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\(0,2:\frac{6}{5}=\frac{2}{3}:\left(6x+7\right)\)
=> \(\frac{0,2.5}{6}=\frac{2}{3\left(6x+7\right)}\)
=> \(\frac{1}{6}=\frac{2}{18x+21}\)
=> 18x + 21 = 12
=> 18x = -9
=> x = -0.5
Vậy x = -0,5
\(0,2:\frac{6}{5}=\frac{2}{3}:\left(6x+7\right)\)
\(\Rightarrow0,2.\frac{5}{6}=\frac{2}{3}.\frac{1}{6x+7}\)
\(\Rightarrow\frac{1}{6}=\frac{2}{3}.\frac{1}{\left(6x+7\right)}\)
\(\Rightarrow\frac{1}{4}=\frac{1}{\left(6x+7\right)}\)
\(\Rightarrow4=6x+7\)
\(\Rightarrow x=-\frac{1}{2}\)
0,2:1 1/5 = 2/3 : (6x + 7)
0,2:6/5 = 2/3 : (6x+7)
1/6 = 2/3 : (6x + 7 )
6x + 7 = 2/3 : 1/6
6x + 7 = 4
6x = 4 - 7 = - 3
x = -3 : 6
x = -1/2
e) \(2^x+2^{x+3}=144\)
\(\Leftrightarrow2^x+2^x.2^3=144\)
\(\Leftrightarrow2^x.\left(1+8\right)=144\)
\(\Leftrightarrow2^x.9=144\)
\(\Rightarrow2^x=144:9=16\)
Ta có :\(2^4=16\Rightarrow x=4\)
l)\(0,2:1\frac{1}{5}=\frac{2}{3}:\left|6x+7\right|\)
\(\Leftrightarrow\frac{2}{3}:\left|6x+7\right|=\frac{1}{6}\)
\(\Rightarrow\left|6x+7\right|=\frac{2}{3}:\frac{1}{6}\)
\(\Rightarrow\left|6x+7\right|=4\)
\(\Rightarrow\orbr{\begin{cases}6x+7=4\\6x+7=-4\end{cases}\Rightarrow\orbr{\begin{cases}6x=-3\\6x=-11\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{1}{2}\\x=-\frac{11}{6}\end{cases}}}\)
Eh, cho mk sửa: dấu chấm phẩy là mk viết nhầm phải là dấu Chia
a)\(\dfrac{0,4}{x}=\dfrac{x}{0,9}\Rightarrow x^2=0,4.0,9=0,36\Rightarrow x=0,6;-0,6\)
\(b)\dfrac{0,2}{1\dfrac{1}{5}}=\dfrac{\dfrac{2}{3}}{6x+7}\Rightarrow6x+7=\dfrac{1\dfrac{1}{5}.\dfrac{2}{3}}{0,2}=4\Rightarrow6x=-3\Rightarrow x=-\dfrac{3}{6}=-\dfrac{1}{2}\)
c)\(\dfrac{13\dfrac{1}{3}}{1\dfrac{1}{3}}=\dfrac{26}{2x+1}\Rightarrow2x+1=\dfrac{1\dfrac{1}{3}.26}{13\dfrac{1}{3}}=2,6\Rightarrow2x=1,6\Rightarrow x=0,8\)
d) mk ko hiểu
e)\(\dfrac{-2,6}{x}=\dfrac{-12}{42}\Rightarrow x=\dfrac{-2,6.42}{-12}=9,1\)
f)\(\dfrac{x^2}{6}=\dfrac{24}{25}\Rightarrow x^2=\dfrac{6.24}{25}=5,76\Rightarrow x=-2,4;2,4\)
n)mk chịu thua
xin lỗi bạn nha
\(\frac{2}{3}:\left|6x+7\right|=0,2:\frac{6}{5}\)
\(\frac{2}{3}:\left|6x+7\right|=\frac{1}{6}\)
\(\left|6x+7\right|=\frac{2}{3}:\frac{1}{6}\)
\(\left|6x+7\right|=4\)
\(\Rightarrow\)6x + 7 = 4 hoặc 6x + 7 = -4
TH1 : 6x + 7 = 4
6x = 4 - 7
6x = -3
x = -3 : 6
x = -0,5.
TH2 : 6x + 7 = -4
6x = -4 - 7
6x = -11
x = -11 : 6
x = \(\frac{-11}{6}\)
Vậy x = -0,5 hoặc x = \(\frac{-11}{6}\).