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\(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\Rightarrow\left(\frac{14}{5}x-50\right)=51.\frac{2}{3}\)
\(\Rightarrow\frac{14}{5}x-50=34\)
\(\Rightarrow\frac{14}{5}x=34+50\)
\(\Rightarrow\frac{14}{5}x=84\)
\(\Rightarrow x=84:\frac{14}{5}\)
\(\Rightarrow x=84.\frac{5}{14}\)
\(\Rightarrow x=30\)
Vậy \(x=30\)
Chúc bạn học tốt !!!
(\(\frac{24}{5}\). x - 50 ) : \(\frac{2}{3}\) = 51
\(\frac{24}{5}\) . x - 50 = 51 . \(\frac{2}{3}\)
\(\frac{24}{5}\) . x - 50 = \(\frac{102}{3}\)
\(\frac{24}{5}\) . x - 50 = 34
\(\frac{24}{5}\) . x = 34 + 50
\(\frac{24}{5}\) . x = 84
x = 84 : \(\frac{24}{5}\)
x = \(\frac{2016}{5}\)
24 hay là 2( số nhân với mẫu rồi cộng tử) rùi đến 4 phần 5
\(2\frac{4}{5}.x-50:\frac{2}{3}=51\)
\(\frac{14}{5}.x-50:\frac{2}{3}=51\)
\(\frac{14}{51}.x=51+50:\frac{2}{3}\)
\(\frac{14}{51}.x=51+75\)
\(\frac{14}{51}.x=126\)
\(x=126:\frac{14}{51}\)
x=459
Vậy x=459
\(\frac{2}{3}.x=\frac{5}{12}=>x=\frac{5}{12}:\frac{2}{3}=\frac{5.3}{12.2}=\frac{15}{24}\)=\(\frac{3}{8}\)
vậy x=3/8
\(\left(2\frac{4}{5}.x-50\right):\frac{2}{3}=51\)
\(\Leftrightarrow\)\(\frac{14}{5}.x-50=51.\frac{2}{3}=34\)
\(\Leftrightarrow\)\(\frac{14}{5}x=34+50=84\)
\(\Leftrightarrow\)\(x=84:\frac{14}{5}=30\)
Vậy....
\(\left(2\frac{4}{5}x-50\right):\frac{2}{3}=51\)
\(\left(\frac{14}{5}x-50\right)=51\times\frac{2}{3}\)
\(\left(\frac{14}{5}x-50\right)=34\)
\(\frac{14}{5}x=34+50\)
\(\frac{14}{5}x=84\)
\(x=84:\frac{14}{5}\)
\(x=30\)
Đề sai r, từ \(x_1;x_2;x_3;...;x_{51}\) có 51 số, chia thành 2 nhóm sẽ thừa 1 số, mà đề bài said: \(x_1+x_2=x_3+x_4=x_5+x_6=...=x_{50}+x_{51}\) vẫn đủ số ->vô cmn lí
Sửa đề
Ta có : x1 + x2 + x3 + x4 + ... + x51 = 0
Xét tổng : \((x_1+x_2)+(x_3+x_4)+...+(x_{49}+x_{50})=1\cdot25=25\)\((\)có 25 cặp\()\)
Tổng x1 + x2 + x3 + x4 + ... + x51 = 0
Hay 25 + x51 = 0
x51 = 0 - 25
x51 = -25
Khi đó x50 + x51 = 1 thay bằng x50 + -25 = 1
=> x50 = 1 - \((\)- 25\()\)
=> x50 = 26
Vậy x50 = 26
Chúc bạn học tốt :>
D = 2 . 3 + 4 . 5 + 6. 7 + ... + 50 . 51 = 150,850
E = 1 . 99 + 2 . 98 + 3 . 97 + ... + 49 . 51 + 50 .50 = 82,464
Tick nha
\(a,\dfrac{-1}{8}=\dfrac{3}{x}\\ \dfrac{3}{-24}=\dfrac{3}{x}\\ x=-24\\ b,\dfrac{x}{3}=\dfrac{3}{x}\\ x.x=3.3\\ x^2=9\\ x=\pm3\\ c,\dfrac{3}{4}.x=1\dfrac{1}{2}\\ \dfrac{3}{4}.x=\dfrac{3}{2}\\ x=\dfrac{3}{2}:\dfrac{3}{4}\\ x=2\\ d,x-\dfrac{3}{10}=\dfrac{7}{15}:\dfrac{3}{5}\\ x-\dfrac{3}{10}=\dfrac{7}{9}\\ x=\dfrac{7}{9}+\dfrac{3}{10}\\ x=\dfrac{97}{90}\\ e,\dfrac{-4}{7}-x=\dfrac{-8}{3}.\dfrac{3}{7}\\ \dfrac{-4}{7}-x=\dfrac{-8}{7}\\ x=\dfrac{-4}{7}+\dfrac{8}{7}\\ x=\dfrac{4}{7}\\ \)
=>(2,8x-50):2/3=51
=>2,8x-50=34
=>2,8x=84
=>x=84/2,8=30
\(\left[2\dfrac{4}{5}x-50\right]:\dfrac{2}{3}=51\)
\(\left(\dfrac{14}{5}x-50\right)=\dfrac{10}{3}\)
\(\dfrac{14}{5}x=\dfrac{160}{3}\)
\(\Rightarrow x=\dfrac{160}{3}:\dfrac{14}{5}\)
\(\Rightarrow x=\dfrac{400}{21}\)