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1) (-1)3 + (-2)3 + (-3)3 - |x+5| = (5 - 6 -7)3
(-1) -8 - 27 - |x+5| = -512
|x+5| = 476
=> x + 5 = 476 hoặc x + 5 = -476
=> x = 472 => x = -481
Vậy....
2) [(x-3)2 - 9] . [(x-1)2-1]=0
( x - 3 - 3).(x - 3 + 3).(x - 1 - 1).(x - 1 +1) =0
( x - 6) . (x - 0) . (x - 2) . (x - 0) = 0
=> x - 6 = 0 hoặc x - 0 = 0 hoặc x - 2 = 0
=> x = 6 => x = 0 => x = 2
Vậy...
\(a,-12\left(x-5\right)+7\left(3-x\right)=5\)
\(-12x+60+21-7x=5\)
\(-12x-7x+81=5\)
\(-19x=5-81\)
\(-19x=-76\)
\(x=-76:\left(-19\right)\)
\(x=4\)
\(Vậyx=4\)
\(b,30\left(x+2\right)-6\left(x-5\right)-24x=100\)
\(30x+60-6x-30-24x=100\)
\(30x-6x-24x+60-30=100\)
\(0x+30=100\)
\(\Rightarrow Vôlý\)
Vậy không có giá trị nào của x thỏa mãn đề bài.
\(c,-5\left(x+\frac{1}{5}\right)-\frac{1}{2}\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-1-\frac{1}{2}x-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(-5x-\frac{1}{2}x-1-\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(-\frac{11}{2}x-\frac{2}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(-\frac{2}{3}+\frac{5}{6}=\frac{3}{2}x+\frac{11}{2}x\)
\(-\frac{4}{6}+\frac{5}{6}=\frac{14}{2}x\)
\(\frac{1}{6}=7x\)
\(x=\frac{1}{6}:7\)
\(x=\frac{1}{6}.\frac{1}{7}\)
\(x=\frac{1}{42}\)
\(Vậyx=\frac{1}{42}\)
\(d,-3\left(x-\frac{1}{2}\right)-5\left(x+\frac{3}{5}\right)=-x+\frac{1}{5}\)
\(-3x+\frac{3}{2}-5x-3=-x+\frac{1}{5}\)
\(-3x-5x+\frac{3}{2}-3=-x+\frac{1}{5}\)
\(-8x+\frac{3}{2}-\frac{6}{2}=-x+\frac{1}{5}\)
\(-8x-\frac{3}{2}=-x+\frac{1}{5}\)
\(-\frac{3}{2}-\frac{1}{5}=-x+8x\)
\(\frac{15}{10}-\frac{2}{10}=7x\)
\(7x=\frac{13}{10}\)
\(x=\frac{13}{10}:7\)
\(x=\frac{13}{10}.\frac{1}{7}\)
\(x=\frac{13}{70}\)
\(Vậyx=\frac{13}{70}\)
\(\frac{1}{3}x+\frac{2}{5}x-\frac{2}{5}x=0\)
\(x.\left(\frac{1}{3}+\frac{2}{5}\right)-\frac{2}{5}=0\)
\(x.\frac{11}{15}=0+\frac{2}{5}=\frac{2}{5}\)
\(x=\frac{2}{5}:\frac{11}{15}=\frac{6}{11}\)
1) \(541+\left(218-x\right)=375\)
\(\Leftrightarrow759-x=375\)
\(\Leftrightarrow x=384\)
2) \(5\cdot\left(x+35\right)=515\)
\(\Leftrightarrow x+35=103\)
\(\Rightarrow x=68\)
3) \(96-3\cdot\left(x+1\right)=42\)
\(\Leftrightarrow3\cdot\left(x+1\right)=54\)
\(\Leftrightarrow x+1=18\)
\(\Rightarrow x=17\)
4) \(2\cdot x-138=2^3\cdot3^2\)
\(\Leftrightarrow2\cdot x-138=72\)
\(\Leftrightarrow2\cdot x=210\)
\(\Rightarrow x=105\)
Ta có :
\(3^{x-1}+5.3^{x-1}=162\)
\(\Leftrightarrow\)\(3^{x-1}\left(1+5\right)=162\)
\(\Leftrightarrow\)\(3^{x-1}.6=162\)
\(\Leftrightarrow\)\(3^{x-1}=\frac{162}{6}\)
\(\Leftrightarrow\)\(3^{x-1}=27\)
\(\Leftrightarrow\)\(3^{x-1}=3^3\)
\(\Leftrightarrow\)\(x-1=3\)
\(\Leftrightarrow\)\(x=3+1\)
\(\Leftrightarrow\)\(x=4\)
Vậy \(x=4\)
Chúc bạn học tốt ~
3x-1. (5 + 1) = 162
3x-1. 6 = 162
3x-1 = 27
3x-1 = 33
x - 1 = 3
=> x = 4
25 x 3 - 3( x + 1 ) = 42
⇒ 96 - 3( x + 1 ) = 42
⇒ 3( x + 1 ) = 54
⇒ x + 1 = 18
⇔ x = 17.
Vậy x = 17.
\(2^5\times3-3\times\left(x+1\right)=42\)
\(32\times3-3\times\left(x+1\right)=42\)
\(96-3\times\left(x+1\right)=42\)
\(3\times\left(x+1\right)=54\)
\(x+1=18\)
\(x=17\)