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{8.30-[76-(9-3)2 ]} :50
={240-[76-36]} :50
={240-40} :50
=200:50 =4
nhầm
{23-[76-(9-3)2]} : 50
= 23 - [76 - 36] : 50
= 8 - 40 : 50
= 8 - 4/5
= 36/5
\(\left\{2^2.30-\left[76-\left(9-3\right)^2\right]\right\}:50\)
\(=\left[2^2.30-\left(76-6^2\right)\right]:50\)
\(=\left[2^2.30-\left(76-36\right)\right]:50\)
\(=\left(2^2.30-40\right):50\)
\(=\left(4.30-40\right):50\)
\(=\left(120-40\right):50\)
\(=80:50\)
\(=\dfrac{8}{5}\)
\(=1,6\)
\(\left\{240-\left[76-\left(9-3\right)^2\right]\right\}\div50=\left\{240-\left[76-6^2\right]\right\}\div50=\left\{240-\left[76-36\right]\right\}\div50\)
\(=\left\{240-40\right\}\div50=200\div50=4\)
Tìm x :
\(\left(2+x\right)\div5=6\)
\(2+x=6.5\)
\(2+x=30\)
\(x=30-2\)
\(x=28\)
\(2+x\div5=6\)
\(x\div5=6-2\)
\(x\div5=4\)
\(x=4.5\)
\(x=20\)
So sánh :
a) Ta có : \(125^{80}=\left(5^3\right)^{80}=5^{240}\)
\(25^{118}=\left(5^2\right)^{118}=5^{236}\)
mà \(240>236\)
\(\Rightarrow5^{240}>5^{236}\)
\(\Rightarrow125^{80}>25^{118}\)
b) Ta có : \(2^{161}>2^{160}=\left(2^4\right)^{40}=16^{40}>13^{40}\)
\(\Rightarrow2^{161}>13^{40}\)
={ 2 3 x 30 - [ 76 - ( 9 - 3 ) 2 ] } : 50
={ 6 x 30 - [ 76 - 62 ] } :50
={ 180 - [ 76 - 36 ]} :50
={ 180 - 40 } :50
=140 :50
=2,8
{2^3 x 30-[ 76-(9-3)^2]} : 50
= { 8x30-[76-6^2]} :50
= [240-(76-36)]:50
=( 240-40):50
=200:50
=4