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\(\frac{3}{3.6.9}+\frac{3}{6.9.12}+\frac{3}{9.12.15}+\frac{3}{12.15.18}=\frac{3}{6}\left(\frac{6}{3.6.9}+\frac{6}{6.9.12}+\frac{6}{9.12.15}+\frac{6}{12.15.18}\right)\)
= \(\frac{1}{2}\left(\frac{1}{3.6}-\frac{1}{6.9}+\frac{1}{6.9}-\frac{1}{9.12}+\frac{1}{9.12}-\frac{1}{12.15}+\frac{1}{12.15}-\frac{1}{15.18}\right)\)
\(=\frac{1}{2}\left(\frac{1}{3.6}-\frac{1}{15.18}\right)=\frac{1}{2}.\frac{14}{270}=\frac{7}{270}\)
( 15 +x ) : 3 = 315 : 312
=> ( 15 + x ) : 3 = 315 - 12
=> ( 15 + x ) : 3 = 33
=> ( 15 + x ) : 3 = 27
=> 15 + x = 27 . 3
=> 15 + x = 81
=> x = 81 - 15
=> x = 66
Vậy x = 66
\(1,\frac{2}{3}+\frac{4}{9}+\frac{1}{5}+\frac{2}{15}+\frac{3}{2}-\frac{17}{18}\)
\(< =>\frac{4}{9}+\frac{3}{2}+\left(\frac{2}{3}+\frac{1}{5}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{8}{18}+\frac{27}{18}+\left(\frac{10}{15}+\frac{3}{15}+\frac{2}{15}\right)-\frac{17}{18}\)
\(< =>\frac{35}{18}+1-\frac{17}{18}\)
\(< =>\frac{53}{18}-\frac{17}{18}\)
\(< =>2\)
\(2,\frac{13}{28}\cdot\frac{5}{12}-\frac{5}{28}\cdot\frac{1}{12}\)
\(< =>\left(\frac{13}{28}-\frac{5}{28}\right)\cdot\left(\frac{5}{12}-\frac{1}{12}\right)\)
\(< =>\frac{2}{7}\cdot\frac{1}{3}\)
\(< =>\frac{2}{21}\)
\(3,\frac{19}{4}\cdot\frac{15}{23}-\frac{15}{4}\cdot\frac{7}{23}+\frac{15}{4}\cdot\frac{11}{23}\)
\(< =>\frac{285}{92}-\frac{105}{92}+\frac{165}{92}\)
\(< =>\frac{15}{4}\)
(15 + x ) : 3 = 3\(^{15}\) : 3\(^{12}\)
(15 + x ) : 3 = 27
15 + x = 27 : 3
15 + x = 9
x = 9 - 15 ( vô lý )
vì 9 ko trừ đc 15 nên x \(\in\)tập\(\varnothing\)
Vậy x\(\in\)tập \(\varnothing\)
học tốt!!!
\(a,3\left(x-5\right)-4\left(x-3\right)=-12\)
\(\Leftrightarrow3x-15-4x+12=-12\)
\(\Leftrightarrow-x=-9\)
\(\Leftrightarrow x=9\)
Vậy x=9
-12(x-15)+7(3-x)=15
-12.15-(-12.x)+7.3-7.x=15
(-12.15+7.3)-(-12x+7x)=15
-172.7-(-5x)=15
-172.7+5x=15
5x=8.48
x=1.696
\(\left(15+x\right):3=3^{15}:3^{12}\)
\(\left(15+x\right)=3^3.3\)
\(15+x=3^4\)
\(x=81-15\)
\(x=66\)
\(\left(15+x\right):3=3^{15}:3^{12}\)
\(\left(15+x\right):3=3^{15-12}\)
\(\left(15+x\right):3=3^3\)
\(15+x=3^3.3\)
\(15+x=81\)
\(x=81-15\)
\(x=66\)