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\(135-5\cdot\left(x+4\right)=35\)
\(5\cdot\left(x+4\right)=135-35\)
\(5\cdot\left(x+4\right)=100\)
\(x+4=100:5\)
\(x+4=20\)
\(x=20-4\)
\(x=16\)
b) \(25+3\cdot\left(x-8\right)=106\)
\(3\cdot\left(x-8\right)=106-25\)
\(3\cdot\left(x-8\right)=81\)
\(x-8=81:3\)
\(x-8=27\)
\(x=27+8\)
\(x=35\)
c) \(3^2\cdot\left(x+4\right)-5^2=5\cdot2^2\)
\(9\cdot\left(x+4\right)-25=5\cdot4\)
\(9\cdot\left(x+4\right)-25=20\)
\(9\cdot\left(x+4\right)=20+25\)
\(9\cdot\left(x+4\right)=45\)
\(x+4=45:9\)
\(x+4=5\)
\(x=5-4\)
\(x=1\)
Chúc bạn học tốt!!!!!!!!!!!!!!!!!!!!

Ta có: \(\left(2008-\dfrac{2}{135}+\dfrac{1}{50}\right)-\left(1-\dfrac{7}{135}+\dfrac{4}{150}\right)-\left(5+\dfrac{5}{135}+\dfrac{3}{50}\right)\)
= \(2008-\dfrac{2}{135}+\dfrac{1}{50}-1+\dfrac{7}{135}-\dfrac{4}{150}-5-\dfrac{5}{135}-\dfrac{3}{50}\)
= (2008-1-5) + \(\left(\dfrac{1}{50}-\dfrac{3}{50}\right)-\left(\dfrac{2}{135}-\dfrac{7}{135}\right)-\dfrac{4}{150}\)
=2002 \(-\dfrac{1}{25}\)+\(\dfrac{1}{27}\)\(-\dfrac{4}{150}\)
=2001,9(3)

a) \(4^{x^{ }}=64\)
\(\Rightarrow4^x=4^3\)
\(\Rightarrow x=3.\)
b) Vì \(35⋮x\)
\(\Rightarrow x\inƯ\left(35\right)=\left\{1;5;7;35\right\}\)
Vậy \(x\in\left\{1;5;7;35\right\}\)
c) \(135-\left(x-5\right)=105:3\)
\(\Leftrightarrow\)\(135-\left(x-5\right)=35\)
\(\Leftrightarrow x-5=135-35\)
\(\Leftrightarrow x-5=100\)
\(\Leftrightarrow x=100+5\)
\(\Leftrightarrow\) \(x=105.\)
d) Vì \(x⋮25\)
\(\Rightarrow x\in B\left(25\right)=\left\{0;25;50;75;100;...\right\}\)
Mà \(x< 100\)
\(\Rightarrow x\in\left\{0;25;50;75\right\}\)

135 - 5( x + 4 ) = 35
5( x + 4 ) = 135 - 35
5( x + 4 ) = 100
x + 4 = 100 : 5
x + 4 = 20
x = 20 - 4
x = 16
Vậy x = 16
\(135-5\left(x+4\right)=35\)
\(5\left(x+4\right)\) \(=135-35=100\)
\(x+4=100:5=20\)
\(x=20-4=16\)

\(\left(2018-\frac{2}{135}+\frac{1}{50}\right)-\left(1-\frac{7}{135}+\frac{4}{50}\right)-\left(5+\frac{5}{135}+\frac{3}{50}\right)\)
\(=2018-\frac{2}{135}+\frac{1}{50}-1+\frac{7}{135}-\frac{4}{50}-5-\frac{5}{135}-\frac{3}{50}\)
\(=2012-\frac{6}{50}\)

\(a,-13-\left(-15\right)=-13+15=2\)
\(b,43-\left(56-43\right)+\left(56-12\right)=43-13+44=30+44=74\)
\(c,4^4:2^8+\left[13-\left(-5\right)\right]\cdot\left(-3\right)=256:256+\left(13+5\right)\cdot\left(-3\right)\)\(=1+18\cdot\left(-3\right)=1+\left(-54\right)=-53\)
\(d,135\cdot\left(13-37\right)+37\cdot\left(135-13\right)=135\cdot\left(-24\right)+37\cdot122\)\(=-3240+4514=1274\)
a, -13-(-15)=-13+15=2
b, 43-(56-43)+(56-12)=43-13+44=30+44=74
c, 4^4:2^8+[13-(-5)].(-3)=256:256+(13+5).(-3)=1+18.(-3)=1+(-54)=-53
d, 135.(13-37)+37.(135-13)=135.(-24)+37.122=-3240+4514=1274

310.93
=310.(32)3
=310.36
=310+6
=316
Tìm x:
3x.5=135
=>3x=135:5=27
Mà: 33=27
=>3x=33
=>x=3
4+4=20 là sai
Vì: 4+4=8

a)\(\frac{x}{15}=\frac{2}{5}\)=> x=\(\frac{15.2}{5}=6\)
b) \(\frac{3}{x^7}hay\frac{3}{x.7}\)

x: 3/4 = (-2)^3
x: 3/4 = -8
x= -8 * 3/4
x= -6
-------------------------------------------
135 - (7-4x) =0
7-4x = 135-0
7- 4x =135
4x = 7-135
4x = -128
x= -128 : 4
x= -32
----------------------------------
(5,6 * 2x) * 10/7 =10/7
5,6 * 2x = 10/7 : 10/7
5,6 * 2x = 1
2x = 1 : 5,6
2x = 5/28
x= 5/28 : 2
x=5/56
--------------------------------
(x+1) + (x+2) + (x+3) +...+(x+100) = 5750
100x + (1+2+3+...+100) = 5750
100x + [(1 + 99) + (2+98)...+(49 + 51) + 50 + 100] = 5750
100x + (100 * 50 + 50) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x=700:100
x=7
135 – 5(x + 4) = 3
<=>5(x+4)=135-3
<=>5(x+4)=132
<=>x+4=132:5
<=>x+4=26,4
<=>x=26,4-4
<=>x=122,4
Vậy x=22,4
5(x+4) =132
x+4 =132/5
x=112/5