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215 - ( x - 35 ) = 150
( x - 35 ) = 215 - 150
( x - 35 ) = 65
x = 65 + 35
x = 100
3x + 3x+1 =108
=> 3x ( 1 + 3 ) = 108
=> 3x = 27
=> 3x = 33
=> x = 3
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a) = \(\frac{-2}{5}\)
b) = \(\frac{-5}{4}\)
c)= \(\frac{-11}{15}\)
d) = \(\frac{3}{2}\)
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a) (2x-32):16=3
2x-32=3.16
2x-32=48
2x=48+32
2x=80
x=80:2
x=40
b) (7x -8:2):5=8
(7x-4):5=8
7x-4=8.5
7x-4=40
7x=40+4
a) (2x - 32) : 16 = 3 \(=\left(2x-32\right)=3.16=48\)
= \(\left(2x-32\right)=48\)
= \(2x=48+32=80\)
= \(2x=80\Rightarrow x=80:2=40\)
b) ( 7x - 8 :2) : 5 = 8
= \(\left(7x-8:2\right)=8.5=40\)
= \(\left(7x-8:2\right)=40\)
= \(\left(7x-8\right)=40.2=80\)
= \(\left(7x-8\right)=80\)
= \(7x=80+8=88\)
=>x = 88 : 7 = ......
c) 215 + ( x - 21) : 2 = 235
\(=\left(x-21\right):2=235-215=20\)
= \(\left(x-21\right):2=20\)
= \(\left(x-21\right)=20.2=40\)
= \(\left(x-21\right)=40\)
= \(\Rightarrow x=40+21=61\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\dfrac{6:\dfrac{3}{5}-\dfrac{17}{16}.\dfrac{6}{7}}{\dfrac{21}{5}.\dfrac{10}{11}+\dfrac{57}{11}}-\dfrac{\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{15}\right).\dfrac{12}{49}}{\dfrac{10}{3}+\dfrac{2}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{\dfrac{509}{56}}{9}-\dfrac{\dfrac{7}{12}.\dfrac{12}{49}}{\dfrac{32}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{509}{504}-\dfrac{\dfrac{1}{7}}{\dfrac{32}{9}}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\left(\dfrac{509}{504}-\dfrac{9}{224}\right).x=\dfrac{215}{96}\)
\(\Rightarrow\dfrac{1955}{2016}.x=\dfrac{215}{96}\)
\(\Rightarrow x=\dfrac{215}{96}:\dfrac{1955}{2016}\)
\(\Rightarrow x=\dfrac{903}{391}\)
`[ 6 : 3/5 - 17/16 . 6/7 : 21/5 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 : 10/3 + 2/9 ] . x = 215/96`
`=>[ 6 . 5/3 - 17/16 . 6/7 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=>[10- 51/56 . 6/7 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 153/196 . 5/21 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 255/1372 . 10/11 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> [10- 1275/7546 + 57/11 - (3/20 + 1/2 - 1/15) . 12/49 . 3/10 + 2/9 ] . x = 215/96`
`=> (10- 1275/7546 + 57/11 - 7/12. 12/49 . 3/10 + 2/9 ) . x = 215/96`
`=> ( 10- 1275/7546 + 57/11 -343/600 . 3/10 + 2/9 ) . x = 215/96`
`=> ( 10- 1275/7546 + 57/11 -343/2000 + 2/9 ) . x = 215/96`
`=>15,06357671 . x= 215/96`
`=> x= 215/96: 15,06357671`
`=>x= 0,1486754027`
Đề có phải như vậy không nhỉ ?
\(\left(15.3-21\right):2^2+108-1^{215}\)
\(=\left(45-21\right):4+108-1\)
\(=24:4+108-1\)
\(=6+108-1\)
\(=113\)