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\(7\left(x-9\right)=35\Leftrightarrow x-9=5\Leftrightarrow x=14\)
Câu 2: \(2^x=2^2\cdot2\Leftrightarrow2^x=2^3\Leftrightarrow x=3\)
Câu 3: \(2\cdot3^{x-1}=54\Leftrightarrow3^{x-1}=27\Leftrightarrow3^{x-1}=3^3\Leftrightarrow x-1=3\Leftrightarrow x=4\)
Câu 4: \(42-\left(2x+32\right)+12:2=6\)
\(\Leftrightarrow42-2x-32+6=6\)
\(\Leftrightarrow-2x=6-6+32-42=-10\)
\(\Leftrightarrow x=5\)
Cau 1: 7.(x-9)=35
x-9=35:7
x-9=5
x=5+9
x=14
Cau2: 2:2^x=2^2.2
2:2^x=8
2^x=8.2
2^x=16
=> x=4
1.4./x-5/-54=-34
4./x-5/=-34+54
4./x-5/=20
/x-5/=20:4
/x-5/=5
=>x-5=5 va x-5=-5
TH1:x-5=-5
=>x=0
TH2:x-5=5
=>x=10
2. /x-1/+(-5)=2
/x-1/=2-(-5)
/x-1/=7
=>x-1=7 va x-1=-7
TH1: x-1=7
=>x=8
TH2:x-1=-7
=>x=-6
vay x=-6 hoac x=8
a) 17.13+17.42-17.35
=17.(13+42-35)
=17.20=340
b) [25.(18-42)-10]:4+6
=(25.2-10):4+6
=40:4+6=16
c) 36:32+23.22-32.3
=34+25-33
=81+32-27=86
d) B=3.42-22.3
=3.(16-4)
=3.12=36
e)20220+3.[52.10-(23-13)2]
=1+3.(250-100)
=1+450=451
g) 27.77+24.27-27
=27.(77+24-1)
=27.100=2700
h) 5.23+79:77-12020
=40+72-1
=89-1=88
i) 120:{54[50:2+(32-2.4)]}
=120:[54(25+1)]
=120:1404=10/117
a) \(2^{2x}.2^4=1024\)
\(2^{2x}=1024:2^4\)
\(2^{2x}=1024:16\)
\(2^{2x}=64\)
\(2^{2x}=2^6\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=3\)
vay \(x=3\)
b) \(2.3^x=10.3^{12}+8.27^4\)
\(2.3^x=2.5.3^{12}+2^3.\left(3^3\right)^4\)
\(2.3^x=2.5.3^{12}+2^3.3^{12}\)
\(2.3^x=2.3^{12}.\left(5+2^2\right)\)
\(2.3^x=2.3^{12}.9\)
\(2.3^x=2.3^{12}.3^2\)
\(2.3^x=2.3^{14}\)
\(\Rightarrow x=14\)
vay \(x=14\)
c) \(5^8.25^x+1=5^{17}\)
\(5^8.\left(5^2\right)^x+1=5^{17}\)
\(5^8.5^{2x}+1=5^{17}\)
\(5^{8+2x}=5^{17}-1\)
e) \(\left(2x-4\right)^5=\left(2x-4\right)^3\)
\(\left(2x-4\right)^5-\left(2x-4\right)^3=0\)
\(\left(2x-4\right)\left[\left(2x-4\right)^2-1\right]=0\)
\(\left(2x-4\right)\left(2x-4-1\right)\left(2x-4+1\right)=0\)
\(\left(2x-4\right)\left(2x-5\right)\left(2x-3\right)=0\)
\(\Rightarrow2x-4=0\)hoac \(\orbr{\begin{cases}2x-5=0\\2x-3=0\end{cases}}\)
\(\Rightarrow2x=4\)hoac \(\orbr{\begin{cases}2x=5\\2x=3\end{cases}}\)
\(\Rightarrow x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
vay \(x=2\)hoac \(\orbr{\begin{cases}x=\frac{5}{2}\\x=\frac{3}{2}\end{cases}}\)
a) 54 + ( 218 - x ) = 735
218 - x = 735 - 34
218 - x = 701
x = 218 - 701
x = -483
b) 96 - 3 ( x + 1 ) = 42
3 ( x + 1 ) = 96 - 42
3 ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
c) 5 ( x + 35 ) 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
d) 12x - 33 = 32 . 32
12x - 33 = 9.9
12x - 33 = 81
12x = 81 + 33
12x = 114
x = 114 : 12
x = 9,5
a) 54+(218-x)=735
218-x=681
x=-463
b) 96-3(x+1)=42
3(x+1)=54
x+1=18
x=17
c) 5(x+35)=515
x+35=103
x=68
d) 12x-33=3^2.2^2
12x-33=81
12x = 114
x=9,5
Nhấn đúng cho mk nha!!!!!!!!
a. 2.3x = 10 . 312 + 8 . 274
2.3x = 10 . 312 + 8 . ( 33 )4
2.3x = 10 . 312 + 8 . 312
2.3x = 312 . ( 10 + 8 ) = 312 . 18
3x = 312 . 9
3x = 312 . 32
3x = 314 => x = 14
b. 64 . 4x = 45
43 . 4x = 45
43+x = 45
3 + x =5
x = 5 - 3 = 2
c. 2x = 4 . 128
2x = 22 . 27
2x = 29 => x = 9
d. Mik 0 bik làm do đề khó hiểu quá nhé!!! :))
e. ( x5 )10 = x
x50 = x
x50 - x = 0 => x . x49 - x = 0
x . ( x49 - 1 ) = 0
=> x = 0 hoặc x49 - 1 = 0
=> x = 0 hoặc x49 = 1 = 149
=> x = 0 hoặc x = 1
c) \(3^2+2^4-\left(6^8:6^6-6^2\right)< 5^x< 125\)
\(=9+16-\left(6^{8-6}-36\right)< 5^x< 5^3\)
\(=25-\left(6^2-36\right)< 5^x< 5^3\)
\(=25-\left(36-36\right)< 5^x< 5^3\)
\(=25-0< 5^x< 5^3\)
\(=25< 5^x< 5^3\)
\(=5^2< 5^x< 5^3\)
Vì \(5^2=25\) và \(5^3=125\) nên \(x\) không thể thỏa mãn đề bài
⇒ \(x\) không thỏa mãn đề bài
\(\left(2\cdot3^x-54\right)\div5+2^4=4^2\)
\(\left(2\cdot3^x-54\right)\div5+16=16\)
\(\left(2\cdot3^x-54\right)\div5=0\)
\(2\cdot3^x-54=0\)
\(2\cdot3^x=54\)
\(3^x=54\div2\)
\(3^x=27\)
\(3^x=3^3\)
=> x = 3
hok tốt