Câu hỏi của Lucky Mari

Question

1,tinh ra gam khoi luong cua cac nguyen tu sau AL,Mg ,Ca,O

2,tong so hat co ban trong mot nguyen tu la 58 trong do so hat manh dien nhieu hon so hat ko mang dien la 18 tinh so hat moi ***** niet ten...

Phùng Hà Châu · Accepted Answer

Bài 1:

$KLT_{Al}=NTK_{Al}\times KLT_{1đvC}=27\times0,16605\times10^{-23}=4,48335\times10^{-23}\left(g\right)$

$KLT_{Mg}=NTK_{Mg}\times KLT_{1đvC}=24\times0,16605\times10^{-23}=3,9852\times10^{-23}\left(g\right)$

$KLT_{Ca}=NTK_{Ca}\times KLT_{1đvC}=40\times0,16605\times10^{-23}=6,642\times10^{-23}\left(g\right)$

$KLT_O=NTK_O\times KLT_{1đvC}=16\times0,16605\times10^{-23}=2,6568\times10^{-23}\left(g\right)$Câu trả lời: Bài 1:

$KLT_{Al}=NTK_{Al}\times KLT_{1đvC}=27\times0,16605\times10^{-23}=4,48335\times10^{-23}\left(g\right)$

$KLT_{Mg}=NTK_{Mg}\times KLT_{1đvC}=24\times0,16605\times10^{-23}=3,9852\times10^{-23}\left(g\right)$

$KLT_{Ca}=NTK_{Ca}\times KLT_{1đvC}=40\times0,16605\times10^{-23}=6,642\times10^{-23}\left(g\right)$

$KLT_O=NTK_O\times KLT_{1đvC}=16\times0,16605\times10^{-23}=2,6568\times10^{-23}\left(g\right)$

Phùng Hà Châu · Answer

Ta có: $p+e+n=58$

$\Leftrightarrow2p+n=58$

$\Leftrightarrow n+18+n=58$

$\Leftrightarrow2n+18=58$

$\Leftrightarrow2n=40$

$\Rightarrow n=20$

$\Rightarrow p+e=58-20=32$

Mà $p=e\Rightarrow p=e=\dfrac{1}{2}\times32=16$

Vậy đây là nguyên tử lưu huỳnhCâu trả lời: Ta có: $p+e+n=58$