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Ta có:\(A=2^{2019}-2^{2018}-....-2^2-2\)
\(=2^{2019}-\left(2^{2018}+2^{2017}+....+2^2+2\right)\)
Xét \(M=2^{2018}+2^{2017}+...+2^2+2\)
\(\Rightarrow2M=2^{2019}+2^{2018}+...+2^3+2^2\)
\(\Rightarrow2M-M=\left(2^{2019}+2^{2018}+...+2^3+2^2\right)-\left(2^{2018}+2^{2017}+...+2^2+2\right)\)
\(\Rightarrow M=2^{2019}-2\)
\(\Rightarrow A=2^{2019}-\left(2^{2019}-2\right)\)
\(\Rightarrow A=2\)
Chắc là thế,cũng chẳng biết đúng hay sai
1. 20182 - 2017.2019 = 20182 - ( 2018 - 1 )( 2018 + 1 ) = 20182 - ( 20182 - 12 ) = 20182 - 20182 + 12 = 1
2. 20012 = ( 2000 + 1 )2 = 20002 + 2.2000.1 + 12 = 4 000 000 + 4000 + 1 = 4 004 001
3. 19992 = ( 2000 - 1 )2 = 20002 - 2.2000.1 + 12 = 4 000 000 - 4000 + 1 = 3 996 001
4. 113 = ( 10 + 1 )3 = 103 + 3.102.1 + 3.10.12 + 13 = 1000 + 300 + 30 + 1 = 1331
5. 193 = ( 20 - 1 )3 = 203 - 3.202.1 + 3.20.1 - 13 = 8000 - 1200 + 60 - 1 = 6859
6. 57.63 = ( 60 - 3 )( 60 + 3 ) = 602 - 32 = 3600 - 9 = 3591
7. 953 + 3.952.5 + 3.95.52 + 53 = ( 95 + 5 )3 = 1003 = 1 000 000
\(2020^2-2019^2+2018^2-2017^2+...+2^2-1^2\)
\(=\left(2020-2019\right)\left(2020+2019\right)+\left(2018-2017\right)\left(2018+2017\right)++\left(2-1\right)\left(2+1\right)\)
\(=2019+2018+2017+...+2+1\)
\(=\frac{\left(2019+1\right)2019}{2}\)
\(=2039190\)
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Bài 2: Rút gọn biểu thức sau một cách nhanh nhất:
a, A=(6x-2)2+(2-5x)2+2.(6x-2)(2-5x)
\(=\left(6x-2\right)^2+2\left(6x-2\right)\left(2-5x\right)+\left(2-5x\right)^2\)
\(\text{(Hằng đẳng thức số 2)}\)
\(=\left(6x-2+2-5x\right)\)
\(=x\)
\(B=\left(2a^2+2a+1\right)\left(2a^2-2a+1\right)-\left(2a^2+1\right)^2\)
\(=\left(2a^2+1+2a\right)\left(2a^2+1-2a\right)-\left(2a^2+1\right)^2\)
\(=\left(2a^2+1\right)^2-4a^2-\left(2a^2+1\right)^2\)
\(=-4a^2\)
12 - 22 + 32 - 42 + .... + 20152 - 20162 + 20172
= (1 - 2)(1 + 2) + (3 - 4)(3 + 4) + .... + (2015 - 2016)(2015 + 2016) + 20172
= - 1.(1 + 2) - 1(3 + 4) - .... - 1.(2015 + 2016) + 20172
= - 1(1 + 2 + 3 + .... + 2015 + 2016) + 20172
\(=-\frac{2016.2017}{2}+2017\)
= - 2031119
\(B=2016^2+2017^2-2\\ B=2016^2-1+2017^2-1\\ B=\left(2016-1\right)\left(2016+1\right)+\left(2017-1\right)\left(2017+1\right)\\ B=2015.2017+2016.2018=A\)
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= (2019 - 2018)(2019 + 2018) + (2017 - 2016)(2017 + 2016) + ... + (3-2)(3+2) + 1
= 4037 + 4033 + ... + 5 + 1
= \(\left[\frac{4037-1}{4}+1\right]\left(4037+1\right):2\) =2039190