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a) \(96 : 2^4 + 3^2 - 2018^0 \)
= 96 : 16 + 9 - 1
= 6 + 9 - 1
= 15 - 1
= 14
b) 32 . 77 + 33 . 24 - 32
= 2541 + 768 - 32
= 3309 - 32
= 3327
c) \({2 . 3^2 + [144 - 5^2 . (15 - 169 : 13)]} - 1^2019\)
1^2019 nha bạn
= 2 . 9 + [144 - 25 . (15 - 169 : 13)]}- 1
= 2 . 9 + [144 - 25 . (15 - 13)]}- 1
= 2 . 9 + [144 - 25 . 2]}- 1
= 2 . 9 + [144 - 50]}- 1
= 2 . 9 + 94 - 1
= 18 + 94 - 1
= 112 - 1
= 111
d) 5^27 . 5 : 5^25 + -125 = 0
\(\left(2\cdot3^2+\left(144-5^2\cdot\left(15-169:13\right)\right)\right)-9999^0\)
\(=\left(2\cdot9+\left(144-25\cdot\left(15-13\right)\right)\right)-1\)
\(=\left(18+\left(144-25\cdot2\right)\right)-1\)
\(=\left(18+\left(144-50\right)\right)-1\)
\(=\left(18+94\right)-1\)
\(=112-1\)
\(=111\)
{2.9+[144-25x(15-169/13)}]-1
=2.9+[144-25.(15-13]]-1
=2.9+[144-25.2]]]-1
=2.9+[144-50]]]-1
=18+94-1
=111
Chúc bn học tốt
{2.9+[144-25x(15-169/13)]}-1
=2.9+[144-25.(15-13)]-1
=2.9+[144-50]-1
=18+94-1
=112-1
=111
\(C=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{870}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{29.30}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{29}-\frac{1}{30}\)
\(=1-\frac{1}{30}\)
\(=\frac{29}{30}\)
a)128-(x+56)=15
x+56=128-15
x+56=113
x=113-56
x=57
b)45+(34-x)=67
34-x=67-45=22
x=34-22
x=12
\(a)\) \(A=\frac{5\left(2^2.3^2\right)^9.\left(2^2\right)^6-2\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
\(A=\frac{2^{30}.3^{18}.5-2^{29}.3^{18}}{2^{28}.3^{18}.5-2^{29}.3^{18}.7}\)
\(A=\frac{2^{29}.3^{18}\left(2.5-1\right)}{2^{28}.3^{18}\left(5-2.7\right)}\)
\(A=\frac{2\left(10-1\right)}{5-14}\)
\(A=\frac{2.9}{-9}\)
\(A=-2\)
Vậy \(A=-2\)
\(b)\) \(B=81.\left[\frac{12-\frac{12}{7}-\frac{12}{289}-\frac{12}{85}}{4-\frac{4}{7}-\frac{4}{289}-\frac{4}{85}}:\frac{5+\frac{5}{13}+\frac{5}{169}+\frac{5}{91}}{6+\frac{6}{13}+\frac{6}{169}+\frac{6}{91}}\right].\frac{158158158}{711711711}\)
\(B=81.\left[\frac{12\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}{4\left(1-\frac{1}{7}-\frac{1}{289}-\frac{1}{85}\right)}:\frac{5\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}{6\left(1+\frac{1}{13}+\frac{1}{169}+\frac{1}{91}\right)}\right].\frac{158158158}{711711711}\)
\(B=81.\left[\frac{12}{4}:\frac{5}{6}\right].\frac{2}{9}\)
\(B=81.\frac{18}{5}.\frac{2}{9}\)
\(B=\frac{324}{5}\)
Vậy \(B=\frac{324}{5}\)
Chúc bạn học tốt ~ ( mỏi tay qué >_< )
1: 8=2^3
2: 25=5^2
3: 4=2^2
4: 49=7^2
5: 81=9^2
6: 36=6^2
7: 100=10^2
8: 121=11^2
9: 144=12^2
10: 169=13^2
11: 27=3^3
12: 125=5^3
13: 1000=10^3
14: 32=2^5
15: 243=3^5
16: 343=7^3
17: 216=6^3
18: 64=4^3
19: 225=15^2
20: 128=2^7
{ 2 . 32 + [ 144 - 52 . ( 15 - 169 : 13 ) ] } - 12019
= { 2 . 9 + [ 144 - 25 . ( 15 - 13 ) ] } - 1
= { 18 + [ 144 - 25 . 2 ] } - 1
= { 18 + [ 144 - 50 ] } - 1
= 18 + 94 - 1
= 112 - 1
= 111
{2 . 3^2 + (144 - 5^2 . (15 - 169 : 13))} - 1^2019
= {2 . 9 + (144 - 25 . ( 15 - 169 : 13))} - 1
= {2 . 9 + (144 - 25 . ( 15 - 13))} - 1
= {2 . 9 + (144 - 25 . 2)} - 1
= {2 . 9 + (144 - 50)} - 1
= {2 . 9 + 94} - 1
= {18 + 94} - 1
= 112 - 1
= 111