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a)1/3x(1/6+17/6)+2013/2014-2014/2014
=1/3 x 3 - 1/2014
=1 - 1/2014
=2013/2014
b) câu này mình k hiểu nên giải thích thế nào
Đặt phân thức trên là D
=> D=(1+1+1+1+...+1+2013/2+2012/3+...+2/2013+1/2014)/(1/2+1/3+1/4+...+1/2014)
=> D=(1+2013/2+1+2012/3+1+2011/4+...+1+2/2013+1+1/2014+1)/(1/2+1/3+1/4+1/5+...+1/2014)
=> D=(2015/2+2015/3+2015/4+...+2015/2013+2015/2014+1)/(1/2+1/3+1/4+...+1/2014)
=> D=[2015*(1/2+1/3+1/4+1/5+....+1/2014)]/(1/2+1/3+1/4+1/5+...+1/2014)
=> D=2015
\((2013\cdot2014\cdot2015)\cdot(1-\frac{1}{3}-\frac{1}{2}-\frac{1}{6})\)
\(=(2013\cdot2014\cdot2015)\cdot(\frac{6}{6}-\frac{2}{6}-\frac{3}{6}-\frac{1}{6})\)
\(=(2013\cdot2014\cdot2015)\cdot(\frac{6-2-3-1}{6})\)
\(=(2013\cdot2014\cdot2015)\cdot0=0\)
( 2013 × 2014 × 2015 ) × ( 1 - 1/3 - 1/2 - 1/6 )
= ( 2013 × 2014 × 2015 ) × ( 6/6 - 2/6 - 3/6 - 1/6)
= ( 2013 × 2014 × 2015 ) × 6 - 2 - 3 - 1/6
= ( 2013 × 2014 × 2015 ) × 0
= 0
Ta có:
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2013.2014}\)
Ta thấy :
\(\frac{1}{1.2}=\frac{1}{1}-\frac{1}{2}\)
\(\frac{1}{2.3}=\frac{1}{2}-\frac{1}{3}\)
\(...\)
\(\frac{1}{2013.2014}=\frac{1}{2013}-\frac{1}{2014}\)
Ta có:
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2013}-\frac{1}{2014}\)
\(=1-\frac{1}{2014}\)
\(=\frac{2013}{2014}\)
\frac{2}{7}\cdot \:x=\frac{1}{7}\cdot \:x+17
\frac{1}{7}\:x=17
x = 119
kb với mình và tk cho tớ nha!
\(\frac{2}{7}.x=\frac{1}{7}.x+17\)
\(\frac{1}{7}x=17\)
\(x=17:\frac{1}{7}\)
\(x=119\)
a) 19 x 64 + 76 x 34
= 19 x 64 + 19 x 136
= 19.(64 + 136)
= 19 . 200
= 3800
a) 19 x 64 + 76 x 34
= 19 x 64 + 19 x 136
= 19.(64 + 136)
= 19 . 200
= 3800
1.
a) \(\frac{6}{15}+\frac{6}{35}+\frac{6}{63}+\frac{6}{99}+\frac{6}{143}\)
\(=\frac{6}{3.5}+\frac{6}{5.7}+\frac{6}{7.9}+\frac{6}{9.11}+\frac{6}{11.13}\)
\(=\frac{6}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{11}-\frac{1}{13}\right)\)
\(=\frac{6}{2}\left(\frac{1}{3}-\frac{1}{13}\right)\)
\(=\frac{6}{2}.\frac{10}{39}\)
\(=\frac{10}{13}\)
b) \(\frac{3}{24}+\frac{3}{48}+\frac{3}{80}+\frac{3}{120}+\frac{3}{168}\)
\(=\frac{3}{4.6}+\frac{3}{6.8}+\frac{3}{8.10}+\frac{3}{10.12}+\frac{3}{12.14}\)
\(=\frac{3}{2}\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}+...+\frac{1}{12}-\frac{1}{14}\right)\)
\(=\frac{3}{2}.\left(\frac{1}{4}-\frac{1}{14}\right)\)
\(=\frac{3}{2}.\frac{5}{28}\)
\(=\frac{15}{56}\)
\(a.\frac{6}{3.5}+\frac{6}{5.7}+...+\frac{6}{11.13}\)
\(=3.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)\)
\(=3.\left(\frac{1}{3}-\frac{1}{13}\right)\)
\(=3.\frac{10}{39}\)
\(=\frac{10}{13}\)
\(\frac{1}{6}\times\frac{1}{3}+\frac{17}{6}\times\frac{1}{3}+\frac{2013}{2014}-1=\frac{1}{3}\times\left(\frac{1}{6}+\frac{17}{6}\right)+\frac{2013}{2014}-1.\)
\(=\frac{1}{3}\times\frac{18}{6}+\frac{2013}{2014}-1=\frac{1}{3}\times3+\frac{2013}{2014}-1.\)
\(=\left(1-1\right)+\frac{2013}{2014}=0+\frac{2013}{2014}=\frac{2013}{2014}\)
2m 5dm 8cm + 3m 2cm=…………
Mn giúp minh thực hiện phép tính này vs.