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\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(x+\dfrac{1}{6}=\dfrac{3}{4}\)
\(x=\dfrac{9}{12}-\dfrac{2}{12}\)
\(x=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(x=\dfrac{1}{2}-\dfrac{1}{2020}\)
\(x=\dfrac{1010}{2020}-\dfrac{1}{2020}\)
\(x=\dfrac{1009}{2020}\)
\(\dfrac{2}{5}\times\dfrac{1}{7}+\dfrac{2}{7}\times\dfrac{2}{5}\)
\(=\dfrac{2}{5}\times\left(\dfrac{1}{7}+\dfrac{2}{7}\right)\)
\(=\dfrac{2}{5}\times\dfrac{3}{7}\)
\(=\dfrac{6}{35}\)
\(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}-x\)
\(\Rightarrow\dfrac{3}{4}-x=\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times...\times\left(1-\dfrac{1}{2020}\right)+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2019}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1\times2\times3\times4\times...\times2019}{2\times3\times4\times5\times...\times2020}+x=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2020}+x=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}-\dfrac{1}{2020}=\dfrac{1009}{2020}\)
Câu 1:
a. $3\frac{2}{3}+2\frac{1}{2}=(3+2)+(\frac{2}{3}+\frac{1}{2})=5+\frac{7}{6}=6+\frac{1}{6}=6\frac{1}{6}$
b. \(2\frac{1}{2}\times 3\frac{2}{5}=\frac{5}{2}\times \frac{17}{5}=\frac{17}{2}\)
c.
\(3\frac{1}{3}: 4\frac{1}{4}=\frac{10}{3}: \frac{17}{4}=\frac{40}{51}\)
d.
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=(3+4-5)+(\frac{1}{2}+\frac{5}{7}-\frac{5}{14})=2+\frac{6}{7}=2\frac{6}{7}\)
Câu 2:
a. $x\times \frac{2}{7}=\frac{6}{11}$
$x=\frac{6}{11}: \frac{2}{7}=\frac{21}{11}$
b. $x: \frac{3}{2}=\frac{1}{4}$
$x=\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$
\(\frac{7}{4}-x.\frac{3}{4}=\frac{5}{19}\)
\(\Rightarrow1+\frac{3}{4}-x.\frac{3}{4}=\frac{5}{9}\)
\(\Rightarrow\frac{3}{4}.\left(1-x\right)=\frac{5}{9}-1=-\frac{4}{9}\)
\(\Rightarrow1-x=-\frac{4}{9}:\frac{3}{4}=-\frac{16}{27}\)
\(\Rightarrow x=1-\left(-\frac{16}{27}\right)=1+\frac{16}{27}=1\frac{16}{27}\)
khỏi chép đề nha
a\Câu 1:
200 : ( 15 - x ) = 15 + 5
200 : ( 15 - x ) = 20
15 - x = 200 : 20
15 - x = 10
x = 15 - 10
x = 5
Câu 2:
63 : ( x - 5 ) = 22 -1
63 : ( x - 5 ) = 21
x - 5 = 63 : 21
x - 5 = 3
x = 3 + 5
x = 8
6 2/7 + 7 3/5 + 8 6/9 + 9 1/4 + 2/5 + 5/7 + 1/3 x 3/4 + 1967
= 44/7 + 38/5 + 78/9 + 37/4 + 2/5 + 5/7 + 1/3 + 1967
= ( 44/7 + 5/7 ) + ( 38/5 + 2/5 ) + ( 26/3 + 1/3 ) + ( 37/4 + 3/4 ) +1967
= 7 + 8 + 9 + 10 + 1967
= 15 + 9 + 10 + 1967
= 24 + 10 + 1967
= 34 + 1967
= 2001
Lời giải:
a.
$x:3\frac{1}{15}-\frac{3}{4}=2\frac{1}{4}$
$x:\frac{46}{15}-\frac{3}{4}=\frac{9}{4}$
$x: \frac{46}{15}=\frac{9}{4}+\frac{3}{4}=3$
$x=3\times \frac{46}{15}=\frac{46}{5}$
b. $x\times 3\frac{2}{3}-1\frac{2}{3}=2\frac{1}{3}$
$x\times \frac{11}{3}=1\frac{2}{3}+2\frac{1}{3}=4$
$x=4: \frac{11}{3}=\frac{12}{11}$
\(\left(x-\frac{2}{5}\right):\frac{4}{3}=\frac{3}{8}\)
\(\Rightarrow x-\frac{2}{5}=\frac{3}{8}.\frac{4}{3}=\frac{1}{2}\)
\(\Rightarrow x=\frac{1}{2}+\frac{2}{5}=\frac{9}{10}\)
\(\frac{5}{4}-x.\frac{5}{6}=\frac{1}{4}+\frac{1}{3}\)
\(\Rightarrow\frac{5}{4}-x.\frac{5}{6}=\frac{7}{12}\)
\(\Rightarrow x.\frac{5}{6}=\frac{5}{4}-\frac{7}{12}=\frac{2}{3}\)
\(\Rightarrow x=\frac{2}{3}:\frac{5}{6}=\frac{2}{3}.\frac{6}{5}=\frac{4}{5}\)
`75/20 - x = 3/2 xx 10`
`15/4 - x = 15`
`x = 15/4 - 15`
`x = -45/4`
`(12 xx 15) - X xx 1/4 = 120 xx 1/4`
`180 - X xx 1/4 = 30`
`X xx 1/4 = 180-30`
`X xx 1/4 = 150`
`X = 150 : 1/4`
`X = 600`
\(\dfrac{15}{4}-x=15\)
\(x=\dfrac{15}{4}-15\)
\(x=-\dfrac{45}{4}\)
\(\left(12\times15\right)-\dfrac{1}{4}x=120\times\dfrac{1}{4}\)
\(180-\dfrac{1}{4}x=30\)
\(-\dfrac{1}{4}x=30-180\)
\(-\dfrac{1}{4}x=-150\)
\(-x=-150:\dfrac{1}{4}\)
\(-x=-150\times4\)
\(-x=-600\)
\(x=600\)
\(\dfrac{1}{4}+\dfrac{3}{4}\times x=\dfrac{2}{3}\)
\(\dfrac{3}{4}\times x=\dfrac{2}{3}-\dfrac{1}{4}\)
\(\dfrac{3}{4}\times x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}\div\dfrac{3}{4}\)
\(x=\dfrac{5}{9}\)
\(\dfrac{1}{4}+\dfrac{3}{4}\times x=\dfrac{2}{3}\)
\(\dfrac{3}{4}\times x=\dfrac{2}{3}-\dfrac{1}{4}\)
\(\dfrac{3}{4}\times x=\dfrac{5}{12}\)
\(x=\dfrac{5}{12}:\dfrac{3}{4}\)
\(x=\dfrac{5}{12}\times\dfrac{4}{3}\)
\(x=\dfrac{5}{9}\)