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Dấu " / " là phân số nhé
a) 5/-4 . 16/25 + -5/4 . 9/25
= -5/4 . 16/25 + -5/4 . 9/25
= -5/4 . ( 16/25 + 9/25 )
= -5/4 . 1
= -5/4
b) 4 11/23 - 9/14 + 2 12/23 - 5/4
= 103/23 - 9/14 + 58/23 - 5/4
= 103/23 + 58/23 - 9/14 - 5/4
= 7 - 9/14 - 5/4
= 143/28
c) 2 13/27 - 7/15 + 3 14/27 - 8/15
= 67/27 - 7/15 + 95/27 - 8/15
= 67/27 + 95/27 - 7/15 - 8/15
= 6 - 7/15 - 8/15
= 5
A= \(\frac{1^2}{1.2}\). \(\frac{2^2}{2.3}\). \(\frac{3^2}{3.4}\). \(\frac{4^2}{5.6}\).
A= \(\frac{1.1}{1.2}\). \(\frac{2.2}{2.3}\). \(\frac{3.3}{3.4}\). \(\frac{4.4}{4.5}\).
A= \(\frac{1.2.3.4}{1.2.3.4}\). \(\frac{1.2.3.4}{2.3.4.5}\).
A= 1. \(\frac{1}{5}\).
A= \(\frac{1}{5}\).
Vậy A= \(\frac{1}{5}\).
B= \(\frac{3}{4}\). \(\frac{8}{9}\). \(\frac{15}{16}\)..... \(\frac{899}{900}\).
B= \(\frac{1.3}{2.2}\). \(\frac{2.4}{3.3}\). \(\frac{3.5}{4.4}\)..... \(\frac{29.31}{30.30}\).
B= \(\frac{1.2.3.....29}{2.3.4.....30}\). \(\frac{3.4.5.....31}{2.3.4.....30}\).
B= \(\frac{1}{30}\). \(\frac{31}{2}\).
B= \(\frac{31}{60}\).
Vậy B= \(\frac{31}{60}\).
2: \(=234+29-80+52^3=140791\)
3: \(=45\cdot\left(3250-225\right)=45\cdot3025=136125\)
4: \(=\left[\left(192-3\right):3\right]^2=63^2=3969\)
Các bạn ơi,mình ghi thiếu,còn 3 câu nữa nha!!!~~nya
e)| \(\dfrac{5}{2}\)x-\(\dfrac{1}{2}\) |-(-22).\(\dfrac{1}{3}\)(0,75-\(\dfrac{1}{7}\))=\(\dfrac{-5}{13}\):2\(\dfrac{9}{13}\)-0,5.(\(\dfrac{-2}{3}\))
f)| 5x+21 | = | 2x -63 |
g) -45 - |-3x-96 | - 54=-207
Làm ơn giúp mình với ạ!Mình đang cần gấp lắm trong ngày hôm nay ạ!!!Mình xin cảm ơn các bạn nhiều nhiều lắm luôn đó!!!Thank you very much!!!(^-^)
a, (\(\dfrac{2}{9}\)(6x - \(\dfrac{3}{4}\)) - 3(\(\dfrac{1}{4}x-\dfrac{1}{5}\)) = \(\dfrac{-8}{15}\)
<=> (\(\dfrac{4}{3}x-\dfrac{1}{6}\)) - (\(\dfrac{3}{4}x-\dfrac{3}{5}\)) = \(\dfrac{-8}{15}\)
<=> \(\dfrac{4}{3}x-\dfrac{1}{6}-\dfrac{3}{4}x+\dfrac{3}{5}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x+\dfrac{13}{30}=\dfrac{-8}{15}\)
<=> \(\dfrac{7}{12}x=\dfrac{-8}{15}-\dfrac{13}{30}\)
<=> \(\dfrac{7}{12}x=-\dfrac{29}{30}\)
<=> x = \(-\dfrac{58}{35}\)
@Nguyễn Gia Hân
15: \(\Leftrightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-63\right]^3-48\right\}=1\)
\(\Leftrightarrow x^2-48=1\)
=>x=7 hoặc x=-7
Tìm x biết:
5) {x\(^2\) - [16\(^2\) - ( 8\(^2\) - 9 . 7)\(^3\) - 17 . 15 ]\(^3\) - 5 . 3 ]\(^3\) = 1
\(\left\{x^2-\left[16^2-\left(8^2-9.7\right)^3-17.15\right]^3-5.3\right\}^3=1\)
\(\left\{x^2-\left[256-\left(64-9.7\right)^3-17.15\right]^3-5.3\right\}^3=1\)
\(\left\{x^2-\left[256-1^3-255\right]^3-15\right\}^3=1\)
\(\left\{x^2-\left[255-255\right]^3-15\right\}^3=1\)
\(\left\{x^2-0^3-15\right\}^3=1\)
\(\left\{x^2-15\right\}^3=1\)
\(\left\{4^2-15\right\}^3=1\)
\(\Rightarrow x=4\)
5: \(\Leftrightarrow\left\{x^2-\left[256-\left(64-63\right)^3-255\right]^3-15\right\}^3=1\)
\(\Leftrightarrow\left\{x^2-15\right\}^3=1\)
\(\Leftrightarrow x^2-15=1\)
=>x=4 hoặc x=-4
a)\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.....\frac{9999}{10000}=\)\(\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.....\frac{99.101}{100.100}=\frac{101}{2.100}=\frac{101}{200}\)
b)\(\frac{8}{9}.\frac{15}{16}.\frac{24}{25}.....\frac{3599}{3600}=\frac{2.4}{3.3}.\frac{3.5}{4.4}.\frac{4.6}{5.6}.....\frac{59.61}{60.60}=\frac{2.61}{60}=\frac{61}{30}\)
\(\left(2^{15}+8^4\right):\left(16^3+2^9\right)\)
= \(\left(32768+4096\right):\left(4096+512\right)\)
= \(36864:4608\)
= \(8\)
( 215 + 84 ) : ( 163 + 29 )
= \(\dfrac{2^{15}+8^4}{16^3+2^9}=\dfrac{2^{15}+2^{12}}{2^{12}+2^9}\)
Thay dấu cộng thành dấu nhân đề bài mới có thể được thực hiện