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a ) \(\left(3\times x-15\right)^7=0.\)
\(3\times x-15=0\)
\(3\times x=15\)
\(x=5\)
b ) \(10-\left\{\left[\left(x\div3+17\right)\div10+3\times2^4\right]\div10\right\}=5\)
\(10-\left\{\left[\left(x\div3+17\right)\div10+3\times16\right]\div10\right\}=5\)
\(10-\left\{\left[\left(x\div3+17\right)\div10+48\right]\div10\right\}=5\)
\(\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)
\(\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)
\(\left(x\div3+17\right)\div10+48=50\)
\(\left(x\div3+17\right)\div10=2\)
\(x\div3+17=20\)
\(x\div3=3\)
\(x=9\)
a) 541 + (218 - x) = 735
\(\Rightarrow\) 218 - x = 735 - 541
\(\Rightarrow\) 218 - x = 194.
\(\Rightarrow\) x = 218 - 194
\(\Rightarrow\) x = 24
b) 5(x + 35) = 515
\(\Rightarrow\) x + 35 = 515 : 5 = 103.
\(\Rightarrow\) x = 103 - 35
\(\Rightarrow\) x =68.
c) 96 - 3(x + 1) = 42
\(\Rightarrow\) 3(x + 1) = 96 - 42 = 54
\(\Rightarrow\) x + 1 = 54 : 3
\(\Rightarrow\) x = 18 - 1
\(\Rightarrow\) x = 17
d) 12x - 33 = 32 . 33
\(\Rightarrow\) 12x - 33 = 243
\(\Rightarrow\)12x = 243 + 33
\(\Rightarrow\) 12x = 276.
\(\Rightarrow\) x = 23.
a) 541 + (218 - x) = 735
Suy ra 218 - x = 735 - 541 hay 218 - x = 194.
Do đó x = 218 - 194. Vậy x = 24.
b) 5(x + 35) = 515 suy ra x + 35 = 515 : 5 = 103.
Do đó x = 103 - 35 =68.
c) Từ 96 - 3(x + 1) = 42 suy ra 3(x + 1) = 96 - 42 = 54. Do đó x + 1 = 54 : 3 = 18. Vậy x = 18 - 1 hay x = 17.
d) Từ 12x - 33 = 32 . 33 hay 12x - 33 = 243 suy ra 12x = 243 + 33 hay 12x = 276. Vậy x = 23.
\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)
\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)
\(x=1\div\left(-\frac{3}{5}\right)\)
\(x=-\frac{5}{3}\)
\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)
\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)
\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)
\(-\frac{4}{21}\cdot x=\frac{3}{5}\)
\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)
\(x=-\frac{63}{20}\)
\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)
\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)
\(\frac{5}{7}\cdot x=1\)
\(x=1\div\frac{5}{7}\)
\(x=\frac{7}{5}\)
\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)
\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)
\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)
\(\frac{17}{33}\cdot x=\frac{9}{14}\)
\(x=\frac{9}{14}\div\frac{17}{33}\)
\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)
(x-5)(x-7)=0
=> x-5=0 hoặc x-7=0
=> x=5 hoặc x=7
541+(218-x)=735
=> 218-x=735-541
=> 218-x=194
=> x=218-194
=> x=24
96-3(x+1)=42
=>3(x+1)=96-42
=>3(x+1)=54
=>x+1=54:3
=>x+1=18
=>x=18-1
=>x=17
(x-47)-115=0
=>x-47=0+115
=>x-47=115
=>x=115+47
=>x=162
(x-36):18=12
=>x-36=12.18
=>x-36=216
=>x=216+36
=>x=252
(x-5).(x-7)=0
x-5=0+7
x=7+5
x=12
541+(218-x)=735
218-x=735-541
x=218-196
x=12
96-3(x+1)=42
3(x+1)=96-42
x+1=54:3
x=17-1
x=16
(x-47)-115=0
x-47=0+115
x=115+47
x=162
(x-36):12=18
x-36=12*18
x-36=216
x=216+36
x=252
Trả lời
Mk nghĩ bạn có thể tham khảo ở CHTT nha !
Có đáp án của câu b;c và d đó.
Đừng ném đá chọi gạch nha !
a) vi(x^2+5)(x^2-25)=0
=>x^2+5=0 hoac x^2-25=0
=>x=...hoac x=...(tu lam)
b)(x-2)(x+1)=0
=>x-2=0 hoac x+1=0
=>x=2 hoac x=-1
c)(x^2+7)(x^2-49)<0
=>x^2+7va x^2-49 trai dau
ma x^2+7>=7=>x^2-49<0=>x<7 va x>-7
con lai tuong tu
tu lam nhe nho k nha
a) 541+(218-x)=735
=>735-541=218-x
194=218-x
x=218-194
x=24
b) (x-47)-115=0
=>x-47=115
x=115+47
x=162
b) (x-47)-115=0
=>x-47=115
x=115+47
x=162