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b, 2x = 42x45 /8
2x = 16x45 /8
2x = 2x45
2x = 2x(22)5
2x = 2x210
2x = 211
=> x = 11
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1)=>3(x-5)(2x+9)+3(x-5)=0=>(x-5)(6x+30)
=>x-5=0=>x=5
6x+30=0=>x=-5
2)=>x^2-16=0=>x=+-4
12-4x=0=>x=3
3)=>9-x^2=0=>x=+-3
4x-8=0=>x=2
4)=>8-x^3=0=>x=3
5^x-125=0=>x=2
5)=>2^x.2^x=8=>2^2x=8=>2x=3=>x=1,5
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\(9^{12}.27^5.81^4=\left(3^2\right)^{12}.\left(3^3\right)^5.\left(3^4\right)^4\)
\(=3^{24}.3^{15}.3^{16}\)
\(=3^{55}\)
\(64^3.4^5.16^2=\left(4^3\right)^3.4^5.\left(4^2\right)^2=4^{18}\)
\(25^{20}.125^4=\left(5^2\right)^{20}.\left(5^3\right)^4=5^{52}\)
\(x^7.x^4.x^3=x^{14}\)
\(3^6.4^6=\left(3.4\right)^6=12^6\)
\(8^4.2^3.16^2=\left(2^3\right)^4.2^3.\left(2^4\right)^2=2^{23}\)
\(2^3.2^2.\left(2^3\right)^3=2^{14}\)
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\(\left(12x-4\right)^3.8^3=4^{16}.16^3\)
\(\Leftrightarrow8\left(12x-4\right)^3=4^6.\left(4^2\right)^{^3}\)
\(\Leftrightarrow\left(96x-32\right)^3=4^6.4^6\)
\(\Leftrightarrow\left(96x-32\right)^3=16^6\)
\(\Leftrightarrow\left(96x-32\right)^3=\left(16^2\right)^{^3}\)
\(\Leftrightarrow\left(96x-32\right)^3=256^3\)
\(\Leftrightarrow96x-32=256\)
\(\Leftrightarrow x=\frac{256+32}{96}\)
Vậy \(x=3\)
(12x-4)3.83=43.163
<=> [(12x-4).8]3=(4.16)3
=> (12x-4).8=4.16
<=> 12x-4=8
<=> 12x=12
=> x=1
16 x 4x= 48
42 x 4x = 48
4x = 48 : 42
4x = 46
→ x= 6
16 x 4x = 48
42 . 4x = 48
42+x = 48
=> x+2=8
x =8-2
x = 6