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2^-1.2^x+4.2^x=9.2^5
0,5.2^x+4.2^x=288
2^x.(4+0,5)=288
2^x.4,5=288
2^x=288:4,5
2^x=64
2^x=2^6
=) x=6
a, \(3^{-2}.3^4.3^x=3^7\)
\(\Rightarrow3^{-2+4+x}=3^7\)
\(\Rightarrow3^{2+x}=3^7\)
Vì \(3\ne\pm1;3\ne0\) nên \(2+x=7\Rightarrow x=5\)
b, \(2^{-1}.2^x+4.2^x=9.2^5\)
\(\Rightarrow2^x\left(2^{-1}+4\right)=288\)
\(\Rightarrow2^x.4,5=288\Rightarrow2^x=64=2^6\)
Vì \(2\ne\pm1;2\ne0\) nên \(x=6\)
Chúc bạn học tốt!!!
a) 2-1.2x + 4.2x = 9.25
=> 2x-1 + 4.2.2x-1 = 9.25
=> 2x-1 + 8.2x-1 = 9.25
=> 2x-1.(1 + 8) = 9.25
=> 2x-1.9 = 9.25
=> x - 1 = 5
=> x = 5 + 1 = 6
Vậy x = 6
b) (7x + 2)-1 = \(\frac{1}{9}\)
=> 7x + 2 = 9
=> 7x = 9 - 2
=> 7x = 7
=> x = 7 : 7 = 1
Vậy x = 1
a) 2^(-1) . 2^x + 4 . 2^x = 9 . 2^5
=> 1/2 . 2^x + 4 . 2^x = 9 . 32
=> 2^x . (1/2 + 4) = 288
=> 2^x . 9/2 = 288
=> 2^x = 288 : 9/2
=> 2^x = 64
2^x = 2^6
=> x = 6
b) (7x + 2)^(-1) = 1/9
=> 1 phần 7x + 2 = 1/9
=> 7x + 2 = 9
=> 7x = 9 - 2
=> 7x = 7
=> x = 7 : 7
=> x = 1
\(\frac{1}{2}.2^x+4.2^x=9.2^5\)
\(\Rightarrow\)2x(\(\frac{1}{2}+4\))=9.25
\(\Rightarrow\)\(\frac{9}{2}.2^x=9.2^5\)
\(\Rightarrow9.2^{x-1}=9.2^5\)
\(\Rightarrow2^{x-1}=2^5\)
\(\Rightarrow\)x-1=5
\(\Rightarrow\)x=6(tm)
Vậy x=6
a) 3x+2 + 5.3x+1 = 648
=> 3x+1.3+ 5.3x+1= 648
=> 3x+1(3+ 5) = 648
=> 3x+1.8 = 648
=> 3x+1 = 81
=>3x+1= 34
=> x+1 = 4
=> x = 3
vậy x= 3
\(2^{-1}.2^x+4.2^x=9.2^5\)
\(\frac{1}{2}.2^x+4.2^x=9.2^5\)
\(2^x\left(\frac{1}{2}+4\right)=9.2^5\)
\(2^x.\frac{9}{2}=288\)
\(2^x=288:\frac{9}{2}\)
\(2^x=64\)
\(2^x=2^6\)
\(\Rightarrow x=6\)
1/2*2x+4*2x=9*25
(1/2+4)*2x=225
9/2*2x=225
2x=225:9/2
2x=50
=>x\(\in\phi\)