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a, \(\left(\frac{17}{6}+\frac{13}{9}\right):\left(\frac{121}{12}+\frac{19}{2}\right)\)
\(=\frac{77}{18}:\frac{235}{12}=\frac{77}{18}.\frac{12}{235}=\frac{154}{705}\)
b, \(\left(\frac{19}{2}-\frac{35}{4}\right).\frac{7}{2}+\frac{5}{8}:\frac{5}{3}\)
\(\frac{3}{4}.\frac{7}{2}+\frac{5}{8}.\frac{3}{5}=\frac{21}{8}+\frac{3}{8}=\frac{24}{8}=3\)
c, \(140.\left(\frac{25}{28}+\frac{25}{36}+\frac{5}{9}\right)=140.\frac{10}{7}=200\)
d, \(\left(\frac{7}{5}-\frac{7}{25}+\frac{7}{125}-\frac{7}{625}\right):\left(1-\frac{1}{5}+\frac{1}{25}-\frac{1}{125}\right)\)
\(=\frac{728}{625}:\frac{104}{125}=\frac{728}{625}.\frac{125}{104}=\frac{7}{5}\)
c)=140[(50.10101)/(56.10101)+(50.10101)/(72.10101)+(50.10101)/(90.10101)]
=140(50/56+50/72+50/90)
=140.50(1/56+1/72+1/90)
=7000(1/7.8+1/8.9+1/9.10)
=7000(1/7-1/8+1/8-1/9+1/9-1/10)
=7000(1/7-1/10)
=7000.3/70
=300
Đặt \(A=\frac{3\cdot7\cdot13\cdot37\cdot39-10101}{505050-70707}\)
\(A=\frac{\left(3\cdot7\cdot13\cdot37\right)\cdot39-10101\cdot1}{50\cdot10101+7\cdot10101}\)
\(A=\frac{10101\cdot39-10101\cdot1}{10101\cdot\left(50+7\right)}\)
\(A=\frac{10101\cdot\left(39-1\right)}{10101\cdot57}\)
\(A=\frac{10101\cdot38}{10101\cdot57}\)
\(A=\frac{38}{57}=\frac{38:19}{57:19}=\frac{2}{3}\)
=\(70\left(\frac{121212}{565656}+\frac{121212}{727272}+\frac{121212}{909090}\right)\)
=\(70\left(\frac{3.40404}{14.40404}+\frac{121212}{6.121212}+\frac{2.60606}{15.60606}\right)\)
=\(70\left(\frac{3}{14}+\frac{1}{6}+\frac{2}{15}\right)\)
=\(70.\frac{18}{35}=38\)
\(B=70\cdot\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
\(B=70\cdot\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\)
\(B=70\cdot\frac{39}{70}\)
\(B=39\)
Vậy B = 39
B=\(70\times\left(\frac{131313}{565656}+\frac{131313}{727272}+\frac{131313}{909090}\right)\)
B=\(70\times\left(\frac{13}{56}+\frac{13}{72}+\frac{13}{90}\right)\)
B=\(70\times\frac{39}{70}\)
B=\(39\)
Nếu mk làm sai thì xin lỗi bạn nhiều nha
http://coccoc.com/search#query=140.+(+505050%2F565656+%2B+505050%2F727272+%2B+505050%2F909090+)
\(140.\left(\frac{505050}{565656}+\frac{505050}{727272}+\frac{505050}{909090}\right)\)
\(=140.\left(\frac{50}{56}+\frac{50}{72}+\frac{50}{90}\right)\)
\(=140.\left(\frac{25}{28}+\frac{25}{36}+\frac{5}{9}\right)\)
\(=140.\frac{225+175+140}{252}\)
\(=140.\frac{540}{252}=140.\frac{15}{7}=300\)