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2 tháng 7 2015

\(2.3^x+3^{x-1}=7\left(3^2+2.6^2\right)\Leftrightarrow2.3.3^{x-1}+3^{x-1}=7.81\)

\(\Leftrightarrow7.3^{x-1}=7.3^4\Leftrightarrow3^{x-1}=3^4\Leftrightarrow x-1=4\Leftrightarrow x=5\)

 

\(7^{x+2}+2.7^{x-1}=345\Leftrightarrow7^3.7^{x-1}+2.7^{x-1}=345\)\(\Leftrightarrow345.7^{x-1}=245\Leftrightarrow7^{x-1}=1=7^0\Leftrightarrow x-1=0\Leftrightarrow x=1\)

 

Bài 1: 

a) Ta có: \(-ax\left(xy^3\right)^2\cdot\left(-by\right)^3\)

\(=-a\cdot x\cdot x^2\cdot y^6\cdot\left(-b\right)^3\cdot y^3\)

\(=abx^3y^9\)

b) Ta có: \(xy\cdot\left(-ax\right)^2\cdot\left(-by\right)^3\)

\(=xy\cdot a^2\cdot x^2\cdot b^3\cdot y^3\)

\(=a^2b^3x^3y^4\)

Bài 2: 

Ta có: \(P\left(x\right)=5x-4x^4+x^6+3-2x^3-7x-x^7+1-2x^6+3x^3+x^7\)

\(=\left(-x^7+x^7\right)+\left(x^6-2x^6\right)-4x^4+\left(-2x^3+3x^3\right)+\left(5x-7x\right)+\left(3+1\right)\)

\(=-x^6-4x^4+x^3-2x+4\)

5 tháng 3 2019

1. f(x) = -3x4 + 5x3 + 2x2 - 7x + 7 tại x = 1; 0; 2

xét x=1 có f(x) =-3.14 +5.13 +2.12-7.1+7

=-3.1+5.1+2.1-7+7

=-3+5+2-7+7

=4

xét x=0 có f(x) =-3.04 +5.03 +2.02-7.0+7

=0+0+0-0+7=7

xét x=2 có f(x) =-3.24 +5.23 +2.22-7.2+7

=-3.16+5.8+2.4-14+7

=48+40+8-14+7

=89

2. g(x) = x4 - 5x3 + 7x2 + 15x + 2 tại x = -1; 0; 1; 2

xét x=-1 có: g(x)=(-1)4-5.(-1)3+7.(-1)2+15.(-1)+2

=1-5.(-1)+7.1-15+2

=1-(-5)+7-15+2

=1+5+7-15+2=0

xét x=0 có: g(x)=04-5.03+7.02+15.0+2

=0-0+0+0+2+2=2

xét x=1 có: g(x)=14-5.13+7.12+15.1+2

=1-5.1+7.1-15+2

=1-5+7-15+2

=1-5+7-15+2=-10

xét x=2 có: g(x)=24-5.23+7.22+15.2+2

=32-5.8+7.4-30+2

=32-40+28-30+2

=-8

3. h(x) = -x4 + 3x3 + 2x2 - 5x + 1 tại x = -2; -1; 1; 2

xét x=-2có:h(X)=-(-2)4 + 3(-2)3 + 2.(-2)2 - 5.(-2) + 1

=-(32)+3.(-8)+2.4+10+1

=-32-24+8+10+1

=-37

xét x=2có:h(X)=-(2)4 + 3.23 + 2.22 - 5.2 + 1

=-(32)+3.8+2.4+10+1

=-32+24+8+10+1

=11

xét x=1có:h(X)=14 + 3.13 + 2.12 - 5.1 + 1

=1+3.1+2.1+5+1

=1+3+2+5+1

=13

xét x=-1có:h(X)=-14 + 3.(-1)3 + 2.(-1)2 - 5.(-1) + 1

=1+3.(-1)+2.(-1)+5+1

=1-3-2+5+1

=2

4. r(x) = 3x4 + 7x3 + 4x2 - 2x - 2 tại x = -1; 0; 1

xét x=-1có:r(X)= 3(-1)4 + 7(-1)3 + 4(-1)2 - 2(-1)- 2

= 3.1+7.(-1) +4.1+2-2

=3-7+4+2-2

= 0

xét x=0có:r(X)= 3.04 + 7.03 + 4.02 - 2.0- 2

= 0+0+0-0-2

= -2

xét x=1có:r(X)= 3(1)4 + 7(1)3 + 4(1)2 - 2(1)- 2

= 3.1+7.1 +4.1-2-2

=3+7+4-2-2

= 10

22 tháng 6 2019

a) \(f\left(x\right)=5x^3-7x^2+2x+5\)

\(\Rightarrow f\left(1\right)=5.1^3-7.1^2+2.1+5\)

\(\Rightarrow f\left(1\right)=5.1-7.1+2+5\)

\(\Rightarrow f\left(1\right)=5-7+7\)

\(\Rightarrow f\left(1\right)=5\)

Vậy f(1) = 5.

\(g\left(x\right)=7x^3-7x^2+2x+5\)

\(\Rightarrow g\left(\frac{1}{2}\right)=7.\left(\frac{1}{2}\right)^3-7.\left(\frac{1}{2}\right)^2+2.\frac{1}{2}+5\)

\(\Leftrightarrow g\left(\frac{1}{2}\right)=7.\frac{1}{8}-7.\frac{1}{4}+1+5\)

\(\Leftrightarrow g\left(\frac{1}{2}\right)=\frac{7}{8}-\frac{14}{8}+6\)

\(\Leftrightarrow g\left(\frac{1}{2}\right)=\frac{-7}{8}+\frac{48}{8}\)

\(\Leftrightarrow g\left(\frac{1}{2}\right)=\frac{41}{8}\)

Vậy \(g\left(\frac{1}{2}\right)=\frac{41}{8}\)

22 tháng 6 2019

\(h\left(x\right)=2x^3+4x+1\)

\(\Rightarrow h\left(0\right)=2.0^3+4.0+1\)

\(\Rightarrow h\left(0\right)=0+0+1\)

\(\Rightarrow h\left(0\right)=1\)

Vậy \(h\left(0\right)=1\)

a) Ta có: \(5x\left(\frac{1}{5}x-2\right)+3\left(6-\frac{1}{3}x^2\right)=12\)

\(\Leftrightarrow x^2-10x+18-x^2=12\)

\(\Leftrightarrow-10x+18=12\)

\(\Leftrightarrow-10x=-6\)

hay \(x=\frac{3}{5}\)

Vậy: \(x=\frac{3}{5}\)

b) Ta có: \(7x\left(x-2\right)-5\left(x-1\right)=7x^2+3\)

\(\Leftrightarrow7x^2-14x-5x+5-7x^2-3=0\)

\(\Leftrightarrow-19x+2=0\)

\(\Leftrightarrow-19x=-2\)

hay \(x=\frac{2}{19}\)

Vậy: \(x=\frac{2}{19}\)

\(2\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)

\(\Leftrightarrow3-2x-\frac{1}{3}=7x-\frac{1}{4}\)

\(\Leftrightarrow-2x+\frac{8}{3}=7x-\frac{1}{4}\)

\(\Leftrightarrow\frac{1}{4}+\frac{8}{3}=7x+2x\)

<=> 9x = 35/12

=> x = 35/12 . 1/9 = 35/108