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14 tháng 10 2020
\(177:\left[2.\left(4^2-9\right)+3^2.\left(15-10\right)\right]\)
\(=177:\left[2.\left(16-9\right)+3^2.5\right]\)
\(=177:\left[2.7+9.5\right]\)
\(=177:\left[14+45\right]\)
\(=177:59=3\)
\(\frac{11^{26}}{11^{23}}-\frac{3^5}{\left(1^{2020}+2^3\right)-60}\)
\(=11^3-\frac{243}{\left(1+8\right)-60}\)
\(=1331-\frac{243}{-51}=1331-\frac{-81}{17}\)
\(=1331+\frac{81}{17}\)
\(=\frac{22708}{17}\)
AH
16 tháng 8 2016
a ) 123 - 5 . ( x - 4 ) = 38
5 . ( x - 4 ) = 85
x - 4 = 17
x = 21
b ) 2 . x - 183 = 2 ^ 3 . 3 ^ 2
2 . x - 183 = 72
2 . x = 255
x = 127 , 5
c ) 10 + 2 . x = 4 ^ 5 . 4 ^ 3
10 + 2 .x = 65536
2 . x = 65526
x = 32763
d ) 25 + ( 177 - x ) = 3 ^ 2 . 2 ^ 2
25 + ( 177 - x ) = 36
177 - x = 11
x = 166
LM
Lê Minh Vũ
CTVHS
14 tháng 6 2023
\(\left(-\dfrac{1}{2}\right)^2\div\dfrac{1}{4}-2\times\left(-\dfrac{1}{2}\right)^2\\= \dfrac{1}{4}\div\dfrac{1}{4}-2\times\dfrac{1}{4}\\ =1-\dfrac{1}{2}\\ =\dfrac{1}{2}\)
\(\left(-2\right)^3\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right)\div\dfrac{5}{12}\)
= \(-6\times-\dfrac{1}{24}+\left(\dfrac{4}{3}-\dfrac{11}{6}\right)\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{1}{2}\div\dfrac{5}{12}\)
= \(\dfrac{1}{4}+-\dfrac{6}{5}\)
= \(\dfrac{1}{4}-\dfrac{6}{5}\)
= \(-\dfrac{19}{20}\)
\(\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\\ =\dfrac{58}{9}+\dfrac{7}{11}-\dfrac{40}{9}+\dfrac{26}{11}\\ =\dfrac{58}{9}-\dfrac{40}{9}+\dfrac{7}{11}+\dfrac{26}{11}\\ =12+3\\ =15\)
TA
14 tháng 6 2023
\(a,\left(\dfrac{-1}{2}\right)^2:\dfrac{1}{4}-2\left(-\dfrac{1}{2}\right)^2\)
\(=\left(-\dfrac{1}{2}\right)^2\left(4-2\right)\)
\(=\dfrac{1}{4}.2=\dfrac{1}{2}\)
\(b,\left(-2\right)^3.\dfrac{-1}{24}+\left(\dfrac{4}{3}-1\dfrac{5}{6}\right):\dfrac{5}{12}\)
\(=\left(-8\right).\dfrac{-1}{24}+\left(-\dfrac{1}{2}\right).\dfrac{12}{5}\)
\(=\dfrac{1}{3}+\left(-\dfrac{1}{5}\right)=\dfrac{2}{15}\)
\(c,\left(6\dfrac{4}{9}+\dfrac{7}{11}\right)-\left(4\dfrac{4}{9}-2\dfrac{4}{11}\right)\)
\(=\dfrac{701}{99}-\dfrac{206}{99}=\dfrac{495}{99}=5\)
\(d,10\dfrac{1}{5}-5\dfrac{1}{2}.\dfrac{60}{11}+\dfrac{3}{15\%}\)
\(=\dfrac{51}{5}-30+20=\dfrac{1}{5}\)
\(e,\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}.\left(-\dfrac{7}{11}\right)\)
\(=-\dfrac{5}{11}\)
\(f,\dfrac{-5}{7}.\dfrac{2}{11}+\left(-\dfrac{5}{7}\right).\dfrac{9}{11}+1\dfrac{5}{7}\)
\(=\left(-\dfrac{5}{7}\right)\left(\dfrac{2}{11}+\dfrac{9}{11}\right)+\dfrac{12}{7}\)
\(=\left(-\dfrac{5}{7}\right)+\dfrac{12}{7}=1\)
TT
2
11 tháng 2 2022
1: =1/5-1/4=-1/20
2: =6/8-7/8=-1/8
3: =11/18-14/18=-3/18=-1/6
4: =-28/210+90/210+28/210=3/7
5: =-8/17-34/17=-42/17
SS
11 tháng 2 2022
1)\(\dfrac{1}{5}+\dfrac{-1}{-4}=\dfrac{4}{20}+\dfrac{5}{20}=\dfrac{9}{20}\)
\(\)2)\(\dfrac{3}{4}+\dfrac{-7}{8}=\dfrac{6}{8}+\dfrac{-7}{8}=\dfrac{-1}{8}\)
3)\(\dfrac{11}{18}+\dfrac{-7}{9}=\dfrac{11}{18}+\dfrac{-14}{18}=\dfrac{-3}{18}=\dfrac{-1}{6}\)
4)\(\dfrac{2}{-15}+\dfrac{3}{7}+\dfrac{-4}{-30}=\dfrac{-2}{15}+\dfrac{2}{15}+\dfrac{3}{7}=0+\dfrac{3}{7}=\dfrac{3}{7}\)
5)\(\dfrac{8}{-17}+\left(-2\right)=\dfrac{-8}{17}+\dfrac{-34}{17}=\dfrac{-42}{17}\)
21 tháng 4 2019
a,\(\frac{1}{2}+\frac{3}{4}-\frac{3}{4}+\frac{4}{5}\)
=\(\frac{1}{2}+\frac{3}{4}+\frac{-3}{4}+\frac{4}{5}\)
=\(\left(\frac{3}{4}+\frac{-3}{4}\right)+\frac{1}{2}+\frac{4}{5}\)
= \(0+\frac{1}{2}+\frac{4}{5}=\frac{13}{10}\)
Nhiều quá bạn ơi
9 tháng 5 2020
-4/5 + 11/3 - 9/10 =(-4/5 + 11/3) -9/10 =43/15 -9/10 =59/30 5/6 + -7/15 - 13/30 =(5/6 + -7/15) -13/30 =11/30 - 13/30 =-1/15 CHÚC EM HỌC TỐT ^_^
Lời giải:
$2,2.\frac{15}{177}-\frac{3}{4}+\frac{1}{5}: \frac{23}{2}$
$=\frac{11}{59}-\frac{3}{4}+\frac{4}{115}$
$=-0,529$