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2020x2019-1/2018x2020+2019=8238329618
a) 5 : 3/4 - 4 4/5 : 3/4
= 5 . 4/3 - 24/5 . 4/3
= (5 - 24/5) . 4/3
= 1/5 × 4/3
= 4/15
b) -3/5 . 2/7 + (-3/7) . 3/5 + (-3/7)
= (-3/7) . (2/5 + 3/5 + 1)
= (-3/7) . 2
= -6/7
c) [(-4 2/7) . 7/11 + 7/11 . (5 1/3)] . 5 - 5 2/3
= (-30/7 . 7/11 + 7/11 . 16/3) . 5 - 17/3
= (-30/11 + 112/33) . 5 - 17/3
= 2/3 . 5 - 17/3
= 10/3 - 17/3
= -7/3
d) 5/39 . [(7 4/5) . (1 2/3) + (8 1/3) . (7 4/5)]
= 5/39 . (39/5 . 5/3 + 25/3 . 39/5)
= 5/39 . 39/5 . (5/3 + 25/3)
= 1 . 10
= 10
=
7(x-3)-5(3-x)=11x-5
<=>7(x-3)+5(x-3)=11x-5
<=>(7+5)(x-3)=11x-5
<=>12(x-3)=11x-5
<=>12x-36=11x-5
<=>12x-11x=-5+36
<=>x=31
\(\left(5^2\times2^3-7^3\times2\right)\div2\times6-7\div2^5\)
\(=\left(25\times8-343\times2\right)\div2\times6-7\div32\)
\(=\left(200-686\right)\div2\times6-7\div32\)
\(=-486\div2\times6-7\div32\)
\(=-1458-0,21875\)
\(=-1458,21875\)
\(3\times x^3-30:5=7\times3^7.\)
\(3\times x^3-30:5=15309\)
\(3\times x^3-6=15309\)
\(3\times x^3=15309+6\)
\(3\times x^3=15315\)
\(x^3=15315:3\)
\(x^3=5105\)
\(x=17,21862954=17,2=\frac{86}{5}\)
\(\frac{4}{5}\). X -X-\(\frac{3}{2}\). X+\(\frac{4}{3}\)
X.(\(\frac{4}{5}\)-1+\(\frac{4}{3}\))-3/2
X.17/15-3/2=-7/10
X.17/15 =4/5
X =12/17
k nhé
( 1 + 3 + 5 + 7 +......+ 2019 + 2021) x ( 13431 x 131 - 14541 x 121)
= ( 1 + 3 + 5 + 7 +......+ 2019 + 2021) x 0
= 0
Học tốt ạ;-;