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28 x 17 + 101 x 3 + 73 x 17 = 17 x (28 + 73) + 101 x 3
= 17 x 101 + 101 x 3
= 101 x (17 + 3)
= 101 x 20
= 2020
28 x 17 + 101x 3 + 73 x 17
= 17x ( 28 + 73 ) + 101 x 3
= 101 x 17 + 101x 3
= 101x( 17 + 3)
= 101 x 20
= 2020
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a) 135 - ( x + 32 ) = 80
x + 32 = 135 - 80
x + 32 = 55
x = 55 - 32
x = 23
b)( x - 17 ) + 52 = 158
x - 17 = 158 - 52
x - 17 = 106
x = 106 + 17
x = 123
c x : 17 + 83 = 297
x : 17 = 297 - 83
x : 17 = 214
x = 214 x 17
x = 3638
d) 9052: x - 56 = 17
9052 : x = 17 + 56
9052 : x = 73
x = 9052 : 73
x = \(\frac{1004}{17}\)
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Bài 1:
a) 17-25+55-17
=(17-17)+(-25+55)
=0+30
=30
b.(-37+101)-(91+37)
= -37+101-91-37
=(-37-37)+(101-91)
= -74 + 10
=-64
c.(-4-6):(-5)
=(-10) : (-5)
=2
d)35-(-95)+372-(372+95)
=35+95+372-372-95
=35+(95-95) + ( 372-372)
=35
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6A=5.7.6+7.9.6+9.11.6+11.13.6+13.15.6+...+99.101.6
6A=5.7.(9-3)+7.9.(11-5)+9.11.(13-7)+11.13.(15-9)+13.15.(17-11)+...+99.101.(103-97)
6A=-3.5.7+5.7.9-5.7.9+7.9.11-7.9.11+9.11.13-9.11.13+11.13.15-11.13.15+13.15.17-...-97.99.101+99.101.103
6A=99.101.103-3.5.7 => A=(99.101.103-3.5.7)/6
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1) tính nhanh
Ta thấy các số cách nhau 2 đơn vị lên
Số số hạng là \(\left(51-3\right)\div2+1=25\) ( số hạng )
Tổng dãy số trên là \(\left(51+3\right)\times25\div2=675\)
2) Tìm x
a) \(135+x\times2=151\)
\(x\times2=151-135=16\)
\(x=16\div8\)
b) \(x\times5-227=273\)
\(x\times5=273+227=500\)
\(x=500\div5\)
\(x=100\)
c) \(\left(x-4\right)\times3+2=101\)
\(\left(x-4\right)\times3=101-2=99\)
\(x-4=99\div3=33\)
\(x=33+4\)
\(x=37\)
d) \(170-\left(4+5\times x\right)=101\)
\(4+5\times x=170-101=69\)
\(5\times x=69-4\)
\(5\times x=65\)
\(x=65\div5\)
\(x=13\)
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\(a;343-4\times\left(x+1\right)=143\)
\(4\times\left(x+1\right)=343-143\)
\(4\times\left(x+1\right)=200\)
\(x+1=200:4\)
\(x+1=50\)
\(x=50-1=49\)
Mấy câu hỏi trẻ trâu thì tự tính nhé
\(\frac{1}{5.8}+\frac{1}{8.11}+...+\frac{1}{x.\left(x+3\right)}=\frac{101}{1540}\)
\(\Leftrightarrow\frac{1}{3}.\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}\right)=\frac{101}{1540}\)
\(\Leftrightarrow\frac{1}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)=\frac{101}{1540}\)
\(\Leftrightarrow\frac{1}{3}.\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{101}{1540}\)
\(\Leftrightarrow\frac{1}{5}-\frac{1}{x+3}=\frac{303}{1540}\)
\(\Leftrightarrow\frac{1}{x+3}=\frac{1}{308}\)
\(\Leftrightarrow x+3=308\)
\(\Leftrightarrow x=305\)
Vậy x=305
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a,(18+29)+(158-18-29)=18+29+158-18-29=158
b,(-13-135+49)-(13+49)=-13-135+49-13-49=-26-135=-161
c,(-25)+15=-10
d,(-99)+(-100)+(-101)+(-102)=-99-100-101-102=-402
e,34+(-11)+(-4)=34-4-11=19
f,134+45+(-14)+(-5)=(134-14)+(45-5)=120+40=160
g,21+(-50)+(-1)=(21-1)-50=20-50=-30
h,44+(-213)+/-156/=44+213+156=(44+156)+213=200+213=413
i,212+[37+(-312)+(-17)]=212+37-312-17=(212-312)+(37-17)=-100+20=-80
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5) 125. (−8). (−25). 9.4.1000 : 3
=[125.(-8)].[(-25).4].(9:3).1000
=-1000.(-100).3.1000
=100000.3.1000
=300000.1000
=300000000
6) (−2)3 . 13.125
=-8.13.125
=(-8.125).13
=-1000.13
=-13000
7) 17. (38 − 5) − 38. (17 − 1)
=17 . 33 - 38 . 16
=561-608
=-47
8) (−41). 135 + 135. (−58) − 135
=(-41).135+135.(-58)+135.(-1)
=135.[-41+(-58)+(-1)]
=135.(-100)
=-13500
\(\left(-17\right).x-135=-101.\)
\(\left(-17\right).x=-101+135\)
\(\left(-17\right).x=34\)
\(x=34\div\left(-17\right)\)
\(x=-2\)