrow\left|x-1\right|^2=36\)
\(\Rightarrow\left|x-1\right|=6\)
TH1: x - 1 = -6 => x = -5
TH2: x - 1 = 6 => x = 7
e) \(\dfrac{x}{2,5}=\dfrac{4}{5}\Rightarrow x=2\)
f) | x - 2 | = 1 + 4 = 5
TH1: x - 2 = -5 => x = -3
TH2: x - 2 = 5 => x = 7
a) \(\dfrac{x}{48}=\dfrac{-4}{7}\)
⇒ x.7=48.(-4)
7x = -192
x=\(\dfrac{-192}{7}\) Vậy x=\(\dfrac{-192}{7}\)
b) \(\left(x+\dfrac{4}{5}\right)-\dfrac{2}{5}=\dfrac{3}{5}\)
\(\left(x+\dfrac{4}{5}\right)=\dfrac{3}{5}+\dfrac{2}{5}\)
\(x+\dfrac{4}{5}=1\)
\(x=1-\dfrac{4}{5}\)
\(x=\dfrac{1}{5}\)
c) chưa từng gặp dạng với giá trị tuyệt đối sory
d) \(\dfrac{1}{6}x-\dfrac{2}{3}=2\)
\(\dfrac{1}{6}x=2+\dfrac{2}{3}\)
\(\dfrac{1}{6}x=\dfrac{8}{3}\)
\(x=\dfrac{8}{3}:\dfrac{1}{6}\)
\(x=16\)
e) \(\dfrac{x}{2,5}=\dfrac{4}{5}\)
=> x.5 = 4.2,5
5x=10
x=10:5
x=2
f) |x-2|-4=1
|x-2|=1+4
|x-2|=5
=>\(\left[{}\begin{matrix}x-2=5\\x-2=-5\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=5+2\\x=-5+2\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=7\\x=-3\end{matrix}\right.\)
đôi khi cũng có sai sót , hãy xem lại thật kĩ
a, \(2,5:7,5=x:\dfrac{3}{5}\)
\(\Leftrightarrow x:\dfrac{3}{5}=2,5:7,5\)
=> \(x.7,5=\dfrac{3}{5}.2,5\) => \(x=\dfrac{1,5}{7,5}=\dfrac{1}{5}\)
b, \(2\dfrac{2}{3}:x=1\dfrac{7}{9}\)
=> \(x=2\dfrac{2}{3}:1\dfrac{7}{9}\)
=> \(x=\dfrac{3}{2}\)
c, \(\dfrac{5}{6}:x=20:3\)
=> \(x.20=\dfrac{5}{6}.3\) => \(x=\dfrac{2,5}{20}=\dfrac{1}{8}\)
3, Tìm x, biết:
a) 2,5 : 7,5 = x : \(\dfrac{3}{5}\)
=> \(x:\dfrac{3}{5}=\dfrac{1}{3}\)
=> \(x=\dfrac{1}{3}.\dfrac{3}{5}=>x=\dfrac{1}{5}\)
b) \(2\dfrac{2}{3}\) : x = \(1\dfrac{7}{9}\)
=> \(\dfrac{8}{3}:x=\dfrac{16}{9}\)
=> \(x=\dfrac{8}{3}:\dfrac{16}{9}=>x=\dfrac{3}{2}\)
c) \(\dfrac{5}{6}\) : x = 20 : 3
=> \(x=\dfrac{5}{6}:\dfrac{20}{3}=>x=\dfrac{1}{8}\)
Cái này chỉ cần làm quy tắc nhân chéo là ra rồi nhé :)
a) \(x=\dfrac{-2,6.42}{-12}\)=9,1
b) x = \(\dfrac{2,5.12}{1.5}\) = 20
c) Nhân chéo: 7.(x-1) = 6.(x+5)
<=> 7x - 7 = 6x +30
<=> 7x - 6x = 7 + 30 (chuyển vế)
-> x = 37
d) Nhân chéo: 25x2 = 24.6 = 144
x2 = \(\dfrac{144}{25}\)=5,76
-> x = \(\sqrt{5,76}\) = 2,4
e) Nhân chéo: (x-2)2 = 4.9 = 36
Ta dễ thấy (x-2)2 = 62
-> x-2 = 6 -> x = 6+2 = 8
TICK NHÉ :)
1.
\(\left(1-2x\right)^4=81\\ \Rightarrow\left[{}\begin{matrix}1-2x=3\\1-2x=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}-2x=2\\-2x=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)
Vậy ...
2.
\(\left|2,5-x\right|=1,3\\ \Rightarrow\left[{}\begin{matrix}2,5-x=1,3\\2,5-x=-1,3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1,2\\x=3,8\end{matrix}\right.\)
Vậy ...
3.
\(5^x+5^{x+2}=650\\ 5^x\left(1+5^2\right)=650\\ 5^x\cdot26=650\\ 5^x=25\\ x=2\)
Vậy ...
4, 5 tự làm
a , \(2x\left(x-\dfrac{1}{7}\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{7}\end{matrix}\right.\)
b , \(\left(x-1\right)^2=4\Leftrightarrow\left(x-1\right)^2-2^2=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=0\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
c , Ta có bảng xét dấu
x | - | 1,5 | 2,5 | + | |
x-1,5 | - | 0 | + | + | |
2,5-x | + | + | 0 | - |
*Th1 : x < 1,5
pt <=> 1,5-x+2,5-x=0 => x=2
* Th2 : \(1,5\le x\le2,5\)
pt <=> x-1,5 +2,5 - x = 0 => vô nghiệm
* Th3 : x > 2,5
pt <=> x-1,5 + x -2,5 = 0 => x = 2
Vậy x = 2 là giá trị cần tìm
d , Áp dụng tính chất dãy tỉ số bằng nhau , ta có :
\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{x+y}{2+5}=\dfrac{-21}{7}=-3\)
=> x = -3.2=-6
=> y = -3.5=-15
e, \(2^x+2^{x+3}=2^x\left(1+2^3\right)=2^x.9=144\)
=> \(2^x=16=>x=4\)
a) \(\frac{25^{7} . 125^{5}}{5^{28}}= \frac{5^{14}. 5^{15}}{5^{28}}= \frac{5^{29}}{5^{28}} = 5\)
b) \((2\tfrac{1}{4} + 2,5): (-3 \tfrac{1}{6} + 2\tfrac{1}{7})\)
= \(\left ( \frac{9}{4} + 2,5 \right )\) : \(\left (- \frac{19}{6} + \frac{15}{7} \right )\)
= \(\frac{-399}{86}\)
a) \(\dfrac{25^7.125^5}{5^{28}}=\dfrac{5^{14}.5^{15}}{5^{28}}=\dfrac{5^{29}}{5^{28}}=5\)
b) \((2\dfrac{1}{4}2,5):\left(-3\dfrac{1}{6}+2\dfrac{1}{7}\right)\)
\(=\left(\dfrac{9}{4}+\dfrac{5}{2}\right):\left(\dfrac{-19}{6}+\dfrac{15}{7}\right)\)
\(=\dfrac{19}{4}:\dfrac{-43}{42}=\dfrac{-399}{86}\)
\(2,5-\dfrac{1}{7}x=-2\)
\(\Rightarrow\dfrac{5}{2}-\dfrac{1}{7}x=-2\)
\(\Rightarrow\dfrac{1}{7}x=\dfrac{5}{2}-\left(-2\right)\)
\(\Rightarrow\dfrac{1}{7}x=\dfrac{9}{2}\)
\(\Rightarrow x=\dfrac{63}{2}\)